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I have a string called $searchquery. $searchquery contains this SQL command:
SELECT * FROM `videos` WHERE (`Title` LIKE "%query%" OR `Tags` LIKE "%query%")
How can I make MySQL execute this command from a PHP page then display the results on PHP page??
I have tried
$sql = ($searchquery)
But dosent seem to work?
Firstly you need to create database connection
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "test";
$conn = mysqli_connect($servername, $username, $password, $dbname);
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
// then execute your query
$sql = "SELECT * FROM `videos` WHERE (`Title` LIKE '%query%' OR `Tags` LIKE '%query%')";
$result = mysqli_query($conn, $sql);
// and fetch result set
while($row = mysqli_fetch_assoc($result)) {
print_r($row);
}
?>
Related
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I am doing a project with PHP and MySQL. I have this problem.
This is my code
<?php
$proyecto = $_POST['id'];
$servername = "localhost";
$username = "dbuser";
$password = "dbpass";
$dbname = "proyectos";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT `horas`, `trabajador` FROM `horas` WHERE `proyecto` LIKE '$proyecto' ";
$result = $conn->query($sql);
$conn->close();
?>
It takes a parameter from a post request and do a search in the database database looks like this:
So I want to get as result the sum of all the hours (horas column) that are made by the same worker (trabajador column). Example of result:
Prueba1: 8 hours in total, Prueba2: 9 hours in total
I am stuck trying to dinf they way to sum when 1 or more fields must be the same, I hope someone can help me with this. Thanks!
You must use sum function to add the number of hours for each worker along with GROUP BY clause to group workers.Formatted Query is like:
SELECT SUM(horas) AS Hours,`trabajador`
FROM `horas`
WHERE `proyecto`
LIKE '%".$proyecto."%'
GROUP BY `trabajador`
In your code,
$select = "
SELECT SUM(horas) AS Hours, `trabajador`
FROM `horas`
WHERE `proyecto` LIKE ?
GROUP BY `trabajador`
";
$sth = $conn->prepare($select);
$sth->execute(['%'.$proyecto.'%']);
/* Fetch all of the remaining rows in the result set */
print("Fetch all rows in the result set:\n");
$result = $sth->fetchAll(\PDO::FETCH_ASSOC);
print_r($result);
Note: You better switch to MYSQL prepared statements to keep your data secure and for better database connectivity practices.
Note answer by maniksidana explains how to use SUM() and GROUP BY and is in general valid. However, it mixes mysqli and PDO approches. Here you have sample how to use it with mysqli (as your question uses it) and why it's important to use prepared statements at all. Just add some dummy data to your table end execute it. Personally I'd suggest to go with PDO only instead, but it's matter of taste.
INSERT INTO `horas` (`fecha`, `horas`, `proyecto`, `trabajador`) VALUES
('2020-08-08', 3, 'foo bar baz', 'Joker1'),
('2020-08-09', 4, 'ello pomello', 'Joker2');
<?php
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$proyecto = "ProyectpDePrueba'; DELETE FROM horas WHERE 1; -- bye bye data";
$proyecto = "ProyectpDePrueba";
$proyecto = "ProyectpDePrueba' OR 1=1 -- no more execution";
// Wrong
$sql = "
SELECT SUM(horas) AS Hours, `trabajador`
FROM `horas`
WHERE `proyecto` LIKE '$proyecto'
GROUP BY `trabajador`
";
$result = $conn->query($sql);
echo '<pre>Wrong' . PHP_EOL;
while ($row = mysqli_fetch_assoc($result)) {
print_r($row);
}
// Correct
$sql = "
SELECT SUM(horas) AS Hours, `trabajador`
FROM `horas`
WHERE `proyecto` LIKE ?
GROUP BY `trabajador`
";
$stmt = $conn->prepare($sql);
$stmt->bind_param('s', $proyecto);
$stmt->execute();
$result = $stmt->get_result();
echo PHP_EOL . 'Corrcet' . PHP_EOL;
while ($row = $result->fetch_assoc()) {
print_r($row);
}
$conn->close();
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here's a part of my code that AFTER you submit your login credentials checks your username, password, etc...:
mysql_select_db("robur_mike") or die ("Could not find DB!");
$query = mysql_query("SELECT * FROM Bx1_Users WHERE Username='$username'");
$numrows = mysql_num_rows($query);
if ($numrows!=0)
{
while ($row =mysql_fetch_assoc($query))
{
$dbusername = $row['Username'];
$dbpassword = $row['Password'];
$dbfirstname = $row['FirstName'];
$dblastname = $row['LastName'];
}
.....
I now need to "translate" that to run under a DB2 database in BlueMix. I am already connected to the database using the code provided here:
How to connect to a SQL Database-s2 from a .php application in BlueMix
The query should be OK since it is basic SQL. What you should change is the way you run it, since in your old code you are using the mysql library.
