warning illegal string offset while fetching result from database - php

Question

I am using the following code to find the data from database
echo $query = "select * from `oc_order` where `store_url`='' ORDER BY `order_id` DESC LIMIT 5";
$mysqlq = mysqli_query($connection,$query) or die(mysqli_error($connection));
$mysqlw = mysqli_fetch_array($mysqlq);
echo "<pre>";
print_r($mysqlw);
foreach($mysqlw as $mysqlw)
{
echo $mysqlw['telephone'];
}
?>
I am getting the following array
Array
(
[0] => 73
[order_id] => 73
[1] => 0
[invoice_no] => 0
[2] =>
[invoice_prefix] =>
[3] => 0
[store_id] => 0
[4] =>
[store_name] =>
[5] =>
[store_url] =>
[6] => 9
[customer_id] => 9
[7] => 1
[customer_group_id] => 1
[8] => T****
[firstname] => ****
[9] =>
[lastname] =>
[10] => ********
[email] => *******
[11] => *****
[telephone] => *****
[12] =>
[fax] =>
[13] => 364ce6e2003bb1404f34
[custom_field] => 364ce6e2003bb1404f34
[14] =>
[payment_firstname] =>
[15] =>
[payment_lastname] =>
[16] =>
[payment_company] =>
[17] =>
[payment_address_1] =>
[18] =>
[payment_address_2] =>
[19] =>
[payment_city] =>
[20] =>
[payment_postcode] =>
[21] =>
[payment_country] =>
[22] => 0
[payment_country_id] => 0
[23] =>
[payment_zone] =>
[24] => 0
[payment_zone_id] => 0
[25] =>
[payment_address_format] =>
[26] =>
[payment_custom_field] =>
[27] =>
[payment_method] =>
[28] =>
[payment_code] =>
[29] =>
[shipping_firstname] =>
[30] =>
[shipping_lastname] =>
[31] =>
[shipping_company] =>
[32] =>
[shipping_address_1] =>
[33] =>
[shipping_address_2] =>
[34] =>
[shipping_city] =>
[35] =>
[shipping_postcode] =>
[36] =>
[shipping_country] =>
[37] => 0
[shipping_country_id] => 0
[38] =>
[shipping_zone] =>
[39] => 0
[shipping_zone_id] => 0
[40] =>
[shipping_address_format] =>
[41] =>
[shipping_custom_field] =>
[42] =>
[shipping_method] =>
[43] =>
[shipping_code] =>
[44] => 1,19
[comment] => 1,19
[45] => 100.0000
[total] => 100.0000
[46] => 0
[order_status_id] => 0
[47] => 0
[affiliate_id] => 0
[48] => 0.0000
[commission] => 0.0000
[49] => 0
[marketing_id] => 0
[50] =>
[tracking] =>
[51] => 0
[language_id] => 0
[52] => 0
[currency_id] => 0
[53] => INR
[currency_code] => INR
[54] => 1.00000000
[currency_value] => 1.00000000
[55] =>
[ip] =>
[56] =>
[forwarded_ip] =>
[57] =>
[user_agent] =>
[58] =>
[accept_language] =>
[59] => 0000-00-00 00:00:00
[date_added] => 0000-00-00 00:00:00
[60] => 0000-00-00 00:00:00
[date_modified] => 0000-00-00 00:00:00
)
but when i am trying to print the value of echo $mysqlw['telephone']; it is throwing warning Warning: Illegal string offset 'telephone' in
What mistake I am making in this code ?

Answer 1

You are trying to do a foreach on the array that you've displayed in your post. That means you're cycling through each item in the array. By trying to access $mysqlw['telephone'] you're expecting the item in the array to be another array containing the key 'telephone'.
I believe you're intending to do this:
while ($mysqlw = mysqli_fetch_array($mysqlq) {
echo $mysqlw['telephone'];
}
But also, you really should read up on how to do MySQL in a more modern style. Using things like mysqli_query in the manner you've used it here can open you up to injection attacks when you start having user input involved in the query.

Answer 2

Note your foreach statement has same variable name on both sides of 'as'
foreach($mysqlw as $mysqlw)
If you want to loop and access each value of an array do this instead:
foreach($mysqlw as $value)
{
echo $value;
}