How to get value from text string in PHP - php

Question

I have the following string:
"{\"ttl\": null\054 \"card_id\": \"np\"}.DPSXmw.VApKpbKiEnEoRgwWblgt-nuewFg"
I can tidy this using strip slashes so it becomes:
"{"ttl": null, "card_id": "np"}.DPSXmw.VApKpbKiEnEoRgwWblgt-nuewFg"
I need to get the value where np is however I am unsure how to do this. Is it best to remove the trailing text and address it as JSON or am I best using another method?
the string in question does contain the wrapping " "
Current Code:
echo stripslashes($VCIDcookie);
$string = stripslashes($VCIDcookie);
output of $string: "{"ttl": null54 "card_id": "np"}.DPSXmw.VApKpbKiEnEoRgwWblgt-nuewFg"
$string = explode('}', $string);
$json = json_decode($string[0] .'}');
echo $json->card_id;
Updated Code - I have used trim() to remove the wrapping quotation marks so the string doesn't have them but I am still not getting the np output:
$string = trim($VCIDcookie,'"');
$string = stripslashes($string);
echo $string;
$string = explode('}', $string);
$json = json_decode($string[0] .'}');
echo $json->card_id;

Answer 1

Try this :
$string = '{"ttl": null, "card_id": "np"}.DPSXmw.VApKpbKiEnEoRgwWblgt-nuewFg';
$string = explode('.', $string);
$json = json_decode($string[0]);
echo $json->card_id;
Care : I suppose ttl or card_id don't have "." in their values.
Or, to avoid problems with "." :
$string = '{"ttl": null, "card_id": "np"}.DPSXmw.VApKpbKiEnEoRgwWblgt-nuewFg';
$string = explode('}', $string);
$json = json_decode($string[0] .'}');
echo $json->card_id;