JSON response is not populating in dropdown perhap query gat the result perfectly.
alert the success function i.e
alert(result.data);--[object object]
here is my html code
Jquery
function fillTransferJobPositionAreaDropDown( job_type_id,province_id,region_id,district_id,tehsil_id,uc_id, area_id) {
var loadDDUrl = baseApiUrl + "Employee/all_new_job_positions_area/"+job_type_id+"/"+province_id+"/"+region_id+"/"+district_id+"/"+tehsil_id+"/"+uc_id+"/"+area_id;
console.log(loadDDUrl);
debugger;
newJobPositionIDFld.empty();
newJobPositionIDFld.append($("<option />").val("0").text("Select New Job Position"));
newJobPositionIDFld.select2('val', '0');
var url = loadDDUrl;
$.ajax({
url: url,
accepts: 'application/json',
cache: false,
type : 'GET',
dataType: 'jsonp',
success: function (result) {
alert(result.data);
console.log(result.data);
// Handle the complete event
if(result.data == null) return;
$.each(result.data, function () {
newJobPositionIDFld.append($("<option />").val(this.job_position_id).text(this.job_position_id+'-'+this.job_name));
});
}
});
}//End Ajax call
PHP
$this->db->select('jp.job_position_id,jp.jobposition_title as job_name');
$this->db->from('job_positions jp');
$this->db->where('jp.job_type_id', $job_type_id);
$this->db->where('jp.province_id', $province_id);
$this->db->where('jp.region_id', $region_id);
$this->db->where('jp.district_id', $district_id);
$this->db->where('jp.tehsil_id', $tehsil_id);
$this->db->where('jp.uc_id', $uc_id);
$this->db->where('jp.area_id', $area_id);
$this->db->get()->row_array();
Your query returns a object, not an array of objects, so remove the loop:
success: function (result) {
newJobPositionIDFld.append($("<option/>").val(result.data.job_position_id).text(result.data.job_position_id+'-'+result.data.job_name));
}
Related
I am trying to send form data using ajax. But there's an error in ajax operation and only "error" callback function is executed.
Here's what I tried:
$("#issue_submit").click(function (e) {
console.log("clicked on the issue submit");
e.preventDefault();
// Validate the form
var procurementForm = $("#it_procuremet_form");
if($(procurementForm).valid()===false){
return false;
}
// Show ajax loader
appendData();
var formData = $(procurementForm).serialize();
// Send request to save the records through ajax
var formRequest = $.ajax({
url: app.baseurl("itprocurement/save"),
data: formData,
type: "POST",
dataType: "json"
});
formRequest.done(function (res) {
console.log(res);
});
formRequest.error(function (res, err) {
console.log(res);
});
formRequest.always(function () {
$("#overlay-procurement").remove();
// do somethings that always needs to occur regardless of error or success
});
});
Routes are defined as:
$f3->route('POST /itprocurement/save', 'GBD\Internals\Controllers\ITProcurementController->save');
Also I added :
$f3->route('POST /itprocurement/save [ajax]', 'GBD\Internals\Controllers\ITProcurementController->save');
I tried returning a simple string to the ajax call at the controller class.
ITProcurementController.php :
public function save($f3)
{
echo 'Problem!';
return;
$post = $f3->get('POST');
}
But only 'error' callback is executed. I cannot locate what is wrong. Please Help.
You are specifying that you expect json back:
// Send request to save the records through ajax
var formRequest = $.ajax({
url: app.baseurl("itprocurement/save"),
data: formData,
type: "POST",
// Here you specify that you expect json back:
dataType: "json"
});
What you send back is not json:
echo 'Problem!';
return;
This is an unquoted string, which is not valid json.
To send valid json back, you would need:
echo json_encode('Problem!');
return;
You could also remove the dataType attribute, depending on your needs.
I'm trying to pass a long Html string from a view to a controller using an ajax call, so I can pass it further to another view.
Markup:
<a id="openPDF">Save as PDF</a>
JS:
$('#openPDF').click(function(){
var htmlText = $( "div.modal" ).html(); //grab the html
var dataToSend = JSON.stringify("{strData : '" + htmlText + "' }");
console.log(dataToSend ); // contains the json
$.ajax({
url: "/dashboard/pdf",
type: "POST",
contentType: "application/json; charset=utf-8",
dataType: "json",
data: dataToSend
success: function (msg) { alert(msg.d); },
error: function (type) { alert("ERROR!" + type.responseText); }
});
});
Controller:
public function pdf(){
$data['htmlString'] = json_decode($this->input->post('strData'));
$this->load->view('pdf', $data);
}
My ajax call doesn't work because when a click the #openPDF button i get the alert error:
ERROR! NULL
What am I doing wrong?
