Generate a simple 2nd level dropdown menu with php and mysql - php

Question

I have a top_menu and a almenu named table. I want a simple dropdown menu by the menu id-s. The problem with this code, that it echo-s out the "Információk" menuitem 3 times, and puts into them the 3 menuitem from the almenu table.
The code does now: (It puts out 3 times the Információk menuitem from the top_menu table as new menuitems in the navbar)
Informáciok (Alapadatok), Informáciok (Kollégium), Informáciok (Osztályok)
And not: Informáciok (Alapadatok, Kollégium, Osztályok) (This is what i want)
<?php
$menu_sql =
"
SELECT
top_menu.top_menu_nev,
top_menu.top_menu_seo,
top_menu.top_menu_dropdown,
almenu.almenu_nev,
almenu.almenu_seo
FROM top_menu LEFT JOIN almenu ON top_menu.top_menu_id = almenu.almenu_parent
WHERE top_menu.menu_status = 1 AND top_menu.menu_position = 1
ORDER BY top_menu.top_menu_sorrend ASC
";
$get_menu = mysqli_query($kapcs, $menu_sql) or die(mysqli_error($kapcs));
while($top_menu = mysqli_fetch_assoc($get_menu))
{
if($top_menu['top_menu_dropdown'] == 0 )
{
echo '<li>'.$top_menu['top_menu_nev'].'</li>';
}
else
{
echo '<li class="dropdown">';
echo ''.$top_menu['top_menu_nev'].'';
echo '<ul class="dropdown-menu">';
echo '<li>'.$top_menu['almenu_nev'].'</li>';
echo '</ul>';
echo '</li>';
}
}
?>

Answer 1

The Problem is that you loop thru the whole nav over and over again.
The following code lets you generate new li items:
echo '<li class="dropdown">';
echo ''.$top_menu['top_menu_nev'].'';
echo '<ul class="dropdown-menu">';
$get_menu = mysqli_query($kapcs, $menu_sql) or die(mysqli_error($kapcs));
while($top_menu = mysqli_fetch_assoc($get_menu))
{
if($top_menu['top_menu_dropdown'] == 0 )
{
echo '<li>'.$top_menu['top_menu_nev'].'</li>';
}
else
{
echo '<li>'.$top_menu['almenu_nev'].'</li>';
}
}
echo '</ul>';
echo '</li>';