I created an input text, where I write something that I want to search in an array.
I already use stristr() and stripos() but whit this I get only the same words, example:
<?php
$value[0]= 'animals';
//other array values
$arrayResp = [];
foreach($valuefounded as $value)
{
if(stristr($value, "animals") !== FALSE)
{
$arrayResp[]= $value;
}
}
how can I get the same result, if I type grammatical mistake like "animls"
There's no simple function to achieve this, but you could build something like with soundex, levenshtein or similar functions. To do so, you have to split the input text into words and do the calculation for each word.
But you should keep in mind, this works only for complete words.
function search_in_string($search, $text, $max = 2) {
$words = explode(' ', $text);
foreach ($words as $word) {
if (levenshtein($word, $search) <= $max) {
return strpos($text, $word);
}
}
return false;
}
Related
I'm facing an issue with a function that gets a string between two other strings.
function string_between($str, $starting_word, $ending_word) {
$subtring_start = strpos($str, $starting_word);
$subtring_start += strlen($starting_word);
foreach ($ending_word as $a){
$size = strpos($str, $a, $subtring_start) - $subtring_start;
}
return substr($str, $subtring_start, $size);
}
The issue is that the function searches for the first ending_word in the array.
An example will be easier to understand:
$array_a = ['the', 'amen']; // Starting strings
$array_b = [',', '.']; // Ending strings
$str = "Hello, the world. Then, it is over.";
Expected result:
"the world."
Current result:
"the world. Then,"
The function will think that the ending_word is "," because it is the first element met in the array_b. However, the text encounters first the '.' after the "the" starting word.
How can I make sure the function goes through the text and stops at the first element in the $str present in the array_b, whatever the position in the array?
Any idea?
Basically, you need to break outside of your foreach loop when $size > 0
That way it stops looping through your array when it finds the 1st occurrence. Here is the more complete code with other fixes:
function stringBetween($string, $startingWords, $endingWords) {
foreach ($startingWords as $startingWord) {
$subtringStart = strpos($string, $startingWord);
if ($subtringStart > 0) {
foreach ($endingWords as $endingWord){
$size = strpos($string, $endingWord, $subtringStart) - $subtringStart + strlen($endingWord);
if ($size > 0) {
break;
}
}
if ($size > 0) {
return substr($string, $subtringStart, $size);
}
}
}
return null;
}
$startArr = array('the', 'amen'); // Starting strings
$endArr = array('.', ','); // Ending strings
$str = "Hello, the world. Then, it is over.";
echo stringBetween($str, $startArr, $endArr); // the world.
This type of problems are best solved by PCRE regexes, only couple of lines needed in function :
function string_between($str, $starts, $ends) {
preg_match("/(?:{$starts}).*?(?:{$ends})/mi", $str, $m);
return $m[0];
}
Then calling like this :
echo string_between("Hello, the world. Then, it is over.", 'the|amen', ',|\.');
Produces : the world.
The trick,- search to the nearest matching ending symbol is done with regex non-greedy seach, indicated by question symbol in pattern .*?. You can even extend this function to accept arrays as starting/ending symbols, just that case modify function (possibly with implode('|',$arr)) for concatenating symbols into regex grouping formula.
Edited version
This works now. Iterate over your teststrings from first array looking for position of occurance from teststring. If found one then search for the second teststring at startposition from end of first string.
To get the shortest hit I store the position from the second and take the minimum.
You can try it at http://sandbox.onlinephpfunctions.com/code/0f1e5c97da62b4daaf0e49f52271fe288d1cacbb
$array_a =array('the','amen');
$array_b =array(',','.', '#');
$str = "Hello, the world. Then, it is over.";
function earchString($str, $array_a, $array_b) {
forEach($array_a as $test) {
$pos = strpos($str, $test);
if ($pos===false) continue;
$found = [];
forEach($array_b as $test2) {
$posStart = $pos+strlen($test);
$pos2 = strpos($str, $test2, $posStart);
$found[] = ($pos2!==false) ? $pos2 : INF;
}
$min = min($found);
if ($min !== INF)
return substr($str,$pos,$min-$pos) .$str[$min];
}
return '';
}
echo earchString($str, $array_a, $array_b);
Hello everyone the search is not working. For example the tags contain Php, Ajax, HTML 5 when you search Php or Ajax there is a result but if you search two words or more such as HTML 5 there is no result.
my model Codes:
public function getTagsMatch($limit=null, $tags, $offset=null) {
$match = $tags;
$this->db->from('threads');
$this->db->where('status', 1);
$search_query_values = explode(' ', $match);
$counter = 0;
foreach ($search_query_values as $key => $value) {
if ($counter == 0) {
$this->db->like('tags', $value);
}
$counter++;
}
$this->db->order_by('pin_post', 'DESC');
$this->db->order_by('id', 'DESC');
$this->db->limit($limit);
$this->db->offset($offset);
$query = $this->db->get();
return $query->result_array();
}
Well...