Are you setting your headers properly before writing the output?
Controller:
public function pdf() {
$data['htmlString'] = json_decode($this->input->post('strData'));
$viewString = $this->load->view('pdf', $data, true); // this returns view as string rather than outputting it
header('Content-Type: application/json');
echo json_encode(['viewString' => $viewString]);
}
In client-side js, you can pass this success function to $.ajax()
success: function (response) {
if ('undefined' !== typeof response.viewString) {
// append view to concerned element
$('#viewTarget').append(response.viewString);
} else {
console.log('response did not contain viewString');
}
},
I hope this helps.
Also:
Navigate directly to the url (the one you are sending an ajax request for) in your browser and see if you get a valid json output.
I'm sending a ajax request to update database records, it test it using html form, its working fine, but when i tried to send ajax request its working, but the response I received is always null. where as on html form its show correct response. I'm using xampp on Windows OS. Kindly guide me in right direction.
<?php
header('Content-type: application/json');
$prov= $_POST['prov'];
$dsn = 'mysql:dbname=db;host=localhost';
$myPDO = new PDO($dsn, 'admin', '1234');
$selectSql = "SELECT abcd FROM xyz WHERE prov='".mysql_real_escape_string($prov)."'";
$selectResult = $myPDO->query($selectSql);
$row = $selectResult->fetch();
$incr=intval($row['votecount'])+1;
$updateSql = "UPDATE vote SET lmno='".$incr."' WHERE prov='".mysql_real_escape_string($prov)."'";
$updateResult = $myPDO->query($updateSql);
if($updateResult !== False)
{
echo json_encode("Done!");
}
else
{
echo json_encode("Try Again!");
}
?>
function increase(id)
{
$.ajax({
type: 'POST',
url: 'test.php',
data: { prov: id },
success: function (response) {
},
complete: function (response) {
var obj = jQuery.parseJSON(response);
alert(obj);
}
});
};
$.ajax({
type: 'POST',
url: 'test.php',
data: { prov: id },
dataType: 'json',
success: function (response) {
// you should recieve your responce data here
var obj = jQuery.parseJSON(response);
alert(obj);
},
complete: function (response) {
//complete() is called always when the request is complete, no matter the outcome so you should avoid to recieve data in this function
var obj = jQuery.parseJSON(response.responseText);
alert(obj);
}
});
complete and the success function get different data passed in. success gets only the data, complete the whole XMLHttpRequest
First off, in your ajax request, you'll want to set dataType to json to ensure jQuery understands it is receiving json.
Secondly, complete is not passed the data from the ajax request, only success is.
Here is a full working example I put together, which I know works:
test.php (call this page in your web browser)
<script type="text/javascript" src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
<script type="text/javascript">
// Define the javascript function
function increase(id) {
var post_data = {
'prov': id
}
$.ajax({
'type': 'POST',
'url': 'ajax.php',
'data': post_data,
'dataType': 'json',
'success': function (response, status, jQueryXmlHttpRequest) {
alert('success called for ID ' + id + ', here is the response:');
alert(response);
},
'complete': function(jQueryXmlHttpRequest, status) {
alert('complete called');
}
});
}
// Call the function
increase(1); // Simulate an id which exists
increase(2); // Simulate an id which doesn't exist
</script>
ajax.php
<?php
$id = $_REQUEST['prov'];
if($id == '1') {
$response = 'Done!';
} else {
$response = 'Try again!';
}
print json_encode($response);
This question already has answers here:
How do I return the response from an asynchronous call?
(41 answers)
Closed 10 years ago.
