IF condition not working in UPDATE query - php

In this code when I want to update the status from Pending to Accepted that time If statement not working.
In database I keep Pending by default. Problem is that when I'm going to update the status the STATUS will update but the code inside the If condition can't work.
please help me out from this problem.
Thanks in advance.
<?php
include("connect.php");//conection
if(isset($_REQUEST['leave_id']))
{
$id=$_REQUEST['leave_id'];
}
else
{
$id=NULL;
}
$result = mysqli_query($con,"SELECT TAKEN_LEAVES,BALANCE_LEAVE,STATUS
FROM xxxemi_person_leave_t
WHERE leave_id= $id");
$res = mysqli_fetch_array($result);
if (!$result)
{
die("Error: Data not found..");
}
$taken_leave = $res['TAKEN_LEAVES'];
$balance_leave = $res['BALANCE_LEAVE'];
$status = $res['STATUS'];
if(isset($_POST['save']))
{
if ($status=='ACCEPTED')
{
$status = $_POST['USTATUS'];
$updated_balance_leave = $_POST['UBALANCE_LEAVE'];
$updated_balance_leave = $balance_leave - $taken_leave;
mysqli_query($con,"UPDATE xxxemi_person_leave_t
SET STATUS ='$status', BALANCE_LEAVE ='$updated_balance_leave'
WHERE leave_id = '$id' ");
echo "<script>alert('Your Record Updated');</script>";
}
else
{
$status = $_POST['USTATUS'];
mysqli_query($con,"UPDATE xxxemi_person_leave_t
SET STATUS ='$status'
WHERE leave_id = '$id' ");
echo "<script>alert('Your Record Updated');</script>";
}
}
mysqli_close($con);
?>
/**************PHP CODE *******/
<form method="post">
<td><input type="hidden" name="id" value=<?php echo $_GET['leave_id'];?>>
<input type="hidden" name="UBALANCE_LEAVE" value="<?php echo $updated_balance_leave;?>">
<input type="checkbox" name="USTATUS" value="ACCEPTED" />
<img src="images/Approved.png" />
<input type="checkbox" name="USTATUS" value="REJECTED" />
<img src="images/Rejected.png" /></td>
<input type="submit" name="save" value="Update">
</form>
/************* HTML CODE**********/

It seems that ,you are using $statu = $res['STATUS']; // STATUS
$statu for STATUS, but in if condition you are checking for $status
Change This
if ($status=='ACCEPTED')
To
if($_POST['USTATUS']=='ACCEPTED')
AND type="checkbox" TO type="radio"

Related

PHP - Undefined index : id - the value is not retrieved

Yes, I know there is a lot of 'Undefined index' questions floating around here and i have been looking through them before asking this question. I copied the codes from those questions to try and test it out but it still doesn't work for my own project. Also, I'm still a beginner in PHP.
So here is my problem. I wanted to try coding a simple edit form after I have finished coding the delete and view form.
This is my code
<?php
require("config.php");
$id = $_GET['id'];
echo "id: ".$id;
$sql = "SELECT * FROM contracts WHERE id= '$id'";
$result = $con->query($sql);
$row = $result->fetch_assoc()
?>
<form action="editform.php" method="GET">
ID:
<?php echo $id; ?><br>
Contract Title<br>
<input type="text" name="contract_title" value="<?php echo $row['contract_title']; ?>" /><br>
<input type="submit" name = "edit "value="Update" />
</form>
?php
if(isset($_POST['edit']) ){
$id = $_GET['id'];
$upd= "UPDATE `contracts` SET
`contract_title`='".$_POST['contract_title']."',
WHERE `id`='".$_POST['id']."";
if($do_upd = $con->query($upd))
{
echo "Update Success";
}
else
{
echo "Update Fail";
}
}
?>
This is the before the error.
This is the error I received.
In line 3, the id is not retrieved after I clicked the button update.
It didn't retrieved the values.
What mistakes did I do in the coding and how do I fix it? Thanks in advance.
Right below:
<form action="editform.php" method="GET">
Add:
<input type="hidden" name="id" value="<?php echo $id; ?>" />
Update:
Fixed other errors in your code:
<?php
require("config.php");
$id = $_GET['id'];
echo "id: ".$id;
$sql = "SELECT * FROM contracts WHERE id= '$id'";
$result = $con->query($sql);
$row = $result->fetch_assoc()
?>
<form action="editform.php" method="GET">
ID: <?php echo $id; ?><br>
Contract Title<br>
<input type="hidden" name="id" value="<?php echo $id; ?>" />
<input type="text" name="contract_title" value="<?php echo $row['contract_title']; ?>" /><br>
<input type="submit" name="edit" value="Update" />
</form>
<?php
if(isset($_GET['edit']) ){
// needs escaping!~~~
$upd= "UPDATE `contracts` SET `contract_title` = '".$_GET['contract_title']."' WHERE `id` = '".$id;
if($do_upd = $con->query($upd)) {
echo "Update Success";
} else {
echo "Update Fail";
}
}
Please consider escaping your database input to prevent SQL injection
<?php
require("config.php");
$id = $_GET['id'];
echo "id: ".$id;
$sql = "SELECT * FROM contracts WHERE id= '$id'";
$result = $con->query($sql);
$row = $result->fetch_assoc()
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$contract_title = $row['contract_title'];
}
} else {
echo "0 results";
}
if(isset($_POST['edit']) ){
$upd = "UPDATE contracts SET contract_title='$contract_title' WHERE id='$id'";
if($do_upd = $con->query($upd))
{
echo "Update Success";
}
else
{
echo "Update Fail";
}
}
?>
<form action="" method="POST">
ID:
<?php echo $id; ?><br>
Contract Title<br>
<input type="text" name="contract_title" value="<?php echo $row['contract_title']; ?>" /><br>
<input type="submit" name = "edit" value="Update" />
</form>

