Please accept my apologies for a lack of attempted code.
I can't get my head around this - or even figure out if it's feasible!
I have a table filled with 'date slots', these can be booked by an individual.
The time slots table looks like this:
ID | Price | Available_from | Available_ to
------------------------------------
1 | 20.00 | 2017-10-01 | 2018-01-01
2 | 20.00 | 2017-11-01 | 2017-12-07
3 | 20.00 | 2017-10-31 | 2018-01-31
4 | 20.00 | 2017-10-22 | 2017-11-21
------------------------------------
In these rows, there is a common date range where all four results are available, 2017-11-01 > 2017-11-21
I would like to query my database to see if 1) there is a common range for every result and 2) if there is, get the date range.
Desperate for help!
Thank you
I think this would work :
SELECT MAX(Available_from) as MatchFrom,
MIN(Available_to) as MatchTo
FROM Temporary.test
WHERE
(SELECT MAX(Available_from) FROM Temporary.test)
<=(SELECT MIN(Available_to) FROM Temporary.test)
It will return NULL, if there is no overlapping range.
Related
I don't know if this is too complicated for a SELECT alone or if it should be done in PHP.
I have two tables: EventDetail and EventPersonnel. I need to return the events for a specific date range and user.
EventDetail
EventId | EventName | Start | End
------: | :-------- | :--------- | :---------
1 | Event A | 2022-03-09 | 2022-03-11
2 | Event B | 2022-03-09 | 2022-03-15
3 | Event C | 2022-03-10 | 2022-03-21
EventPersonnel
EventID | UserID
------: | -----:
1 | 1
1 | 3
2 | 2
3 | 1
3 | 2
3 | 3
Expected Results:
If today were March 10, 2022 and current userId = 1, the expected results are:
EventId | EventName | StartDate | EndDate
------: | :-------- | :--------- | :---------
1 | Event A | 2022-03-09 | 2022-03-11
3 | Event C | 2022-03-10 | 2022-03-21
db<>fiddle here
I solved the first part returning all of the rows in where the current date falls between the start date and end date in my eventDetails table as below:
$currentEvent = new WA_MySQLi_RS("currentEvent",$stapleton,1);
$currentEvent->setQuery("SELECT * FROM eventDetails WHERE CURDATE() BETWEEN start AND end");
$currentEvent->execute();
I can also return all of the records of the logged in user via the session:
$userEvent = new WA_MySQLi_RS("userEvent",$stapleton,0);
$userEvent->setQuery("SELECT eventID FROM eventPersonnel WHERE userID = ?");
$userEvent->bindParam("i", "".($_SESSION['UserID']) ."", "-1"); //colname
$userEvent->execute();
Both of these work as i need them. However there is one more piece I need and that is to combine them so that I am only returning the events for the logged in user. I have tried several subqueries and cannot come up with anything that is not a illegal SQL error.
I don't know if I am explaining it well enough. I don't believe this would be hard for someone knowing what they are doing. But I don't know where to start.
I am very new to Php and can echo the queries and can create repeat regions to show my results but I do not know where to begin to write proper code. I'd appreciate it if someone could show me the proper code AND if they could please tell me what I need to learn so I can understand this myself. There's SO MUCH out there that for a noob like myself I have no clue even where to start. Thanks in advance!
Hello I am facing hard time trying to realized this task. The problem is that I am not sure in which way this have to be proceeded and couldn't find tutorials or information about realizing this type of task.
The question is I have 2 tables and one connecting table between the two of them. With regular query usually what is displayed is the table header which is known value and them then data. In My case I have to display the table horizontally and vertically since the header value is unknown value.
