I want dates like if today is Tuesday then I want a date from starting of this week to the current day and get last week date from starting of last week to the current day like if today is 11-02-2020 and Tuesday then I want date like 10-02-2020 11-02-2020 and last week dates like 03-02-2020 04-02-2020
for that, I have used below functions
function last_week_date(){
date_default_timezone_set("Asia/Kolkata");
$day = date("l");
$previous_week = strtotime("-1 week +1 day");
$start_week = strtotime("last monday",$previous_week);
$end_week = strtotime("next $day",$start_week);
$start_week = date("Y-m-d",$start_week);
$end_week = date("Y-m-d",$end_week);
return $start_week.' '.$end_week ;
}
function this_week_date(){
date_default_timezone_set("Asia/Kolkata");
$day = date("l");
$previous_week = strtotime("+1 day");
$start_week = strtotime("last monday",$previous_week);
$end_week = strtotime("next $day",$start_week);
$start_week = date("Y-m-d",$start_week);
$end_week = date("Y-m-d",$end_week);
return $start_week.' '.$end_week ;
}
but with this, I have received dates of the full week not till a particular day
can anybody help me with this
This function will give you the results you want. You can simply pass it a parameter which is the number of weeks forward or backward to shift the dates to get this weeks/last weeks/next weeks days:
function week_date($weeks = 0) {
$start = new DateTime("monday this week");
$end = new DateTime();
$start->modify("$weeks weeks");
$end->modify("$weeks weeks");
return $start->format('Y-m-d') . ' ' . $end->format('Y-m-d');
}
To call, use
echo week_date() . "\n"; // this week
echo week_date(-1) . "\n"; // last week
echo week_date(1) . "\n"; // next week
Output (as of Monday 2020-02-10):
2020-02-10 2020-02-10
2020-02-03 2020-02-03
2020-02-17 2020-02-17
Demo on 3v4l.org
When i have current date is in "31/12/2017". I need to find date of after 2 months that means its February. When its february i need to get as "29/2/2018". But When we use below code i got "03/03/2018". Can you please help me to solve this task,
Here i added my PHP code,
$xmasDay = new DateTime('2017-12-31 + 2 month');
echo $xmasDay->format('Y-m-d');
please try this
<?php
function add_month($date_str, $months)
{
$date = new DateTime($date_str);
// We extract the day of the month as $start_day
$start_day = $date->format('j');
// We add 1 month to the given date
$date->modify("+{$months} month");
// We extract the day of the month again so we can compare
$end_day = $date->format('j');
if ($start_day != $end_day)
{
// The day of the month isn't the same anymore, so we correct the date
$date->modify('last day of last month');
}
return $date->format('Y-m-d');
}
$result = add_month('2017-12-31', 2);
echo $result
calculate from first of the month, then use date t
$orginal = '2017-12-31';
$orginal = explode('-', $orginal);
$originalDate = strtotime($orginal[0] . '-' . $orginal[1] . '-01 00:00:00');
$newDate = strtotime('+2 month', $originalDate);
echo date('Y-m-t', $newDate);
// or
$date = new DateTime();
$date->setTimestamp($newDate);
echo $date->format('Y-m-t');
I am making a page to let the clients choose a date for an appointment, so I need to build a list of the dates like this :
always begin from tomorrow, end by 6 months
always from Mondy to Saturday, no Sunday
the day of the week need to be in chinese, like "Monday" is "星期一", but the timezone is in France
Here is the php
date_default_timezone_set('Europe/Paris');
$tomorrow = date("Y年m月d日 l", time() + 86400);
$end = date("Y年m月d日 l", time() + 86400 * 7); // just 7 days for a try
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($tomorrow, $interval, $end);
foreach ($daterange as $date) {
echo $date . '<br/>';
}
This code is not working.
I need to build an array, which store all the dates of next 6 months, begin from tomorrow, without Sunday, the days need to be in chinese and the timezone needs to be in Europe, is that possible?
I think strtotime and array_push is what you are looking for. Try this:
$curDate = date('Y-m-d', strtotime('+1 day'));
$endDate = date('Y-m-d', strtotime('+6 months +1 day'));
$myArr = array();
while ($endDate >= $curDate) {
if (date('w', strtotime($curDate)) !== '0') array_push($myArr, $curDate);
$curDate = date('Y-m-d', strtotime($curDate . " +1 days"));
}
var_dump($myArr);
For the Options, create an array from sunday to saturday.