How do I run multiple SQL Queries using "if(isset($_POST['Submit'])){"

Trying to make a CRUD, everything works except my Update function. I feel like the problem is in the second sql query. When I click on submit it just refreshes and the change is gone. Can anyone show me how to find what I need to change/show me what to change?
<head>
<title>Update</title>
</head>
<body>
</form>
<?php
require_once('dbconnect.php');
$id = $_GET['id'];
$sql = "SELECT * FROM dealers where ID=$id";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo '<form action="" method="post">';
echo "Company: <input type=\"text\" name=\"CName\" value=\"".$row['CName']."\"></input>";
echo "<br>";
echo "Contact: <input type=\"text\" name=\"Contact\" value=\"".$row['Contact']."\"></input>";
echo "<br>";
echo "City: <input type=\"text\" name=\"City\" value=\"".$row['City']."\"></input>";
echo "<br>";
echo "<input type=\"Submit\" = \"Submit\" type = \"Submit\" id = \"Submit\" value = \"Submit\">";
echo "</form>";
}
echo "</table>";
} else {
echo "0 results";
}
if(isset($_POST['Submit'])){
$sql = "UPDATE dealers SET CName='$CName', Contact='$Contact', City='$City' where ID=$id";
$result = $conn->query($sql);
}
$conn->close();
?>
Instead of building a form inside PHP, just break with ending PHP tag inside your while loop and write your HTML in a clean way then start PHP again. So you don't make any mistake.
Also you've to submit your $id from your form too.
Try this
<?php
require_once('dbconnect.php');
$id = $_GET['id'];
$sql = "SELECT * FROM dealers where ID=$id";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
?>
<form action="" method="post">
<input type="hidden" name="id" value="<?= $id ?>" />
Company: <input type="text" name="CName" value="<?= $row['CName'] ?>" />
<br>
Contact: <input type="text" name="Contact" value="<?= $row['Contact'] ?>" />
<br>
City: <input type="text" name="City" value="<?= $row['City'] ?>" />
<br>
<input type="Submit" name="Submit" id="Submit" value="Submit" />
</form>
<?php
} // end while loop
echo "</table>";
}
else {
echo "0 results";
}
Note: You are passing undefined variables into your update query. As you are submitting your form you must have to define those variables before you use them.
if (isset($_POST['Submit'])) {
$CName = $_POST['CName'];
$Contact = $_POST['Contact'];
$City = $_POST['City'];
$id = $_POST['id'];
$sql = "UPDATE dealers SET CName='$CName', Contact='$Contact', City='$City' where ID=$id";
$result = $conn->query($sql);
}
$conn->close();
that loop? ID primary key or not?
maybe u need create more key in table dealer like as_id
<input type="hidden" name="idform" value="$as_id">
in statment
if($_POST){
$idf = $_POST['idform'];
if(!empty($idf)){
$sql = "UPDATE dealers SET CName='$CName', Contact='$Contact', City='$City' where as_id=$idf";
$result = $conn->query($sql);
}
$conn->close();
}

PHP - Can't update information from table

I can't change the information from my database.
I'm trying to update information from my database. But it's not working.
The user just need to put one existing ID from the table, and it will update the information from the specific column, in this case, it's a column called "titulo".
Here my page code:
<?php
if(isset ($_POST['submit']))
{
include("../classes/administrador/Administrador.class.php");
$Administrador = new Administrador();
if ($Administrador->atualizarCD($_REQUEST['id'],$_REQUEST['titulo']))
{
echo "It works !!!<br>";
} else {
echo "its not working<br>";
}
$Administrador->endAdministrador();
}
else{
?>
<b>Alterar CD</b><br><br>
<form name="form3" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<b>ID</b>:
<input type="text" name="id" size="3">
<br>
<br>
<b>Titulo</b>:
<input type="text" name="titulo">
<br>
<input type="submit" name="submit" value="submit">
</form>
<p> </p>
<?php
}
?>
And my function code:
function atualizarCD($id, $titulo) {
$sql= "UPDATE `cds` SET `titulo` = '$titulo' WHERE `ID` = '$id";
if($this->bd->executarSQL($sql)) return true;
else return false;
}
You have missed to add ' end of the query
$sql= "UPDATE `cds` SET `titulo` = '$titulo' WHERE `ID` = '$id' ";

