I set up my localhost, I have all my relevant files in place. I run the php where I run the sql query, it returns NULL values. But it should not. I visit to the directory of the link via browser.
Can someone point me in the return direction, why it is returning NULL? I ran the SQL query, and works fine on my phpmyAdmin
<?php
header('Content-Type: application/json');
define('DB_HOST', '127.0.0.1');
define('DB_USERNAME', 'myusername');
define('DB_PASSWORD', 'Ihavenopassword');
define('DB_NAME', 'mytablename');
$mysqli = new mysqli(DB_HOST, DB_USERNAME, DB_PASSWORD, DB_NAME);
//$conn = mysqli_connect($db_host, $db_user, $db_pass, $db_name);
if(!$mysqli){
die("Connection failed: " . $mysqli->error);
}
//query to get data from the table
$query = sprintf("SELECT playerid, score FROM score ORDER BY playerid");
//execute query
$result = $mysqli->query($query);
//loop through the returned data
$data = array();
foreach ($result as $row) {
$data[] = $row;
}
//free memory associated with result
$result->close();
//close connection
$mysqli->close();
//now print the data
print json_encode($data);
$result is not what you expect. You need to fetch every item, with fetch_assoc for example:
//loop through the returned data
$data = array();
while ($row = $result->fetch_assoc()) {
$data[] = $row;
}
Related
I'm trying to convert timestamp from my mysql table in to normal time.
I've tried looking for information on the internet but there is only solutions for timestamps that you entered by hand
<?php
//setting header to
header('Content-Type: application/json');
//database
define('DB_HOST', 'localhost');
define('DB_USERNAME', 'root');
define('DB_PASSWORD', '');
define('DB_NAME', 'bitcoin');
//get connection
$mysqli = new mysqli(DB_HOST, DB_USERNAME, DB_PASSWORD, DB_NAME);
if(!$mysqli){
die("Connection failed: " . $mysqli->error);
}
//query to get data from the table
$query = sprintf("SELECT Kaina, Laiko_Kodas FROM localbtc LIMIT 200");
//execute query
$result = $mysqli->query($query);
//loop through the returned data
$data = array();
foreach ($result as $row) {
$data[] = $row /*("SELECT date_format(Laiko_Kodas) FROM localbtc")*/;
}
//free memory associated with result
$result->close();
//close connection
$mysqli->close();
//now print the data
print json_encode($data);
while($row = $result->fetch_assoc()) {
$data = array();
$data2[]= $row['Kaina'];
$datetime=$row['Laiko_Kodas'];
$data2[] = date('M j Y g:i A', strtotime($datetime));
$dtata[]=$data;
}
Try the following code:
<?php
//setting header to
header('Content-Type: application/json');
//database
define('DB_HOST', 'localhost');
define('DB_USERNAME', 'root');
define('DB_PASSWORD', '');
define('DB_NAME', 'bitcoin');
//get connection
$mysqli = new mysqli(DB_HOST, DB_USERNAME, DB_PASSWORD, DB_NAME);
if(!$mysqli){
die("Connection failed: " . $mysqli->error);
}
//query to get data from the table
$query = "SELECT Kaina, Laiko_Kodas FROM localbtc LIMIT 200";
//execute query
$result = $mysqli->query($query);
//loop through the returned data
$data = array();
foreach ($result as $row) {
$row['Laiko_Kodas'] = date('H:i:s', strtotime($row['Laiko_Kodas']));
$data[] = $row;
}
//free memory associated with result
$result->close();
//close connection
$mysqli->close();
//now print the data
print json_encode($data);
I am using the chart.js library to create graphs. I can successfully create graphs using individual ID's from users. However, I would like to rewrite my code so that I could extract the user's ID from the URL and generate graph based on that specific ID.
Here is the code i'm using now to generate the points in the graph:
<?php
//setting header to json
header('Content-Type: application/json');
//database
define('DB_HOST', 'localhost');
define('DB_USERNAME', 'root');
define('DB_PASSWORD', '');
define('DB_NAME', 'test');
//get connection
$mysqli = new mysqli(DB_HOST, DB_USERNAME, DB_PASSWORD, DB_NAME);
if(!$mysqli){
die("Connection failed: " . $mysqli->error);
}
//query to get data from the table
$query = sprintf("SELECT treatment_log.bdi, treatment_log.date FROM treatment_log WHERE treatment_fk = 21 ORDER BY created_at");
//execute query
$result = $mysqli->query($query);
//loop through the returned data
$data = array();
foreach ($result as $row) {
$data[] = $row;
}
//free memory associated with result
$result->close();
//close connection
$mysqli->close();
//now print the data
print json_encode($data);
Here is what the page outputs:
[{"bdi":"4","date":"2018-07-11"},{"bdi":"1","date":"2018-07-21"},{"bdi":"5","date":"2018-07-21"},{"bdi":"34","date":"2018-07-21"},{"bdi":"34","date":"2018-07-21"},{"bdi":"3","date":"2018-07-22"},{"bdi":"2","date":"2018-07-23"},{"bdi":"12","date":"2018-07-23"},{"bdi":"3","date":"2018-07-24"},{"bdi":"2","date":"2018-07-25"},{"bdi":"12","date":"2018-07-30"},{"bdi":"3","date":"2018-07-30"},{"bdi":"4","date":"2018-07-30"},{"bdi":"11","date":"2018-07-30"}]
In this case "21" is specific user. I am familiar with prepared statements, and have attempted rewrite this as a prepared statement.