Looking at the other question, I assume that you are able to connect doing something like:
$conn = db2_connect($conn_string, '', '');
Now to execute the query you can use db2_exec 'translating' your code to something like:
$sql = "SELECT * FROM <schemaName>.Bx1_Users WHERE Username='$username'";
if ($conn) {
$stmt = db2_exec($conn, $sql, array('cursor' => DB2_SCROLLABLE));
while ($row = db2_fetch_assoc($stmt)) {
$dbusername = $row['Username'];
$dbpassword = $row['Password'];
$dbfirstname = $row['FirstName'];
$dblastname = $row['LastName'];
}
}
db2_close($conn);
As you can see I've added a placeholder for the schema name in the SQL query. You can retrieve it within your SQL Database dashboard (Manage/Work with tables).
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I have a table called "users" which has columns 'username', 'password' and 'permission'. In the permission column is either 'browse' or 'edit'.
Say I have a user logged into my site, I want to select select their permission using their username (which I have stored in a session variable). I want to then set a variable equal to either 'browse' or 'edit' based on their permission, to then use in further logic.
Assuming I have connected to and selected the appropriate database I am pretty sure the php code and query should go something like:
$u = $_SESSION['username'] ;
$sql = "SELECT permission FROM users WHERE username = '$u' " ;
$result = mysqli_query($sql);
But Im unsure how to then set a variable equal to 'browse' or 'edit' accordingly.
Any ideas?
Say you have a connection $con, for using session you have to start your session.
$u = $_SESSION['username'] ;
$sql = "SELECT `permission` FROM `users` WHERE username='$u'";
$result = mysqli_query($con, $sql);
$rows = mysqli_fetch_object($result);
//now its time to set the permission to the variable
echo $permission = $rows->permission;
mysqli_close($con);
you can also set the $permission to a $_SESSION.
$_SESSION['permission'] = $permission;
You have to do it like this:
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$u = $_SESSION['username'] ;
$sql = "SELECT `permission` FROM `users` WHERE username='$u'";
$result = mysqli_query($conn, $sql);
$rows = mysqli_fetch_object($result);
//now its time to set the permission to the variable
echo $permission = $rows->permission;
mysqli_close($conn);
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I try to learn mysql an have a problem with a sql query.
i made a database connection with mysqli
the php script create a table code_scanned in database.
Creating the Table works very good!
But my second query to fill the table wont work :(
If i paste the query manually to phpadmin it works.
But not in my php script.
Can please anyone have a look on my code, what i do wrong.
$servername = "xxxxxxx";
$username = "xxxxxx";
$password = "xxxxxx";
$dbname = "xxxxxx";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
// sql to create table
$sql = "CREATE TABLE IF NOT EXISTS code_scanned (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
produkt VARCHAR(50) NOT NULL,
code VARCHAR(30) NOT NULL
)";
if ($conn->query($sql) === TRUE) {
echo "code_scanned erstellt";
} else {
echo "Fehler" . $conn->error;
}
$sql = "INSERT INTO code_scanned (produkt, code) VALUES ('gates', 'Microsoft')";
$conn->close();
Exexute the insert query :
And correct The code:
$sql = "INSERT INTO code_scanned (produkt, code) VALUES ('gates', 'Microsoft')";
$result= mysqli_query($conn,$sql);
if($result)
{
echo "Insert sucessfully";
}
else
{
echo("Sorry:".mysqli_errno($conn));
}
$conn->close();
You are not running the second query. Put this below the line that has $sql = "INSERT...."
$conn->query($sql);
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So I'm working on a website that has a list of novels in a database with some basic info about them. I'd like to make a table of the most recent additions to the database. I'm using PHP and SQL and this is what I've got so far.
<?php
$servername = "localhost";
$username = "root";
$password = "password";
$database = "novels";
// Create connection
$conn = new mysqli($servername, $username, $password, $database);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
// Select ten most recent entries
SELECT `N_ID`, `NAME`, `DATE_RELEASED`, `GENRES` FROM basic_info ORDER BY N_ID DESC LIMIT 10
?>
I"m new to PHP And SQL so what I can gather is that I've made a connection to the database and have pulled the information from the latest 10 entries. Now I'm just not sure how to print them.
Any help is appreciated!
Try to use PDO if you can. Also you could use lower case for your columns to avoid case sensitivity issues.
You have to "wrap" your SELECT query in a variable (e.g. $sql) to be able to pass it in your php code.
error_reporting(E_ALL);
ini_set("display_errors", 1);
$servername = "localhost";
$username = "root";
$password = "password";
$database = "novels";
try {
//Make your connection handler to your database
$conn = new PDO("mysql:host=".$servername.";dbname=".$database, $username, $password, array(PDO::ATTR_ERRMODE => PDO::ERRMODE_WARNING));
$sql = "SELECT `N_ID`, `NAME`, `DATE_RELEASED`, `GENRES` FROM basic_info ORDER BY N_ID DESC LIMIT 10";
$stmt = $conn->prepare($sql);
//Execute the query
$stmt->execute();
$result = $stmt->fetchAll();
//Fetch the results
foreach ($result as $row) {
echo '<p>'.$row['NAME'].'</p>';
}
} catch(PDOException $e) {
echo $e->getMessage();
die();
}