Getting the field of an object - php

Question

I have objects like below
{
"user": "58a9bf92e0f78000055dd932",
"type": "template_created",
"count": 2
}
I need to get 'user' field, ..->type returns "template_created" and ..->count gives its value but ..->user returns null. These objects come from mongodb aggregation framework by the way.

Answer 1

Use this code
$data = json_decode($data); //where $data contain the json
$data->user;

Answer 2

It looks, like your objects are json-encoded. This means, you can use the native php functions json_encode() and json_decode() to process them. In your example, you can deserialize the object by calling
$obj = json_decode($str);
with $str being the data you show above. Now you can access the fields of this object with standard php access methods like
$type = $obj->type;
Hope this helps!

Answer 3

Don't forget to check errors after json_decode, like this:
$payload = json_decode($data);
if (json_last_error() !== JSON_ERROR_NONE) {
throw new RuntimeException('Invalid JSON.');
}
// also you cah check this
if (property_exists($payload, 'user')) {
var_export($payload->user);
}

Answer 4

You can resolve with two ways :-
$data = '{
"user": "58a9bf92e0f78000055dd932",
"type": "template_created",
"count": 2
}';
$objectdata = json_decode($data); //stclassobject
echo $objectdata->count;
--------OR-------
$arraydata= json_decode($data,true); //convert to array
echo $arraydata['count'];
Hope it hepls!