Here is my attempt:
<?php
//setting header to json
header('Content-Type: application/json');
//database
define('DB_HOST', 'localhost');
define('DB_USERNAME', 'root');
define('DB_PASSWORD', '');
define('DB_NAME', 'test');
//get connection
$mysqli = new mysqli(DB_HOST, DB_USERNAME, DB_PASSWORD, DB_NAME);
if(!$mysqli){
die("Connection failed: " . $mysqli->error);
}
$cid = htmlentities ($_GET['customer_id']);
//query to get data from the table
$sql = sprintf("SELECT treatment_log.bdi, treatment_log.date FROM treatment_log WHERE treatment_fk = ? ORDER BY created_at");
$stmt = mysqli_stmt_init($conn);
mysqli_stmt_prepare($stmt, $sql);
mysqli_stmt_bind_param($stmt, "i", $cid);
mysqli_stmt_execute($stmt);
$result = mysqli_stmt_get_result($stmt);
//execute query
$results = $mysqli->query($sql);
//loop through the returned data
$data = array();
foreach ($results as $row) {
$data[] = $row;
}
//free memory associated with result
$results->close();
//close connection
$mysqli->close();
//now print the data
print json_encode($data);
Obviously my code doesn't seem to work. Help would be greatly appreciated.
Change this:
$result = mysqli_stmt_get_result($stmt);
//execute query
$results = $mysqli->query($sql);
//loop through the returned data
$data = array();
foreach ($results as $row) {
$data[] = $row;
}
into this:
$data = array();
mysqli_stmt_bind_result($stmt, $bdi, $date);
while(mysqli_stmt_fetch($stmt)) {
$data[]['bdi'] = $dbi;
$data[]['date'] = $date;
}
I have a hard time trying to list all the tables in my database.
I tried
<?php
//Configuration
$dbname = 'local';
$user = 'root';
$host = '127.0.0.1';
$pass = '';
$date = date('Y-m-d');
$export_type = 'mysql'; // option : mysql | psql
$file_name = $date.'-portal';
$file_path = $file_name;
// Create connection
$conn = mysqli_connect($host, $user, $pass);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
$sql = "SHOW TABLES FROM $dbname";
$res = mysqli_query($conn, $sql);
if($res != false){
echo "Connected successfully";
$FILE = fopen("output.csv", "w");
$table = array();
while($row = mysql_fetch_array($res)){
$table[] = $row['0'];
}
foreach($tables as $table) {
$columns = array();
$res = mysqli_query($conn, "SHOW COLUMNS FROM $table");
while($row = mysql_fetch_array($res, MYSQL_NUM)) {
$columns[] = "$row[0]";
}
fwrite($FILE, implode(",", $columns)); fwrite("\n");
$resTable = mysqli_query($conn, "SELECT * FROM $table");
while($row = mysql_fetch_array($resTable, MYSQL_NUM)) {
fwrite($FILE, implode(",", $row)); fwrite("\n");
}
}
}else{
die(mysql_error());
}
?>
Result
if($res != false){
//.. everything in here never get executed
}
`$res` kept returning `false`.
What did I do wrong that could have lead to this ?
You can always execute the query:
Show tables;
After you selected database.
By the way you also can execute:
Show databases;
To list all of the databases your current user has permission to view.
Use db in your connection
mysqli_connect($host, $user, $pass, $dbname);
And use query like this
$sql = "SHOW TABLES";
You need to pass through your database in the connection script.
Like so:
$conn = mysqli_connect($host, $username, $pass, $dbname);
Then, when you want to pull rows from a table, you do it like this:
mysqli_query($conn, "SELECT rows FROM table");
One of the reasons this wasn't working for you was because you weren't passing through your database name through the connection. Also, rather than doing the above query, you selected a table from a database; rather than a row from a table.
Also, I noticed that you're using the mysql_* error output on the last line.
Here is a working version
Changes:
Added $dbname to mysqli_connect function
Added the backtick ` char between the table names, to avoid errors with reserved keyword from MySQL
Changed mysql_ functions to mysqli_
Close the file
Close the connection
Here is the code
NOTE: sorry I don't why, but when I pasted the code in the answer, all de code identation was messed up, even trying to indent it properly, I wasted like 10 minutes :(
I am trying to query a MySQL database with PHP and return the results as JSON. I'm new to PHP and web development so I'm not sure what I'm doing wrong. I've set up the database using MAMP. My parameters are being printed but I'm not getting the JSON. I've gotten this far with the help of a tutorial.
