I am working on creating table in to my database with mysql and here is my code:
mysqli_query($link, "CREATE TABLE IF NOT EXISTS `review` (
`clients_id` int(15) NOT NULL AUTO_INCREMENT,
`client_id` varchar(150) NOT NULL DEFAULT '',
`rating` tinyint(2) NOT NULL DEFAULT '0',
`proj_date` date NOT NULL DEFAULT '0000-00-00',
`proj_desc` text NOT NULL DEFAULT '',
`photoname` text NOT NULL,
`companyname` text NOT NULL,
`feedback` text NOT NULL,
`status` tinyint(1) NOT NULL DEFAULT '0',
`emailid` varchar(100) NOT NULL DEFAULT '',
`customratings` varchar(100) NOT NULL DEFAULT '',
`photo_option` varchar(100) NOT NULL DEFAULT '',
`title` varchar(100) NOT NULL DEFAULT '',
`citation` varchar(100) NOT NULL DEFAULT '',
`date_option` varchar(100) NOT NULL DEFAULT '',
`rating_option` varchar(100) NOT NULL DEFAULT '',
PRIMARY KEY (`clients_id`),
FULLTEXT KEY `feedback` (`feedback`)
) ENGINE=MyISAM AUTO_INCREMENT=1") or mysqli_error($link);
But this is not reflecting into my database ? Why were I may be going wrong ?
but I tried creating other table with the following code
mysqli_query($link, "CREATE TABLE IF NOT EXISTS `setting` (
`id` int(11) NOT NULL auto_increment,
`script_url` text NOT NULL,
`date` varchar(4) NOT NULL,
`rateing` varchar(4) NOT NULL,
`photo` varchar(4) NOT NULL,
`dateformat` varchar(4) NOT NULL,
`page_limit` int(4) NOT NULL,
`proj_desc` varchar(4) NOT NULL,
`companyname` varchar(4) NOT NULL,
`text_color` varchar(255) NOT NULL,
`citation_color` varchar(255) NOT NULL,
`bg_color` varchar(255) NOT NULL,
`border_color` varchar(255) NOT NULL,
`ratingsformat` varchar(250) NOT NULL,
`rating` varchar(250) NOT NULL,
`customratings` varchar(250) NOT NULL,
`speed` varchar(250) NOT NULL,
`pagination` varchar(250) NOT NULL,
`version` varchar(250) NOT NULL,
`global_option` varchar(250) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=0;
") or mysqli_error($link);
it is being created correctly and both the tables are in the same file
No you cannot create table using an insert statement.
There are four types of SQL statements:
DML (DATA MANIPULATION LANGUAGE)
DDL (DATA DEFINITION LANGUAGE)
DCL (DATA CONTROL LANGUAGE)
TCL (TRANSACTION CONTROL LANGUAGE)
DML is your SELECT, INSERT, UPDATE and DELETE statements...
DDL is you your CREATE, ALTER and DROP statements.
See more info about types of SQL statements
In order to insert data in your table, first you need to create it.
How to create sql table from php
No. "INSERT INTO" used to insert the data to existing table only.You should create the table with respective column before try to insert the values.
Or you can check the table exist or not before going insert."If exists" u can insert the value else just create and insert the values.
This worked for me but I don't know how?
I just removed DEFAULT '' present while creating review table and table just got created
Here is edited code
mysqli_query($link, "CREATE TABLE IF NOT EXISTS `review` (
`clients_id` int(15) NOT NULL AUTO_INCREMENT,
`client_id` varchar(150) NOT NULL,
`rating` tinyint(2) NOT NULL,
`proj_date` date NOT NULL,
`proj_desc` text NOT NULL,
`photoname` text NOT NULL,
`companyname` text NOT NULL,
`feedback` text NOT NULL,
`status` tinyint(1) NOT NULL,
`emailid` varchar(100) NOT NULL,
`customratings` varchar(100) NOT NULL,
`photo_option` varchar(100) NOT NULL,
`title` varchar(100) NOT NULL,
`citation` varchar(100) NOT NULL,
`date_option` varchar(100) NOT NULL,
`rating_option` varchar(100) NOT NULL,
PRIMARY KEY (`clients_id`),
FULLTEXT KEY `feedback` (`feedback`)
) ENGINE=MyISAM AUTO_INCREMENT=1") or mysqli_error($link);
Related
Here is the structure of the database tables in quesiton.