PHP Form update will not update

I have written an Edit part of my Form but somehow it will not Update the edited Fields. The Code does not give any Errors but it will not update?!
If possible could somebody take a look please?
<?php
include "connect.php";//database connection
if (isset($_GET["id"])) {
$id = intval($_GET["id"]);
if (isset($_POST["edited"]))
{
$update = "UPDATE traumprojekt SET";
$update .= sprintf("quantityProduct='%s', " , mysql_real_escape_string($_POST["quantityProduct"]));
$update .= sprintf("titleProduct='%s', " , mysql_real_escape_string($_POST["titleProduct"]));
$update .= sprintf("informationProduct='%s'", mysql_real_escape_string($_POST["informationProduct"]));
$update .= "WHERE id = '$id'";
mysql_query($update);
}
$sql = "SELECT * FROM `traumprojekt` WHERE id=$id";
$res = mysql_query($sql) or die (mysql_error());
if (mysql_num_rows($res) == 1)
{
$row = mysql_fetch_assoc($res);
?>
<form method="post" action="edit_form.php?id=<?php echo $row["id"] ?>">
ID: <?php echo $row["id"] ?><br />
Quantity: <input type="text" name="quantityProduct" value="<?php echo $row["quantityProduct"] ?>"><br />
Product Title: <input type="text" name="titleProduct" value="<?php echo $row["titleProduct"] ?>"><br />
Product Information: <input type="text" name="informationProduct" value="<?php echo $row["informationProduct"] ?>"><br />
<input type="submit" name="submit" value="Update"><br />
<input type="hidden" name="edited" value="1">
</form>
<?php
}
}
?>

Unable to edit mysql row using form

I am trying to create a form that will edit rows from my db table. (Based on some code I got from a StackOverflow page.)
I am able to populate the form with relevant data, but when I submit the form, the row isn't updated. In fact, some of my columns are deleted.
What did I do wrong?
edit.php
<?php
$UID = (int)$_GET['f'];
$query = mysql_query("SELECT * FROM user_feeds WHERE feed_id = '$UID'") or die(mysql_error());
if(mysql_num_rows($query)>=1){
while($row = mysql_fetch_array($query)) {
$feedtitle = $row['feed_title'];
$feedurl = $row['feed_url'];
$feedorder = $row['feed_order'];
$feedowner = $row['feed_owner'];
}
?>
<form action="update.php" method="post">
<input type="hidden" name="ID" value="<?=$UID;?>">
Title:<br /> <input type="text" name="ud_feedtitle" value="<?=$feedtitle?>"><br>
URL: <br /> <input type="text" name="ud_feedurl" value="<?=$feedurl?>"><br>
Order: <br /> <input type="text" name="ud_feedorder" value="<?=$feedorder?>"><br>
Owner:<br /> <input type="text" name="ud_feedowner" value="<?=$feedowner;?>"><br>
<input type="Submit">
</form>
<?php
}else{
echo 'No entry found. Go back';
}
?>
</div>
</body>
</html>
update.php
<?php
$ud_ID = $_REQUEST["ID"];
$ud_feedtitle = $_POST["feed_title"];
$ud_feedurl = $_POST["feed_url"];
$ud_feedorder = $_POST["feed_order"];
$ud_feedowner = $_POST["feed_owner"];
$query = "UPDATE user_feeds SET feed_title = '$ud_feedtitle', feed_url = '$ud_feedurl', feed_order = '$ud_feedorder', feed_owner = '$ud_feedowner', WHERE feed_id = '$ud_ID'";
$res = mysql_query($query);
if ($res)
echo "<p>Record Updated<p>";
else
echo "Problem updating record. MySQL Error: " . mysql_error();
?>
Reason:
The name of the input field is the same name by which $_POST is populated. The variables you are currently requesting :
$_POST["feed_title"];, $_POST["feed_url"];, $_POST["feed_order"];, $_POST["feed_owner"];
are all empty as they don't exist. When updating, you are replacing the values in your table with blank values.
Solution:
In your update.php, the following should be there instead.
$ud_ID = $_POST["ID"];
$ud_feedtitle = $_POST["ud_feedtitle"]; //corresponding to <input type="text" name="ud_feedtitle" ...
$ud_feedurl = $_POST["ud_feedurl"]; //corresponding to <input type="text" name="ud_feedurl" ...
$ud_feedorder = $_POST["ud_feedorder"]; //corresponding to <input type="text" name="ud_feedorder" ...
$ud_feedowner = $_POST["ud_feedowner"]; //corresponding to <input type="text" name="ud_feedowner" ...

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