Trouble controlling the loops - php

Question

If pressed delet , All images are deleted ,I do not want that.
I just want to delete one image.
$get_img = "SELECT * FROM img";
$run_img = mysqli_query($db,$get_img);
while ($row_img= mysqli_fetch_array($run_img)){
if (isset($_POST['delete'])){
$delete= "DELETE FROM img WHERE id = {$row_img['id']} ";
$query = mysqli_query ($db , $delete);
}
echo '
<div style="width:200px; height:200px; border: 5px solid red; margin:10px; float: right;">
<img src="images/'.$row_pro['c_img'].'" width="200" height="200" /><br />
<form action="get.php" method="POST">
<input type="submit" name="delet" value="delet" />
</form>
</div>
';
}

Answer 1

Just a little explain, we start talking Arabic because Mostafa is not good in english, so i wrote a little explain in English and Arabic below to help to help both languages users.
while($row_img = mysqli_fetch_array($run_img)){
//explain [1]
echo '
<div style="width:200px; height:200px; border: 5px solid red; margin:10px; float: right;">
<img src="images/'.$row_img['c_img'].'" width="200" height="200" /><br />
<form action="?" method="POST">
<input name="id" value="'.$row_img['id'].'" hidden><!-- //explain [2] -->
<input type="submit" name="delet" value="delet" />
</form>
</div>
';
}
if(isset($_POST['delet'])){
$id = intval($_POST['id']);//explain [3]
$delete= "DELETE FROM img WHERE id = '$id'";
$query = mysqli_query($db, $delete);
if($query){
echo 'Deleted Successfully!';
}
}
explain [1] Remove the query from inside while its bad to put it there
explain [2] Then i made a hidden input called id to get the id from it
explain [3] Make the hidden sent id to $id variable and intval it for more security, you can read about it
.
explain [1] اول حاجة شلت الكويري إلي انت كاتبها جوا ال while
explain [2] بعدين سويت زر مخفي مع كل صورة إسمه أي دي يعطينا الاي دي الخاص فيها
explain [3] بعدين بستقبل الاي دي إلى بالزر المخفي على متغير جديد وبسويله شوية حماية.
I hope this helps you :)

Answer 2

Grab your isset and delete query out of while
Something like that. I did not checked all details but maybe it's good for inspiration.
$get_img = "SELECT * FROM img";
$run_img = mysqli_query($db, $get_img);
while ($row_img = mysqli_fetch_array($run_img))
{
echo '<div>
<img src="images/' . $row_pro['c_img'] . '" /><br />
</div>';
}
echo '<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
<input type="submit" name="delete" value="delete" />
</form>';
if (isset($_POST['delete']))
{
$delete= "DELETE FROM img WHERE id = :id", ['id'=>$row_pro['id']];
$query = mysqli_query($db, $delete);
}
Hope you'll figured out.