Here is example of the DB
Clients:
+--------+------ +
| ID | client|
+--------+------ +
| 1 | Sony |
| 2 | Dell |
+--------+------ +
Users:
+--------+---------+------------+
| ID | name | department |
+--------+--------+-------------+
| 1 | John | 1|
| 2 | Dave | 2|
| 3 | Michael| 1|
| 4 | Rich | 3|
+--------+--------+-------------+
Time:
+--------+------+---------------------+------------+
| ID | user | clientid | time | date |
+--------+------+---------------------+------------+
| 1 | 1 | 1 | 01:00:00 | 2017-01-02 |
| 2 | 2 | 2 | 02:00:00 | 2017-01-02 |
| 3 | 1 | 2 | 04:00:00 | 2017-02-02 | -> Result Not Selected since date is different
| 4 | 4 | 1 | 02:00:00 | 2017-01-02 |
| 5 | 1 | 1 | 02:00:00 | 2017-01-02 |
+--------+------+---------------------+------------+
Result Table
+------------+--------+-----------+---------+----------+
| Client | John | Michael | Rich | Dave |
+------------+--------+-----------+---------+----------+
| Sony |3:00:00 | 0 | 2:00:00 | 0 |
+------------+--------+-----------+---------+----------+
| Dell | 0 | 0 | 0 | 2:00:00 |
+------------+--------+-----------+---------+----------+
First table Clients Contains information about clients.
Second table Users Contains information about users
Third Table Time contains rows of time for each users dedicated to different clients from the clients table.
So my goal is to make a SQL Query which will show the Result table. In other words it will select sum of hours which every user have completed for certain client. The number of clients and users is unknown. So first thing that have to be done is Select all users, no matter if they have hours completed or not. After that have to select each client and the sum of hours for each client which was realized for individual user.
The problem is I don't know how to approach this situation. Do I have first to make one query slecting all users then foreach them in the table header and then realize second query selecting the hours and foreaching the body conent, or this can be made with single query which will render the whole table.
The filters for select command are:
WHERE MONTH(`date`) = '$month'
AND YEAR(`date`) ='$year'
AND u.department = '$department'
Selecting single row for tume SUM is:
(SELECT SUM( TIME_TO_SEC( `time` ) ) FROM Time tm
WHERE tm.clientid = c.id AND MONTH(`date`) = '$month' AND YEAR(`date`) ='$year'
This is the query to select the times for a user , here by my logic this might be transformed with GROUP BY c.id (client id), and the problem is that it have to contains another WHERE clause which will specify the USER which is unknown. If the users was known value was for example 5, there is no problem to make 5 subsequent for each user WHERE u.id = 1, 2, 3 etc.
So here are the 2 major problems how to display in same query The users header and them select the sum of hours for each client corresponding the user.
Check out the result table hope to make the things clear.
Any suggestion or answer which can come to resolve this situation will be very helpful.
Thank you!
I am trying to select data, when inserting the data it has an auto insert of the date when submitting. So when data is inserted it inserts the current date.
However, in my table I have week beginnings, so I am trying to select the data inside of that week:
mysql> select * from week;
+---------+------+------------+
| week_id | week | date |
+---------+------+------------+
| 1 | 1 | 2014-12-29 |
| 2 | 2 | 2015-01-05 |
| 3 | 3 | 2015-01-12 |
| 4 | 4 | 2015-01-19 |
| 5 | 5 | 2015-01-26 |
| 6 | 6 | 2015-02-02 |
| 7 | 7 | 2015-02-09 |
| 8 | 8 | 2015-02-16 |
| 9 | 9 | 2015-02-23 |
| 10 | 10 | 2015-03-02 |
| 11 | 11 | 2015-03-09 |
| 12 | 12 | 2015-03-16 |
| 13 | 13 | 2015-03-23 |
| 14 | 14 | 2015-03-30 |
| 15 | 15 | 2015-04-06 |
| 16 | 16 | 2015-04-13 |
| 17 | 17 | 2015-04-20 |
e.g.
select * from table where date='2015-04-06';
However the data will not be selected and presented because the inserted date was 2015-04-10. The only way to retrieve that data is by doing this:
select * from table where date='2015-04-10'; < when the data was inserted
So my question is, is it possible to select that data from that week beginning?