$search_query_values = explode(' ', $match);
This line takes in query values and "explodes" the string using spaces. So if you input "HTML 5", it will actually search for tags like "HTML" or "5". Consider using a different character for exploding.
For example:
$search_query_values = explode(',', $match);
And the function call would be something like this:
getTagsMatch(NULL, 'Ajax,HTML 5,PHP', NULL);
A few more notes:
Default parameters should be at the end of an argument list (function foo(bar0, bar1=0, bar2='') { ... }, not randomly placed).
Consider using less variables. There is absolutely no reason to have $tags, $match and $search_query_values - one is enough. You might consider using 3 variables a semantic advantage, but it actually makes your code more difficult to read.
The problem of this was on my controller because. I customize the tags but the fact is Im having a trouble how to explain this since Im not good in explaining such thing. I will just post some of the codes with some explanation.
My tags search will base on what is the tags slug for example website.com/tags/html-5
so my controller codes:
public function tags($tags) {
$tag = search_title($tags);
$data['result'] = $this->topic_model->getTagsMatch($tag);
}
and my search_title function code:
function search_title($str, $separator = ' ') {
$str = ucwords(strtolower($str));
foreach (array('-', '\'') as $delimiter) {
if (strpos($str, $delimiter)!==false)
{
$str =implode($delimiter, array_map('ucfirst', explode($delimiter, $str)));
}
}
$str = str_replace('-',' ',$str);
$str = str_replace('%20',' ',$str);
$str = str_replace('%26','&',$str);
$str = str_replace('%27',' ',$str);
$str = str_replace('%28',' ',$str);
$str = str_replace('%29',' ',$str);
return trim(stripslashes($str));
}
the problem of it is on this line
$data['result'] = $this->topic_model->getTagsMatch($tag);
so I change the $tag to str_replace("-"," ",$tags)
I've done a bunch of searching but can't figure this one out.
I have an array like this:
$array = array(cat => 0, dog => 1);
I have a string like this:
I like cats.
I want to see if the string matches any keys in the array. I try the following but obviously it doesn't work.
array_key_exists("I like cats", $array)
Assuming that I can get any random string at a given time, how can I do something like this?
Pseudo code:
array_key_exists("I like cats", *.$array.*)
//The value for cat is "0"
Note that I want to check if "cat" in any form exists. It can be cats, cathy, even random letter like vbncatnm. I am getting the array from a mysql database and I need to know which ID cat or dog is.
You can use a regex on keys. So, if any words of your string equal to the key, $found is true. You can save the $key in the variable if you want. preg_match function allows to test a regular expression.
$keys = array_keys($array);
$found = false;
foreach ($keys as $key) {
//If the key is found in your string, set $found to true
if (preg_match("/".$key."/", "I like cats")) {
$found = true;
}
}
EDIT :
As said in comment, strpos could be better! So using the same code, you can just replace preg_match:
$keys = array_keys($array);
$found = false;
foreach ($keys as $key) {
//If the key is found in your string, set $found to true
if (false !== strpos("I like cats", $key)) {
$found = true;
}
}
This should help you achieve what you're trying to do:
$array = array('cat' => 10, 'dog' => 1);
$findThis = 'I like cats';
$filteredArray = array_filter($array, function($key) use($string){
return strpos($string, $key) !== false;
}, ARRAY_FILTER_USE_KEY);
I find that using the array_filter function with a closure/anonymous function to be a much more elegant way than a foreach loop because it maintains one level of indentation.
You could do using a preg_match with the value not in array but in search criteria
if(preg_match('~(cat|dog)~', "I like cats")) {
echo 'ok';
}
or
$criteria = '~(cat|dog)~';
if (preg_match($criteria, "I like cats")) {
echo 'ok';
}
Otherwise you could use a foreach on your array
foreach($array as $key => $value ) {
$pos = strpos("I like cats", $key);
if ($pos > 0) {
echo $key . ' '. $value;
}
}
I have this code:
$getClass = $params->get('pageclass_sfx');
var_dump($getClass); die();
The code above returns this:
string(24) "sl-articulo sl-categoria"
How can I retrieve the specific word I want without mattering its position?
Ive seen people use arrays for this but that would depend on the position (I think) that you enter these strings and these positions may vary.
For example:
$myvalue = $params->get('pageclass_sfx');
$arr = explode(' ',trim($myvalue));
echo $arr[0];
$arr[0] would return: sl-articulo
$arr[1] would return: sl-categoria
Thanks.
