Codeigniter data from view to controller - php

Question

Each User has multi profiles. once they logged in, they are asked to select a profile,
here is the code for Form to select profile.
<div class="row">
<div class="col-md-4 col-md-offset-4">
<div class="login-panel panel panel-default">
<div class="panel-heading">
<h3 align ="center" class="panel-title">Select Profiles</h3>
</div>
<div class="panel-body">
<?php
foreach($resJacs->{'details'} as $key) {
echo form_open('selectaccess', array(
'class' => 'form-group',
'role' => 'form'
));
echo form_submit(array(
'value' => $key->profile_name,
'name' => $key->profile_type,
'class' => 'btn btn-lg btn-default btn-block'
));
echo form_close();
}
?>
</div>
</div>
</div>
</div>
when user selects the profile profile id is passed to session for later use. here is the code for "selectaccess",
public function SelectAccess() {
$sess_data = array(
'id' => $this->session->userdata['is_logged_in']['id'],
'prfid' => $this->input->post('')
);
print_r($sess_data);
}
how can i prfid as mentioned in selectaccess method.

Answer 1

I just want to give an example, maybe this can help u :
I am use pure html .
<form action="SelectAccess/<?php echo $id; ?>">
<input type="text" name="name">
<button type="submit">Submit</button>
</form>
Controller
function SelectAccess($val='') {
$input = $this->input->post('name');
$_SESSION['whatever'] = $val;
}

Answer 2

Normally you need to know the name of the field in order to get the value at the controller. But you are dynamically creating the field names so that gets tricky.
Fortunately you are only posting one input so $_POST should have only one item. The way your view is written the value of $_POST[0] will be provided by $key->profile_name. Hopefully, that value is what you are looking for.
public function SelectAccess() {
{
$sess_data = array(
'id' => $this->session->userdata['is_logged_in']['id'],
'prfid' => isset($_POST[0])) ? $_POST[0] : NULL;
);
}