Trying to run a script, (test.al();) and inside test.al, its called getcrypt.php();, the php script is on a webserver, and it is working. Currently, these are my scripts
JS
var getcrypt = {
php: function () {
$.ajax({
url: "server.com/return.php",
type: "POST",
async: true,
data: "id=getit",
success: function (msg) {
var v = msg.match(/^.*$/m)[0];
return v;
}
});
}
}
var test = {
al: function () {
a = getcrypt.php();
alert(a);
}
}
PHP
<?php
$id = $_POST['id'];
if ('getit' == $id){
$value = 'VALUE';
echo $value;
}else{
echo 0;
}
?>
In this way, it will show an alert with 'unidefined', and if i add a alert(v); right before return v, it will show me 'VALUE', but not able to use it outside the variable...
var getcrypt = {
php: function () {
$.ajax({
url: "server.com/return.php",
type: "POST",
async: true,
data: "id=getit",
success: function (msg) {
var v = msg.match(/^.*$/m)[0];
alert(v);
return v;
}
});
}
}
This will give me an alert with the correct value (AFTER THE 'undefined')
This is because of the asynchronous call you're making. The return is only for the success function and not for the php function.
To get the value out you would need to write:
var value;
var getcrypt = {
php: function (callback) {
$.ajax({
url: "",
type: "POST",
async: true,
data: "id=getit",
success: function (msg) {
var v = msg.match(/^.*$/m)[0];
alert(v);
callback(v);
}
});
}
}
getcrypt.php(function(v) {
alert(v);
// This happens later than the below
value = v;
});
// The below will still not work since execution has already passed this place
// alert will still return undefined
alert(value);
The problem is jQuery ajax works with callbacks and does not work with return value's so you need to add an callback to your getcrypt function so say
var getcrypt = {
php: function (callback) {
$.ajax({
url: "server.com/return.php",
type: "POST",
async: true,
data: "id=getit",
success: function (msg) {
var v = msg.match(/^.*$/m)[0];
callback(v);
}
});
}
}
so now if you call
getcrypt.php(function(returnVar){
alert(returnVar)
});
you will get an alert with VALUE
$.ajax returns immidiately (well, almost :)) upon calling, before the response is received. You should rewrite your code to accomodate to this fact, something like this;
var getcrypt = {
php: function(){
$.ajax({
//..other params ..//
success: function(msg){
var v = msg.match(/^.*$/m)[0];
alertResponse(v);
}
});
},
alertResponse: function(processedResponse) {
alert(v);
}
}
var test = {
al: function(){
getcrypt.php();
}
}
If you need your response in test object, you move alertResponse to that object and call it from success method. I think this tutorial might be useful for you to learn javascript event-driven programming model.
$.ajax calls are async. So what you get is the return value of $.ajax (when the request is sent, before a response is received). It is only when the browser receives a response to the ajax call that the success callback is run, as a seerate process from the $.ajax call. In other words the return value of $.ajax will always be null. I'm not sure it's possible to do anythging with the return value of the success callback, you need to put your logic (or a call to another function with the logic) in the success callback itself, in the same way you did with the alert in your final example
I have this php function inside a class the returns json data
function getPhotoDetails( $photoId ) {
$url = $this::APP_URL . 'media/' . $photoId . $this::APP_ID;
return $this->connectToApi($url);
}
and this ajax request
function getPhotoDetails( photoId ) {
$.ajax({
type: "GET",
cache: false,
url: 'index.php',
success: function (data) {
console.log(data);
}
});
}
The question is how I can call the php function to get the json data.
Solution:
A big thanks to all of you guys and thanks to Poonam
The right code
PHP:
I created a new object instance in php file
$photoDetail = new MyClass;
if(isset($_REQUEST['image_id'])){
$id = $_REQUEST['image_id'];
echo (($photoDetail->getPhotoDetails($id)));
}
JavaScript
function getPhotoDetails( photoId ) {
$.ajax({
type: "GET",
cache: false,
url: './instagram.php?image_id=' + photoId,
success: function (data) {
var data = $.parseJSON(data);
console.log(data);
}
});
}
Try with setting some parameter to identify that details needs to send for e.g assuming photoid params needed for function
function getPhotoDetails( photoId ) {
$.ajax({
type: "GET",
cache: false,
url: 'index.php?sendPhoto=1&photoid=23',
success: function (data) {
console.log(data);
}
});
}
and then on index.php check (You can make check for photoid whatever you need as per requirement)
if(isset($_REQUEST['sendPhoto'])){
$id = $_REQUEST['photoid'];
return getPhotoDetails($id);
}
setup a switch-case. Pass the function name as GET or POST variable such that it calls the php function
You need a file which calls the PHP function. You can't just call PHP functions from Ajax. And as pointed out by Tim G, it needs to use the proper header, format the code as JSON, and echo the return value (if the function is not already doing these things).