You can use substr for that in combination with strpos:
http://nl1.php.net/substr
http://nl1.php.net/strpos
$word = 'sl-categoria';
$page_class_sfx = $params->get('page_class_sfx');
if (false !== ($pos = strpos($page_class_sfx, $word))) {
// stupid because you already have the word... But this is what you request if I understand correctly
echo 'found: ' . substr($page_class_sfx, $pos, strlen($word));
}
Not sure if you want to get a word from the string if you already know the word... You want to know if it's there? false !== strpos($page_class_sfx, $word) would be enough.
If you know exactly what strings you're looking for, then stripos() should be sufficient (or strpos() if you need case-sensitivity). For example:
$myvalue = $params->get('pageclass_sfx');
$pos = stripos($myvalue, "sl-articulo");
if ($pos === FALSE) {
// string "sl-articulo" was not found
} else {
// string "sl-articulo" was found at character position $pos
}
If you need to check if some word are in string you may use preg_match function.
if (preg_match('/some-word/', 'many some-words')) {
echo 'some-word';
}
But this solution can be used for a small list of needed words.
For other cases i suggest you to use some of this.
$myvalue = $params->get('pageclass_sfx');
$arr = explode(' ',trim($myvalue));
$result = array();
foreach($arr as $key=> $value) {
// This will calculates all data in string.
if (!isset($result[$value])) {
$result[$value] = array(); // or 0 if you don`t need to use positions
}
$result[$value][] = $key; // For all positions
// $result[$value] ++; // For count of this word in string
}
// You can just test some words like follow:
if (isset($result['sl-categoria'])) {
var_dump($result['sl-categoria']);
}
I have a PHP array of about 20,000 names, I need to filter through it and remove any name that has the word job, freelance, or project in the name.
Below is what I have started so far, it will cycle through the array and add the cleaned item to build a new clean array. I need help matching the "bad" words though. Please help if you can
$data1 = array('Phillyfreelance' , 'PhillyWebJobs', 'web2project', 'cleanname');
// freelance
// job
// project
$cleanArray = array();
foreach ($data1 as $name) {
# if a term is matched, we remove it from our array
if(preg_match('~\b(freelance|job|project)\b~i',$name)){
echo 'word removed';
}else{
$cleanArray[] = $name;
}
}
Right now it matches a word so if "freelance" is a name in the array it removes that item but if it is something like ImaFreelaner then it does not, I need to remove anything that has the matching words in it at all
A regular expression is not really necessary here — it'd likely be faster to use a few stripos calls. (Performance matters on this level because the search occurs for each of the 20,000 names.)
With array_filter, which only keeps elements in the array for which the callback returns true:
$data1 = array_filter($data1, function($el) {
return stripos($el, 'job') === FALSE
&& stripos($el, 'freelance') === FALSE
&& stripos($el, 'project') === FALSE;
});
Here's a more extensible / maintainable version, where the list of bad words can be loaded from an array rather than having to be explicitly denoted in the code:
$data1 = array_filter($data1, function($el) {
$bad_words = array('job', 'freelance', 'project');
$word_okay = true;
foreach ( $bad_words as $bad_word ) {
if ( stripos($el, $bad_word) !== FALSE ) {
$word_okay = false;
break;
}
}
return $word_okay;
});
I'd be inclined to use the array_filter function and change the regex to not match on word boundaries
$data1 = array('Phillyfreelance' , 'PhillyWebJobs', 'web2project', 'cleanname');
$cleanArray = array_filter($data1, function($w) {
return !preg_match('~(freelance|project|job)~i', $w);
});
Use of the preg_match() function and some regular expressions should do the trick; this is what I came up with and it worked fine on my end:
<?php
$data1=array('JoomlaFreelance','PhillyWebJobs','web2project','cleanname');
$cleanArray=array();
$badWords='/(job|freelance|project)/i';
foreach($data1 as $name) {
if(!preg_match($badWords,$name)) {
$cleanArray[]=$name;
}
}
echo(implode($cleanArray,','));
?>
Which returned:
cleanname
Personally, I would do something like this:
$badWords = ['job', 'freelance', 'project'];
$names = ['JoomlaFreelance', 'PhillyWebJobs', 'web2project', 'cleanname'];
// Escape characters with special meaning in regular expressions.
$quotedBadWords = array_map(function($word) {
return preg_quote($word, '/');
}, $badWords);
// Create the regular expression.
$badWordsRegex = implode('|', $quotedBadWords);
// Filter out any names that match the bad words.
$cleanNames = array_filter($names, function($name) use ($badWordsRegex) {
return preg_match('/' . $badWordsRegex . '/i', $name) === FALSE;
});
This should be what you want:
if (!preg_match('/(freelance|job|project)/i', $name)) {
$cleanArray[] = $name;
}