How to handle get_headers() function if URL doesn't exist - php

Question

While usign the function get_headers() for example, If i wrote
get_headers("www.websitedoesntexist.com");
i get the following error
Warning: get_headers(): php_network_getaddresses: getaddrinfo failed:
No such host is known Warning:
get_headers(www.websitedoesntexist.com): failed to open stream:
php_network_getaddresses: getaddrinfo failed: No such host is known
I want to know how to handle these problems, Something like
if (isset(get_headers("www.websitedoesntexist.com"))) {
echo "URL Exists";
}

Answer 1

Suppress errors on the get_headers() function. Assign get_headers to a variable. Then check the Boolean value of that variable.
$file_headers = #get_headers("www.websitedoesntexist.com");
if(!$file_headers) {
$exists = false;
}
else {
$exists = true;
}
Edit:
Based on the comments, for a better, long-term solution using curl see https://stackoverflow.com/a/36743670/4374801

Answer 2

From the PHP manual :
Returns an indexed or associative array with the headers, or FALSE on failure.
Which means you can test against FALSE.
Read more : http://php.net/manual/en/function.get-headers.php
Edit
If you want just to check if the URL exists or not, instead of supressing the errors I suggest you use curl, a simple function like this can do the job :
function url_exists($url) {
if (!$fp = curl_init($url)) {
return false;
}
return true;
}

Answer 3

if you want to check the url exist or not in php, simply code this.testing purpose
$array = get_headers('url');
$string = $array[0];
if (strpos($string, "200")) {
echo "thats cool dude";
} else {
echo "Bad request";
}