Officials:
CREATE TABLE IF NOT EXISTS `officials` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`last` varchar(250) NOT NULL DEFAULT '',
`first` varchar(250) NOT NULL DEFAULT '',
`middle` varchar(250) NOT NULL DEFAULT '',
`address` varchar(250) NOT NULL DEFAULT '',
`city` varchar(250) NOT NULL DEFAULT '',
`state` varchar(250) NOT NULL DEFAULT '',
`zip` varchar(250) NOT NULL DEFAULT '',
`homeph` varchar(250) NOT NULL DEFAULT '',
`workph` varchar(250) NOT NULL DEFAULT '',
`cellph` varchar(250) NOT NULL DEFAULT '',
`main_phone` varchar(10) DEFAULT NULL,
`email` varchar(250) NOT NULL DEFAULT '',
`notes` text NOT NULL,
`blockreg` varchar(10) NOT NULL,
`inactive` varchar(10) NOT NULL,
`gender` varchar(100) NOT NULL,
`minority` varchar(100) NOT NULL,
`affiliate` tinyint(4) NOT NULL DEFAULT '0' COMMENT 'Is affiliate official? 0 = no. 1 = yes.',
PRIMARY KEY (`id`),
UNIQUE KEY `email` (`email`)
) ENGINE=InnoDB AUTO_INCREMENT=14506 DEFAULT CHARSET=latin1;
Transactions (edited from original post to show foreign key constraints):
CREATE TABLE IF NOT EXISTS `transactions` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`offid` int(11) NOT NULL,
`txn_id` varchar(64) NOT NULL,
`txn_time` varchar(24) NOT NULL,
`approval_code` varchar(24) DEFAULT NULL,
`amount` varchar(8) NOT NULL,
`result_message` varchar(100) NOT NULL,
`ch_phone` varchar(10) NOT NULL COMMENT,
`ch_card_type` varchar(4) NOT NULL,
`ch_address` varchar(50) NOT NULL,
`ch_state` varchar(15) NOT NULL,
`ch_last_name` varchar(50) NOT NULL,
`ch_email` varchar(100) NOT NULL,
`ch_zip` varchar(10) NOT NULL,
`ch_exp_date` varchar(4) NOT NULL,
`ch_city` varchar(50) NOT NULL,
`ch_first_name` varchar(30) NOT NULL,
`ch_transaction_type` varchar(15) NOT NULL,
`ch_card_number` varchar(18) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `txn_id` (`txn_id`) USING BTREE,
KEY `offid` (`offid`)
) ENGINE=InnoDB AUTO_INCREMENT=72 DEFAULT CHARSET=utf8mb4;
ALTER TABLE `transactions`
ADD CONSTRAINT `transactions_ibfk_1` FOREIGN KEY (`offid`) REFERENCES `officials` (`id`);
Transaction details (edited from original post to show foreign key constraints):
CREATE TABLE IF NOT EXISTS `transaction_details` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`xact_id` varchar(64) NOT NULL,
`detail_amount` float(5,2) NOT NULL,
`sport` varchar(10) NOT NULL,
`regyr` varchar(250) NOT NULL,
PRIMARY KEY (`id`),
KEY `xact_id` (`xact_id`)
) ENGINE=InnoDB AUTO_INCREMENT=63 DEFAULT CHARSET=utf8mb4;
ALTER TABLE `transaction_details`
ADD CONSTRAINT `transaction_details_ibfk_1` FOREIGN KEY (`xact_id`) REFERENCES `transactions` (`txn_id`) ON DELETE CASCADE ON UPDATE CASCADE;
Code that executes upon receiving the data from the credit card company where rows are inserted into the table:
// this creates the main transaction
$sql = "INSERT INTO transactions (offid, txn_id, txn_time, approval_code, amount, result_message, ch_phone,
ch_card_type, ch_address, ch_state, ch_last_name, ch_email, ch_zip, ch_exp_date, ch_city, ch_first_name,
ch_transaction_type, ch_card_number) VALUES ('$offid', '$txn_id', '$txn_time', '$approval_code', '$amount', '$result_message',
'$ch_phone', '$ch_card_type', '$ch_address', '$ch_state', '$ch_last_name', '$ch_email',
