Multiple search value using dropdown list in PHP and MySQL - php

Question

Html Form:
<form>
<select name="country[]" id="country" multiple>
<option value="any">any</option>
<option value="India">India</option>
<option value="Canada">Canada</option>
<option value="UK">UK</option>
<option value="USA">USA</option>
<option value="Australia">Australia</option>
</select>
</form>
PHP Code
<?php
$country = $_REQUEST['country'];
if($country=="")
$countrysql = "";
else
{
if($country == "Any") $countrysql = "";
else
{
$country = str_replace(",","','",$country);
$countrysql = " and Country in ('$country')";
}
}
$queryString = "SELECT * FROM register where $countrysql";
?>
I have created a form in PHP and I want to search multiple options. I already created table Register and a column Country. I am getting the result If I give single value. If I give multiple I am not getting the result. Please help.

Answer 1

You evaluate in if($country == "Any") the word Any is not equal to any in option <option value="any">any</option>
But I suggest this php code:
<?php
$country="";
$countryError="";
if ($_SERVER["REQUEST_METHOD"] == "POST") {
if (empty($_POST["country"])){
$countryError = "Country is required";
}else{
$country = $_POST["country"];
}
if($country == "Any") {
$queryString = "SELECT * FROM register";
}else{
$queryString = "SELECT * FROM register where Country in ('$country')";
}
// Print the SQL string:
echo $queryString;
}
?>
The html tags:
<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
<select name="country" id="country" multiple>
<option value="Any">any</option>
<option value="India">India</option>
<option value="Canada">Canada</option>
<option value="UK">UK</option>
<option value="USA">USA</option>
<option value="Australia">Australia</option>
</select>
<input type="submit" name="submit" value="Submit">
</form>
<span class="error"><?php echo $countryError;?></span>