EDIT: I just went into phpMyAdmin to make sure it was working and when I click on Server:localhost:8889, a window pops up that says Error in processing request. Error code 404.
I'm thinking this is the problem, I'm just not sure why it isn't working. I may reinstall MAMP.
<?php
$user = 'root';
$password = 'root';
$db = 'TestDB';
$host = '127.0.0.1';
$port = '8889';
$first_name = filter_input(INPUT_GET, 'first_name');
$last_name = filter_input(INPUT_GET, 'last_name');
$membership_number = filter_input(INPUT_GET, 'membership_number');
echo $first_name;
echo $last_name;
echo $membership_number;
// Create connection
// $con = mysqli_connect("localhost", "root", "root", "TestDB");
// $con = mysqli_connect("localhost", "root", "root", "TestDB", "8889", $socket);
$link = mysqli_init();
$con = mysqli_real_connect($link, $host, $user, $password, $db, $port);
// Check connection
if(mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "SELECT * FROM NAME WHERE FIRST_NAME = \'$first_name\' and LAST_NAME = \'$last_name\' and MEMBERSHIP_NUMBER = \'$membership_number\'";
$result = mysqli_query($con, $sql);
if(!$result) {
die('Query failed: ' . mysqli_error());
}
// Check for results
// if ($result = mysqli_query($con, $sql)) {
if($result) {
// If there are results, create results array and a temporary one to hold the data
$resultArray = array();
$tempArray = array();
// Loop through each row in the result set
// while($row = $result->fetch_object()) {
while($row = mysqli_fetch_object($result)) {
// Add each row to the results array
$tempArray = $row;
array_push($resultArray, $tempArray);
}
echo $tempArray;
echo $resultArray;
echo $result;
echo json_encode($resultArray);
}
// Close connections
mysqli_close($con);
?>
You need to change you $sql variable to remove the escapes on the single quotes. They register as part of the string because you are using double-quotes to wrap it. Basically, you're telling the database to run the query "SELECT * FROM NAME WHERE FIRST_NAME = \'John\' and LAST_NAME = \'Smith\' and MEMBERSHIP_NUMBER = \'VRX78435\'". This will error if you run it directly because the escape characters are not escaping.
$sql = "SELECT * FROM NAME WHERE FIRST_NAME = '$first_name' and LAST_NAME = '$last_name' and MEMBERSHIP_NUMBER = '$membership_number'";
That should fix it for you.
There may also be an issue with your connection to the server. mysqli_query() uses the results of mysqli_connect() to run the query. mysqli_real_connect() only returns a boolean value, so it is invalid for this particular use (at least it failed to work on my server).
This would be a simple matter of replacing the $con and then you can drop the $link variable.
$con = mysqli_connect($host, $user, $password, $db, $port);
These changes, and assuming the $first_name, $last_name, and $membership_number are all valid, allowed your script to run for me, so I hope this helps.
Seems you are using procedural style coding
Instead of
while($row = $result->fetch_object()) {
You need mysqli_fetch_object in procedural style
while($row = mysqli_fetch_object($result)) {
I am trying to query the table bets but it seems it is not returning anything, even though there is data in it which matches the criteria
I'm not sure if I'm missing something completely obvious or not
Here is my code,
<?php
//Begin session
session_start();
//Get pool var
if(isset($_GET['pool'])) {
$_SESSION['pool'] = $_GET['pool'];
$pool = $_SESSION['pool'];
}
//Include database connection details
require_once('config.php');
//Array to store validation errors
$errmsg_arr = array();
//Validation error flag
$errflag = false;
//Connect to mysql server
$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
if(!$link) {
die('Failed to connect to server: ' . mysql_error());
}
//Assign memberid
$memberid = $_SESSION['SESS_MEMBER_ID'];
echo "POOLNAME $pool<br>";
echo "MEMBERID $memberid<br>";
//Select database
$db = mysql_select_db(DB_DATABASE);
if(!$db) {
die("Unable to select database");
}
$result = mysql_query($link,"SELECT * FROM bets WHERE member_id='$memberid'");
echo "RESULT $result";
echo "SQL executed<br>";
echo "Executing loop<br>";
while($row = mysql_fetch_array($result))
{
echo "test<br>";
$matchid = $row['match_id'];
$betAmount = $row['bet_amount'];
$teamname = $row['team_name'];
echo "$betAmount credits placed on team: $teamname for match: $matchid";
}
?>
You are mixing mysql and mysqli commands. You need to use one or the other, preferably mysqli, if possible.
$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
should be:
$link = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_DATABASE);
And in mysqli_fetch_array() the first parameter is the mysqli result object (which you have correctly) and it requires a second parameter for the array it will return., MYSQLI_BOTH for example.
MYSQLI_BOTH will allow you to reference the array by the number indices or the column name
MYSQLI_ASSOC will allow reference from column names but not number indices and MYSQLI_NUM allows number indices.
so while ($row = mysqli_fetch_array($result, MYSQLI_BOTH)) would be what you want.
Also, do refer to the comment from Andy Lester about SQL injection, it is very important to sanitize input.