Ajax PHP Article Paginator - php

Question

I'm trying to find code to paginate a long post via Ajax and Php, e.g
My post has more than 2000 words, I would like to break the page into several pages with next& previous links with each page having 500 words. So in total 4 links should be displayed.
What I have gotten so far are plugins which paginate database records.
Any leads would be highly appreciated.

Answer 1

If you want to check how many characters are there in an article you can use a PHP strlen() function. Then if it's greater than 500 you can set up a new link with $_GET... I don't know that you have a database but I recommend it to save the article in a mysql database.
Code:
// This first query is just to get the total count of rows
$sql = "SELECT COUNT(id) FROM articles WHERE account_name=?"; // or you can use an strlen function here
$stmt = $conn->prepare($sql);
$stmt->bind_param("s",$u);
$stmt->execute();
$stmt->bind_result($rows);
$stmt->fetch();
$stmt->close();
// Here we have the total row count
// This is the number of results we want displayed per page
$page_rows = 10;
// This tells us the page number of our last page
$last = ceil($rows/$page_rows);
// This makes sure $last cannot be less than 1
if($last < 1){
$last = 1;
}
// Establish the $pagenum variable
$pagenum = 1;
// Get pagenum from URL vars if it is present, else it is = 1
if(isset($_GET['pn'])){
$pagenum = preg_replace('#[^0-9]#', '', $_GET['pn']);
}
// This makes sure the page number isn't below 1, or more than our $last page
if ($pagenum < 1) {
$pagenum = 1;
} else if ($pagenum > $last) {
$pagenum = $last;
}
// This sets the range of rows to query for the chosen $pagenum
$limit = 'LIMIT ' .($pagenum - 1) * $page_rows .',' .$page_rows;
// Establish the $paginationCtrls variable
$paginationCtrls = '';
// If there is more than 1 page worth of results
if($last != 1){
/* First we check if we are on page one. If we are then we don't need a link to
the previous page or the first page so we do nothing. If we aren't then we
generate links to the first page, and to the previous page. */
if ($pagenum > 1) {
$previous = $pagenum - 1;
$paginationCtrls .= 'Previous '; // here we set up the link
// Render clickable number links that should appear on the left of the target page number
for($i = $pagenum-4; $i < $pagenum; $i++){
if($i > 0){
$paginationCtrls .= ''.$i.' ';
}
}
}
// Render the target page number, but without it being a link
$paginationCtrls .= ''.$pagenum.' ';
// Render clickable number links that should appear on the right of the target page number
for($i = $pagenum+1; $i <= $last; $i++){
$paginationCtrls .= ''.$i.' ';
if($i >= $pagenum+4){
break;
}
}
// This does the same as above, only checking if we are on the last page, and then generating the "Next"
if ($pagenum != $last) {
$next = $pagenum + 1;
$paginationCtrls .= ' Next ';
}
}
Since I don't know what do you want exactly watch this video: pagination