$weekdays = array('Sunday', ..., 'Saturday');
echo date('Y/m/d', strtotime($curDate)) . ' ' . $weekdays[date('w', strtotime($curDate))];
I like to iterate through all weeks in a date range that spawns 2 years. Starting at the current week number two years ago, until the current week number this year.
The problem is that a year can either have 52 weeks or 53 weeks, for example:
2015 had 53 weeks (the 53th was from 2015-12-28 till 2016-01-03)
2016 had 52 weeks (the 52th was from 2016-12-26 till 2017-01-01)
So this is currently my php code:
# start with the current week 2 years ago
$year = date("Y") - 2;
$week = (int) date("W"); // (int) removes leading zero for weeks < 10
$endYear = date("Y");
$endWeek = (int) date("W");
# iterate through all weeks until now
do {
echo $week. " of ". $year;
$week++;
if ($week > 52) { // or greater 53 ?????????????
$year ++;
$week = 1;
}
}
while ($year < $endYear || $week < $endWeek);
Instead of trying to keep track of the bounds, let PHP do it for you.
$start = new DateTime('-2 years');
$end = new DateTime();
$interval = new DateInterval('P1W');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $date) {
echo $date->format('W') . " of ". $date->format('Y') . "\n";
}
Demo
With the help of Ross Wilson and John Conde I found a solution:
$now = new DateTime;
$from = (new DateTime)->setISODate($now->format('Y') - 2, $now->format('W'));
$from->modify("thursday this week"); // see ISO 8601
while($from < $now) {
echo $from->format('W Y').'<br />';
$from->modify("+1 week");
}
It is important so set the week day to thursday, because according to ISO 8601, the week "belongs" to the year which still contains the thursday.
You could use DateTime and setISODate for something like this:
$now = new DateTime;
$from = (new DateTime)->setISODate($now->format('Y') - 2, $now->format('W'));
while($from < $now) {
echo $from->format('W Y').'<br />';
$from->modify("1 week");
}
Hope this helps!
how can I get last week' date range in php ?
see my codes bellow:
<?php
function get_last_week_dates(){
// how can i get the date range last week ?
// ex: today is 2014-2-8
// the week date range of last week should be '2014-1-26 ~ 2014-2-1'
}
?>
You can use strtotime()
$previous_week = strtotime("-1 week +1 day");
$start_week = strtotime("last sunday midnight",$previous_week);
$end_week = strtotime("next saturday",$start_week);
$start_week = date("Y-m-d",$start_week);
$end_week = date("Y-m-d",$end_week);
echo $start_week.' '.$end_week ;
UPDATE
Changed the code to handle sunday. If the current day is sunday then - 1 week will be previous sunday and again getting previous sunday for that will go the one week back.
$previous_week = strtotime("-1 week +1 day");
In addition if we need to find the current week and next week date
range we can do as
Current week -
$d = strtotime("today");
$start_week = strtotime("last sunday midnight",$d);
$end_week = strtotime("next saturday",$d);
$start = date("Y-m-d",$start_week);
$end = date("Y-m-d",$end_week);
Next Week -
$d = strtotime("+1 week -1 day");
$start_week = strtotime("last sunday midnight",$d);
$end_week = strtotime("next saturday",$d);
$start = date("Y-m-d",$start_week);
$end = date("Y-m-d",$end_week);
Simply use
date("m/d/Y", strtotime("last week monday"));
date("m/d/Y", strtotime("last week sunday"));
It will give the date of Last week's Monday and Sunday.
you need you use strtotime function for this
<center>
<?php
function get_last_week_dates()
{
// how can i get the date range last week ?