'$ch_zip', '$ch_exp_date', '$ch_city', '$ch_first_name', '$ch_transaction_type', '$ch_card_number')";
$result = mysqli_query($conn, $sql);
// this creates the detail transactions
if ($ssl_result == 0) {
$detail_sports = array('fb', 'vb', 'sb', 'bb', 'wr', 'sw', 'so', 'ba', 'tr');
foreach ($detail_sports as $sport) {
$var = $sport . 'total';
// cookie is set for fbtotal, vbtotal, etc. with an amount for that line item
if (isset($_COOKIE[$var])) {
$detail_amount = $_COOKIE[$var];
$sql = "INSERT INTO transaction_details (xact_id, detail_amount, sport, regyr) VALUES ('$txn_id', '$detail_amount', '$sport', '$regyear')";
$result = mysql_query($sql);
}
}
}
The transaction table has id numbers 1, 2, 3, 5, 6, 8, 9, 11, 12, 13, 15, 16, 17, etc. These should be consecutively numbered, but they aren't. It's almost as if they were written to the transaction (parent) table and then deleted. But the code doesn't delete a record.
The transaction detail table has a many-to-one relationship with transaction and all of its records contain consecutive ids.
Any idea what's going on?
I am creating a database that will store 'graduate details'. I have been able to set the ID to auto increment, Unique and also my primary key that start from 1...
I also want to make the certificate number field unique and auto-increment value in an increasing order that will start from 00001.
Please any help on how to go about this will be very appreciated. Thank you.
This is the MYSQL code for the database below;
CREATE TABLE IF NOT EXISTS `graduates` (
`id` int(10) NOT NULL AUTO_INCREMENT,
`f_name` varchar(25) NOT NULL,
`l_name` varchar(25) NOT NULL,
`gender` varchar(6) DEFAULT NULL,
`address` varchar(100) DEFAULT NULL,
`city` varchar(15) DEFAULT NULL,
`region` varchar(30) DEFAULT NULL,
`phone` varchar(15) DEFAULT NULL,
`email` varchar(50) DEFAULT NULL,
`certificate_number` int(50) NOT NULL AUTO_INCREMENT,
`programme` varchar(50) CHARACTER SET utf8mb4 NOT NULL,
`marks` int(10) NOT NULL,
`college_name` varchar(50) CHARACTER SET utf8mb4 NOT NULL,
`date_of_birth` date DEFAULT NULL,
`created_by` int(10) UNSIGNED NOT NULL DEFAULT 0,
`created_at` date DEFAULT NULL,
`updated_by` int(10) UNSIGNED NOT NULL DEFAULT 0,
`updated_at` timestamp NULL DEFAULT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `certificate_number` (`certificate_number`)
) ENGINE=InnoDB AUTO_INCREMENT=90 DEFAULT CHARSET=utf8;
after form submission, the data is stored in database. This is the query i already have:
CREATE TABLE IF NOT EXISTS `registered_users` (
`id` int(8) NOT NULL AUTO_INCREMENT,
`first_name` varchar(255) NOT NULL,
`last_name` varchar(255) NOT NULL,
`gender` varchar(20) NOT NULL,
`date_birth` varchar(255) NOT NULL,
`address` varchar(255) NOT NULL,
`postal_code` varchar(255) NOT NULL,
`place` varchar(255) NOT NULL,
`school_name` varchar(255) NOT NULL,
`email` varchar(55) NOT NULL,
`tel` varchar(55) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;
This is how i insert the data into the DB:
Now i want to insert a new row in the DB which can have only 2 values: "active" or "inactive" for each user. Default on "inactive". That should be inserted automatically for each user after submit. How can i do that?
