I am using the GAPI class (gapi.class.php) for Google Analytics API.
This is the code:
<?php
require 'gapi.class.php';
define('ga_profile_id', 'your profile id');
$ga = new gapi("XXXXXXXX#developer.gserviceaccount.com", "key.p12");
$filter = 'country == United States && browser == Firefox || browser == Chrome';
$ga->requestReportData(ga_profile_id, array('browser', 'browserVersion'), array('pageviews', 'visits'), '-visits', $filter);
?>
<table>
<tr>
<th>Browser & Browser Version</th>
<th>Pageviews</th>
<th>Visits</th>
</tr>
<?php
foreach($ga->getResults() as $result):
?>
<tr>
<td><?php echo $result ?></td>
<td><?php echo $result->getPageviews() ?></td>
<td><?php echo $result->getVisits() ?></td>
</tr>
<?php
endforeach
?>
</table>
<table>
<tr>
<th>Total Results</th>
<td><?php echo $ga->getTotalResults() ?></td>
</tr>
<tr>
<th>Total Pageviews</th>
<td><?php echo $ga->getPageviews() ?>
</tr>
<tr>
<th>Total Visits</th>
<td><?php echo $ga->getVisits() ?></td>
</tr>
<tr>
<th>Result Date Range</th>
<td><?php echo $ga->getStartDate() ?> to <?php echo $ga->getEndDate() ?></td>
</tr>
</table>
But I can't find how to change the date ranges.
By default, it's showing the status from 2014 to today — I think it's the life of the analytics account.
There is a similar question but it's for an older version, which is not working now.
Thank you.
Ok this worked
$start_date = ("2017-11-01");
$end_date = ("today");
$ga->requestReportData(ga_profile_id, array('browser', 'browserVersion'), array('pageviews', 'visits'), '-visits', $filter,$start_date,$end_date);
Related
I have a table for saving details including logging time.Just as soon as a new record is inserted I want the column 'Countdown' to start an automatic time countdown from 30min until it gets to zero(0).How do I go about it?Thanks.
Here is the table php code
`<?php $results = mysqli_query($db, "SELECT
Vehicle_name,Vehicle_make,Vehicle_color,Number_plate,Date,Time FROM
vehicle"); ?>
<div class="table">
<table>
<thead>
<tr>
<th>Vehicle name</th>
<th>Vehicle make</th>
<th>Vehicle color</th>
<th>Reg Number</th>
<th>Date</th>
<th>Time</th>
<th>Countdown</th>
<th colspan="4">Action</th>
</tr>
</thead>
<?php while ($row = mysqli_fetch_array($results)) { ?>
<tr>
<td><?php echo $row['Vehicle_name']; ?></td>
<td><?php echo $row['Vehicle_make']; ?></td>
<td><?php echo $row['Vehicle_color']; ?></td>
<td><?php echo $row['Number_plate']; ?></td>
<td><?php echo $row['Date']; ?></td>
<td><?php echo $row['Time']; ?></td>
<td><?php echo $row['Time']; ?></td>
<td>
<a href="php_code.php?del=<?php echo $row['Number_plate']; ?>"
class="del_btn">Delete</a>
</td>
</tr>
<?php } ?>
`
I am creating a table that fetches data from an SQL database using a PDO method. The data loads fine but the issue I'm having is that the 'for loop' I'm using is multiplying a (table header) after every (table row).
I am wondering what a possible solution the the issue could be.
Any help is appreciated, thanks!
Here is the code:
<?php
for($i=0; $row = $result->fetch(); $i++){
?>
<table id="eventstable">
<tr>
<th>Event ID</th>
<th>Event Name</th>
<th>Location</th>
<th>Date</th>
</tr>
<tr>
<td><?php echo $row['event_id']; ?></td>
<td><?php echo $row['event_name']; ?></td>
<td><?php echo $row['event_location']; ?></td>
<td><?php echo $row['event_date']; ?></td>
</tr>
</table>
<?php }
?>
Up at the very top is the connection file that creates a connection to my local database and a statement that brings in the information I want to display from the database like so:
$result = $conn->prepare("SELECT * FROM events");
$result->execute();
Few possible solutions are
i) Put the header part and the table opening and closing tag outside the for loop. This will give you an empty table with headers if there is no data.
ii) Put an if condition and print headers only when i = 0, and put table tags outside the loop. This will give you an empty table with nothing if there is no data.
Edit: Method II (since you are learning)
<table id="eventstable">
<?php
for($i=0; $row = $result->fetch(); $i++){
if($i == 0){
?>
<tr>
<th>Event ID</th>
<th>Event Name</th>
<th>Location</th>
<th>Date</th>
</tr>
<?php }//if statment ends here ?>
<tr>
<td><?php echo $row['event_id']; ?></td>
<td><?php echo $row['event_name']; ?></td>
<td><?php echo $row['event_location']; ?></td>
<td><?php echo $row['event_date']; ?></td>
</tr>
<?php }
?>
I would also suggest since you are learning, use better ways than for loop. Look at the php PDO manuals and see the use of while or foreach. It will help more.
Put in loop only, what should be looped, everything else should be outside of loop.