So if I select data from 2015-04-06 it should show data from the range of 2015-04-06 to 2015-04-12, is that possible?
Hopefully I have explained correctly, been a bit tricky to explain let alone try to implement. I can add any more info if needed.
NOTE: I am trying to use this inside of PHP so where the date is I would just use a variable, just thought I would say.
As the week will always end 6 days from the beginning you can use the between operator and the date_add function like this:
(for your specific example):
select *
from table
where date between '2015-04-06' and date_add('2015-04-06', interval 6 day)
And using a php variable:
select *
from table
where date between '$name_of_dt_var' and date_add('$name_of_dt_var', interval 6 day)
You could also compare the week of the date the data was entered with the weeks in the week table using WEEK() function.
Assuming that week is the same value as week(), the:
select t.*
from table t
where week = week('2015-04-10');
Even if the numbers do not match, then presumably you have some base date (such as 2015-01-01 and simple arithmetic would accomplish something very similar).
I have found that the most robust way to do this sort of week processing is to truncate each date in the table (in your example 2015-04-10) to the preceding Monday at midnight. That way you can compute the week of each item by assigning it to the first day of that week.
This little formula returns the preceding Monday given any DATE or DATETIME value.
FROM_DAYS(TO_DAYS(datestamp) -MOD(TO_DAYS(datestamp) -2, 7))
For example,
set #datestamp := '2015-04-10'
SELECT FROM_DAYS(TO_DAYS(#datestamp) -MOD(TO_DAYS(#datestamp) -2, 7))
yields the value 2015-04-06.
So, if you have a table called sale you can add up sales by week like this:
SELECT SUM(amount) weekly_amount,
FROM_DAYS(TO_DAYS(datestamp) -MOD(TO_DAYS(datestamp) -2, 7)) week_beginning
FROM sale
GROUP BY FROM_DAYS(TO_DAYS(datestamp) -MOD(TO_DAYS(datestamp) -2, 7))
This is a very convenient way to handle things, because it's robust over end-of-year transitions. The WEEK() function doesn't work quite as well.
If your business rules say that your weeks begin on Sunday rather than Monday, use -1 rather than -2, as follows.
FROM_DAYS(TO_DAYS(datestamp) -MOD(TO_DAYS(datestamp) -1, 7))
I'm looking for something like the person here was lookin for, only I'd like to use MySQL. The table below is something you'd find in my database (simplified).
+------+------+------+------+
| id | name | first| last |
+------+------+------+------+
| 1 | John | 1020 | 0814 |
| 2 | Ram | 0827 | 0420 |
| 3 | Jack | 0506 | 0120 |
| 4 | Jill | 0405 | 0220 |
| 5 | Zara | 1201 | 1219 |
+------+------+------+------+
First of all the entry has to be random, not id 4 and I only want 1 entry. I worked that out: SELECT * FROM test WHERE id <> 4 ORDER BY rand() LIMIT 1.
In this table the columns 'first' and 'last' are dates formatted as mmdd (both integers). So John is available for most of the year; from October 20th to August 14th. Zara on the other hand is only available for a small period of time; December 1st till December 19th.
My question: how do I change my query to only select the available people? I can't use 'between' since, in John's case, there's nothing between 1020 and 0814.
I just can't figure it out, there's must be other people that have a similar problem... Does anyone have a solution?
Kind regards
You need to distinguish two cases.
When first < last, the dates are in the same year. You can then use between to match dates.
When first > last, it means last is in the next year. In this case, the dates that match are date >= first OR date <= last.
So your WHERE clause should be:
WHERE IF(first < last, #date BETWEEN first AND last,
#date >= first OR date <= last)
So, in my mysql database I am storing days and hours open in one field, called days, the data is stored in the following format:
[Monday:9:17[Tuesday:9:17[Wednesday:10:18[
As you may've guessed, it goes: [Day:From:Till and brackets are just seperatars for PHP to distinguish how many days are there.