// ex: today is 2014-2-8
// the week date range of last week should be '2014-1-26 ~ 2014-2-1'
$startdate = "last monday";
if (date('N') !== '1')
{
// it's not Monday today
$startdate .= " last week";
}
echo "<br />";
$day = strtotime($startdate);
echo date('r', $day);
echo "<br />";
$sunday = strtotime('next monday', $day) - 1;
echo date('r', $sunday);
}
get_last_week_dates();
?>
</center>
Well just for the fun of trying to solve this:
date_default_timezone_set('UTC');
$firstDayOfLastWeek = mktime(0,0,0,date("m"),date("d")-date("w")-7);
$lastDayOfLastWeek = mktime(0,0,0,date("m"),date("d")-date("w")-1);
echo("Last week began on: ".date("d.m.Y",$firstDayOfLastWeek));
echo("<br>");
echo("Last week ended on: ".date("d.m.Y",$lastDayOfLastWeek));
This should do the trick
$startWeek = date('Y-m-d',strtotime("Sunday Last Week"));
$endWeek = date('Y-m-d',strtotime("Sunday This Week"));
this would not work if ran on a Monday. It would get last Sunday (the day before) to the next Sunday. So using Abhik Chakraborty's method with the above:
$startTime = strtotime("last sunday midnight",$previous_week);
$endTime = strtotime("next sunday midnight",$startTime);
$startDate = date('Y-m-d 00:00:00',$startTime);
$endDate = date('Y-m-d 23:59:59',$endTime);
This will now give
start = 2014-08-10 00:00:00
endDate = 2014-08-17 23:59:59
I know this is old but here's a much more succinct way of doing it:
$startDate = date("m/d/y", strtotime(date("w") ? "2 sundays ago" : "last sunday"));
$endDate = date("m/d/y", strtotime("last saturday"));
echo $startDate . " - " . $endDate
This one will produce the proper result and handles the Monday issue
<?php
$monday = strtotime("last monday");
$monday = date('W', $monday)==date('W') ? $monday-7*86400 : $monday;
$sunday = strtotime(date("Y-m-d",$monday)." +6 days");
$this_week_sd = date("Y-m-d",$monday);
$this_week_ed = date("Y-m-d",$sunday);
echo "Last week range from $this_week_sd to $this_week_ed ";
?>
Most of those other solutions offered were off by one day.
If you want Sunday to Saturday for last week, this is the way to do it.
$start = date("Y-m-d",strtotime("last sunday",strtotime("-1 week")));
$end = date("Y-m-d",strtotime("saturday",strtotime("-1 week")));
echo $start. " to ".$end;
Carbon
$startOfTheWeek = Carbon::now()->subWeek(1)->startOfWeek();
$endOfTheWeek = Carbon::now()->subWeek(1)->endOfWeek();
From a specific date
$startOfTheWeek = Carbon::parse('2020-03-02')->subWeek(1)->startOfWeek();
$endOfTheWeek = Carbon::parse('2020-03-02')->subWeek(1)->endOfWeek();
Considering the week starts at Monday and ends at Sunday.
You can do this way.
First get the current timestamp and subtract the no.of days you want.
$curTime = time();
echo date("Y-m-d",$curTime);
echo "<br />";
echo date("Y-m-d",($curTime-(60*60*24*7)));
$lastWeekStartTime = strtotime("last sunday",strtotime("-1 week"));
$lastWeekEndTime = strtotime("this sunday",strtotime("-1 week"));
$lastWeekStart = date("Y-m-d",$lastWeekStartTime);
$lastWeekEnd = date("Y-m-d",$lastWeekEndTime);
In order to find the last week start date and end date you can follow up this code for doing it so.
It works on all intervals to find the date interval.
$Current = Date('N');
$DaysToSunday = 7 - $Current;
$DaysFromMonday = $Current - 1;
$Sunday = Date('d/m/y', strtotime("+ {$DaysToSunday} Days"));
$Monday = Date('d/m/y', strtotime("- {$DaysFromMonday} Days"));
If so you need to change it with the datatime() you can perform this function.
$date = new DateTime();
$weekday = $date->format('w');
$diff = 7 + ($weekday == 0 ? 6 : $weekday - 1); // Monday=0, Sunday=6
$date->modify("-$diff day");
echo $date->format('Y-m-d') . ' - ';
$date->modify('+6 day');
echo $date->format('Y-m-d');
Using Functions:
If you want to find the last week range with the help of the functions you can preform like this.
Function:
// returns last week's range
function last_week_range($date) {
$ts = strtotime("$date - 7 days");
$start = (date('w', $ts) == 0) ? $ts : strtotime('last sunday', $ts);
return array(
date('Y-m-d', $start),
date('Y-m-d', strtotime('next saturday', $start))
);
}
Usage:
$today=date();
print_r(last_week_range($today));
All the above functions that has been given will return the last week range irrespective of the start day of the week..