Joomla Component: View: Get values from field - php

Question

I'm new to Joomla, especially to component development. Anyway, here's my question:
site\views\plaingallery\tmpl\default.xml
<?xml version="1.0" encoding="utf-8"?>
<metadata>
<layout title="COM_PLAINGALLERY_PLAINGALLERY_VIEW_DEFAULT_TITLE">
<message>
<![CDATA[COM_PLAINGALLERY_PLAINGALLERY_VIEW_DEFAULT_DESC]]>
</message>
</layout>
<fields name="request"
addfieldpath="/administrator/components/com_plaingallery/models/fields">
<fieldset name="request">
<field name="galleryFolder" type="folderlist" default="" recursive="true"
label="Select a folder" directory="images" filter="" exclude="" width="300"
hide_none="true" hide_default="true" stripext="" />
</fieldset>
</fields>
</metadata>
site\views\plaingallery\view.html.php
<?php
// No direct access to this file
defined('_JEXEC') or die('Restricted access');
// import Joomla view library
jimport('joomla.application.component.view');
/**
* HTML View class for the PlainGallery Component
*/
class PlainGalleryViewPlainGallery extends JViewLegacy
{
// Overwriting JView display method
function display($tpl = null)
{
// Assign data to the view
$this->msg = 'I am new to Joomla';
// Display the view
parent::display($tpl);
}
}
My question is: How do I access the value from the field[name="galleryFolder"] the user provided in the menu configuration?
Thanks for your help! I really do appreciate it.

Answer 1

This parameter is located in the query variable of the menu item.
You can try this for example:
$app = JFactory::getApplication();
/* Default Page fallback*/
$active = $app->getMenu()->getActive();
if (NULL == $active) {
$active = $app->getMenu()->getDefault();
}
if ( isset($active->query['galleryFolder']) ) {
$galleryFolder = $active->query['galleryFolder'];
}