I've been thinking all day what query would be but I could not figure out, so basically I need to get current date and time using PHP:
date(l); // Day in full text representation.
date(G); // current hour in 24 hour format.
So basically I need a query which in simple english would sound like:
SELECT all FROM businessdetails WHERE column date CONTAINS [current date] and :#:# numbers to be less than current hour and greater than current hour.
Help? My brain is melting by now.
So honestly the best thing to do is to normalize your database so you can do better queries. BUT I love to see if I can solve impossible situations so here is what you can do!
This will check all the business that are open on Tuesday at 11am
SELECT * FROM `businessdetails` WHERE `date` REGEXP 'Tuesday:(0|1|2|3|4|5|6|7|8|9|10|11):(11|12|13|14|15|16|17|18|19|20|21|22|23)[^0-9]'
(Funny thing I've found I can't seem to escape the [ in the column so I had to make sure the Regex doesn't have any extra digits at the end or it may erroneously match 2 and 20 or something.)
Here's how you can generate that REGEXP string via PHP:
<?php
$regexp = date('l') . ':(' . join('|', range(0, date('G'))) . '):(' . join('|', range(date('G'), 23)) . ')[^0-9]';
DISCLAIMER I don't actually recommend doing this but I thought it was clever and wanted to share since it directly answers your question.
EDIT
Just noticed you changed your answer. below may not apply anymore, but I'll leave it for future reference...
I would suggest having a separate child table for this.
STORES
auto increment ID
|
| the store name the store description etc..
| / / /
.--------------------------------------------------.
| id | name | description | etc |
|--------------------------------------------------|
| 1 | mary's kitchen | a fancy restaurant | etc |
| 2 | willow creek inn | we serve breakfast | etc |
'--------------------------------------------------'
STORE_HOURS
auto increment ID
| The STORES.id
| / the day (0-SUN, 6-SAT)
| _________/ / the 24h time OPEN (HH:MM:SS *TIME*)
| / _________/ ____/ the 24h time CLOSE (HH:MM:SS *TIME*)
| / / / /
.----------------------------------------------.
| id | store_id | day | time_open | time_close |
| 1 | 1 | 1 | 08:30:00 | 20:00:00 |
| 2 | 1 | 2 | 08:30:00 | 20:00:00 |
| 3 | 1 | 3 | 10:30:00 | 20:00:00 |
| 4 | 1 | 4 | 11:00:00 | 20:00:00 |
| 5 | 1 | 5 | 08:30:00 | 22:30:00 |
'----------------------------------------------'
Now, depending on what you want to display, you could query the table:
SELECT
stores.name AS store_name,
stores.description AS store_description,
store_hours.day AS store_hours_day,
TIME(store_hours.time_open) AS store_open,
TIME(store_hours.time_close) AS store_close
FROM
stores
JOIN
store_hours
ON
store_hours.store_id = stores.id
Result: http://sqlfiddle.com/#!2/e6872/8/0
With this table structure and relationship, you can then create granular queries without too much effort.
So this might be a hell of a response, but here is one way to do it... (Although I'm sure there must be more significantly better ways:
$day = date(l); // Day in full text representation.
$time = date(G); // current hour in 24 hour format.
$sql = "SELECT businessID FROM (SELECT SUBSTRING_INDEX(t_time,':',1) as start, SUBSTRING_INDEX(LEFT(t_time,POSITION('[' IN t_time) - 1), ':',-1) as end,businessID from (SELECT SUBSTRING_INDEX(SUBSTR(`column_date`,POSITION('$day' IN `column_date`) + LENGTH('" . $day . "') + 1),':',2) as t_time, businessID from `businessdetails ` where `column_date` like '%$day%') as t_table_1) as t_table_2 where start >= $time && end <= $time";
Hopefully that works =)
PS If you need help there are all these string functions you could use:
http://dev.mysql.com/doc/refman/5.0/en/string-functions.html