Affecting all data in Database While Using Modal - php

Question

Without Modal, user_timeout.php does not have a problem but When I use modal, as you can see at the picture below the problem is. But they have same logic codes so I dont know what the problem is. I want to use modal for some quality design so help me guys thank you
logs.php
<a rel="tooltip" title="Timeout" id="<?php echo $idlogs; ?>" href="user_timeout.php<?php echo '?id='.$idlogs; ?>" class="btn btn-info"><i class="icon-minus icon-large"></i> Manual Time-Out</a>
And for Modal
<a rel="tooltip" title="timeout" id="<?php echo $idlogs; ?>" href="#timeout<?php echo $idlogs; ?>" data-toggle="modal" class="btn btn-success"><i class="icon-pencil icon-large"></i> Manual Time-Out</a>
<?php include('modal_time_user.php'); ?>
user_timeout.php
<?php $get_id= $_GET['id']; ?>
<div class="container">
<div class="margin-top">
<div class="row">
<div class="span12">
<?php
$query=mysqli_query($dbcon,"select * from user_logs_tbl where id ='$get_id'")or die(mysqli_error());
$row=mysqli_fetch_assoc($query);
$iduser=$row['user_id'];
$idlogs=$row['id'];
?>
<div class="alert alert-info"><i class="icon-pencil></i> Manual Time-out</div>
<p><a class="btn btn-info" href="logs.php"><i class="icon-arrow-left icon-large"></i> Back</a></p>
<div class="addstudent">
<div class="details">Please Enter Details Below</div>
<form class="form-horizontal" method="POST" enctype="multipart/form-data">
<div class="control-group">
<br>
<div class="control-group">
<label class="control-label" style="margin-left:10%;" for="inputEmail">Time-Out:</label>
<div class="controls">
<input type="time" id="inputEmail" name="timeout" placeholder="Time">
</div>
</div>
<br>
<div class="control-group">
<div class="controls">
<button name="timeouts" type="submit" style="margin-left:16%;" class="btn btn-success"><i class="icon-save icon-large"></i> Update</button>
</div>
</div>
</form>
</div>
</div>
</div>
</div>
</div>
<?php
if (isset($_POST['timeouts'])){
$timeout=$_POST['timeout'];
$timeout = date('Y-m-d H:i:s', strtotime(str_replace('-', '/',
$timeout)));
mysqli_query($dbcon,"UPDATE user_logs_tbl set time_out = '$timeout' where id='$idlogs'")or die(mysqli_error($dbcon));
$yourURL="logs.php";
echo ("<script>location.href='$yourURL'</script>");
}
?>
But If I change it into modal form, it's working but all data will change if I change one
modal_time_user.php
<div id="timeout<?php echo $idlogs; ?>" class="modal hide fade" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-body">
<div class="alert alert-info"><strong>Time</strong></div>
<form class="form-horizontal" method="post">
<div class="control-group">
<label class="control-label" for="inputEmail">Time-Out :</label>
<div class="controls">
<input type="time" id="inputEmail" name="time_out" pattern="[a-zA-Z0-9]{5,}" required>
</div>
</div>
<div class="control-group">
<div class="controls">
<button name="enter" type="submit" class="btn btn-success"><i class="icon-save icon-large"></i> Update</button>
</div>
</div>
</form>
</div>
<div class="modal-footer">
<button class="btn" data-dismiss="modal" aria-hidden="true"><i class="icon-remove icon-large"></i> Close</button>
</div>
</div>
<?php
if (isset($_POST['enter'])){
$timeout=$_POST['time_out'];
$timeout = date('Y-m-d H:i:s', strtotime(str_replace('-', '/', $timeout)));
mysqli_query($dbcon,"UPDATE user_logs_tbl SET time_out='$timeout' where id = '$idlogs'")or die(mysqli_error($dbcon));
$yourURL="logs.php";
echo ("<script>location.href='$yourURL'</script>");
}
?>
Problem
After Inserting a Time Out In USER ID 45