For example, your code could look like this
<table id="eventstable">
<tr>
<th>Event ID</th>
<th>Event Name</th>
<th>Location</th>
<th>Date</th>
</tr>
<?php
for($i=0; $row = $result->fetch(); $i++){
?>
<tr>
<td><?php echo $row['event_id']; ?></td>
<td><?php echo $row['event_name']; ?></td>
<td><?php echo $row['event_location']; ?></td>
<td><?php echo $row['event_date']; ?></td>
</tr>
<?php
}
?>
</table>
try this :
<table id="eventstable">
<tr>
<th>Event ID</th>
<th>Event Name</th>
<th>Location</th>
<th>Date</th>
</tr>
<?php
foreach($result->fetch() as $row){
?>
<tr>
<td><?php echo $row['event_id']; ?></td>
<td><?php echo $row['event_name']; ?></td>
<td><?php echo $row['event_location']; ?></td>
<td><?php echo $row['event_date']; ?></td>
</tr>
<?php }
?>
</table>
I wrote code to retrieve data from database and to print in form of tables on my web. I have stored 4 columns of data in my database but while retrieving it's only showing one column.
My database image
My webpage
My code:
<?php
$con = mysqli_connect("localhost", "root", "", "project");
if(!$con)
{
die('not connected');
}
$result= mysqli_query($con, "SELECT name, stay, food, travel,
SUM(stay + food + travel) AS totalamount,doj
FROM placedetails ");
?>
<div class="container">
<table class="table table-hover">
<thead>
<tr>
<th>place</th>
<th>stay cost</th>
<th>food cost</th>
<th>flight cost</th>
<th>Date of journey</th>
<th>Total cost</th>
</tr>
</thead>
<?php
while($row =mysqli_fetch_array($result))
{
?>
<tbody>
<tr>
<td><?php echo $row['name']; ?></td>
<td><?php echo $row['stay']; ?></td>
<td><?php echo $row['food'] ;?></td>
<td><?php echo $row['travel'] ;?></td>
<td><?php echo $row['doj'] ;?></td>
<td><?php echo $row['totalamount'] ;?></td>
</tr>
</tbody>
<?php
}
?>
</table>
</div>
</div>
Can anyone can tell where the mistake is?
And one more question: I want to diplay only the recent uploaded data on my web page. Suppose I have 4 names as mumbai, but uploaded at different times, I want to display the most recently added mumbai name on my web page
Can anyone help me out in this matter? I will be very thankful..
update your code as move tbody from php loop
<div class="container">
<table class="table table-hover">
<thead>
<tr>
<th>place</th>
<th>stay cost</th>
<th>food cost</th>
<th>flight cost</th>
<th>Date of journey</th>
<th>Total cost</th>
</tr>
</thead>
<tbody>
<?php
while($row = mysqli_fetch_assoc($result))
{
?>
<tr>
<td><?php echo $row['name']; ?></td>
<td><?php echo $row['stay']; ?></td>
<td><?php echo $row['food'] ;?></td>
<td><?php echo $row['travel'] ;?></td>
<td><?php echo $row['doj'] ;?></td>
<td><?php echo $row['totalamount'] ;?></td>
</tr>
<?php
}
?>
</tbody>
</table>
</div>
1) <tbody> should be outside of while loop
2) if you want show only one record means no need to use while loop
3) if you want show recent record means just do descending sort by date column or id column
Query :
SELECT name, stay, food, travel, SUM(stay + food + travel) AS totalamount,doj FROM placedetails order by doj desc limit 1;
Table :
<tbody>
<?php
$row = mysqli_fetch_assoc($result); //fetch first record set only
?>
<tr>
<td><?php echo $row['name']; ?></td>
<td><?php echo $row['stay']; ?></td>
<td><?php echo $row['food']; ?></td>
<td><?php echo $row['travel']; ?></td>
<td><?php echo $row['doj']; ?></td>
<td><?php echo $row['totalamount'];?></td>
</tr>
</tbody>
I am working on a xml to table project which would use PHP.
<? $xml = new SimpleXMLElement('http://example.com/genXML.php?product=388', 0, TRUE);
?>
<table>
<thead>
<tr>
<th>Symbol</th>
<th>Name</th>
<th>Price</th>
<th>Change</th>
<th>Percentage</th>
<th>High</th>
<th>Low</th>
</tr>
</thead>
<tbody>
<?php foreach ($xml->product as $check) :?>
<tr>
<td><?php echo $check->symbol; ?></td>
<td><?php echo $check->name->chinese; ?></td>
<td><?php echo $check->price; ?></td>
<td><?php echo $check->change; ?></td>
<td><?php echo $check->pct_change; ?></td>
<td><?php echo $check->high; ?></td>
<td><?php echo $check->low; ?></td>
</tr>
<?php endforeach; ?>
</tbody>
</table>
As product will have their own unique code, I would like the programe to show all the details in one table.
Is it possible to use MYSQL Database to store the product code that i need to ref. and show them out on a single web page? Thanks!
I am new to GAPI.. I want to find top 10 pages of site using GAPI for both mobile devices and desktop.. I coded up to this..
<?php
define('ga_email','xxxxxxxxxxxxxx#gmail.com');
define('ga_password','xxxxxxxxxxxxxxx');
define('ga_profile_id','xxxxxxxxxxx');
require 'gapi.class.php';
$ga = new gapi(ga_email,ga_password);
$ga->requestReportData(ga_profile_id,array('browser','browserVersion'),array('pageviews','visits'));
//echo '<pre>';print_r($ga->getResults());exit;
?>
<table>
<tr>
<th>Browser & Browser Version</th>
<th>Pageviews</th>
<th>Visits</th>
</tr>
<?php
foreach($ga->getResults() as $result):
?>
<tr>
<td><?php echo $result ?></td>
<td><?php echo $result->getPageviews() ?></td>
<td><?php echo $result->getVisits() ?></td>
</tr>
<?php
endforeach
?>