When you create a table in a mysql db you can specify a default value for attributes. So if you want a boolean "active" / "inactive" flag you might want to try adding an active attribute to your table. See the added last column here:
CREATE TABLE IF NOT EXISTS `registered_users` (
`id` int(8) NOT NULL AUTO_INCREMENT,
`first_name` varchar(255) NOT NULL,
`last_name` varchar(255) NOT NULL,
`gender` varchar(20) NOT NULL,
`date_birth` varchar(255) NOT NULL,
`address` varchar(255) NOT NULL,
`postal_code` varchar(255) NOT NULL,
`place` varchar(255) NOT NULL,
`school_name` varchar(255) NOT NULL,
`email` varchar(55) NOT NULL,
`tel` varchar(55) NOT NULL,
`active` BOOLEAN NOT NULL DEFAULT false,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;
Ref.: https://dev.mysql.com/doc/refman/5.7/en/create-table.html
My knowledge of MySQL/ SQL apart from the simple CRUD operations is basic.
If I had to use a stored procedure to move certain attributes (not in a specific order) to another table how could it be done?
These are the following tables. I want to move from the 1st to the 2nd table.
As you can see the datatype sizes are different for certain columns.
CREATE TABLE IF NOT EXISTS `source_cdr` (
`callstart` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
`src` varchar(80) NOT NULL DEFAULT '',
`dst` varchar(80) NOT NULL DEFAULT '',
`accountcode` varchar(50) NOT NULL,
`uniqueid` varchar(100) NOT NULL,
`ID` int(11) NOT NULL AUTO_INCREMENT,
`callanswer` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
`callend` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
`disposition` varchar(50) NOT NULL,
`cdr_id` int(11) unsigned NOT NULL DEFAULT '0',
`pin_code` varchar(4) NOT NULL,
`provider` int(11) NOT NULL,
PRIMARY KEY (`ID`),
KEY `calldate_idx` (`callstart`) USING BTREE,
KEY `idx_acc_code_calldate` (`accountcode`,`callstart`) USING BTREE,
KEY `uniqueid` (`uniqueid`),
KEY `cdr_id` (`cdr_id`),
KEY `idx_uniqueid_cdr_id` (`uniqueid`,`cdr_id`)
) ENGINE=MyISAM;
--
CREATE TABLE IF NOT EXISTS `destination_cdr` (
`id` bigint(20) NOT NULL AUTO_INCREMENT,
`calldate` datetime NOT NULL,
`source` varchar(80) NOT NULL,
`destination` varchar(80) NOT NULL,
`account_code` varchar(30) DEFAULT NULL,
`pincode` varchar(45) NOT NULL,
`duration_call` bigint(20) NOT NULL DEFAULT '0',
`duration_talk` bigint(20) NOT NULL,
`disposition` varchar(255) NOT NULL,
`clid` varchar(80) DEFAULT NULL,
`cdr_id` bigint(20) DEFAULT NULL,
`vxcdr_id` bigint(20) DEFAULT NULL,
`provider` int(11) NOT NULL DEFAULT '0'
PRIMARY KEY (`id`)
) ENGINE=MyISAM;
EDIT 1
An example of a row
('2012-03-18 20:54:49', '5796', '0761100866', '103f0124ad510516f33cab132c0a695b', 'call-F1884808-6753-2F10-181C-3A#10.217.164.33', 308006367, '2012-03-18 20:55:05', '2012-03-18 20:55:51', '200 OK', 2, '', 0),
Thanks
You can use MySQL: INSERT ... SELECT Syntax to copy data from one table to the other.
Decide common fields in both and copy the same.
Example:
INSERT INTO TABLE2( COL1, COLx, ... ) SELECT colM, colY FROM TABLE1;
If the column sizes mismatch, data truncation takes place, and you can't overcome that but redefine the destination table columns.
I want to create some table through PHP but it fails everytime, but the same code excutes perfectly when excuted through MYsql console or PHPMyAdmin
The SQLs are
$sql = <<<SQL_CODE
CREATE TABLE IF NOT EXISTS `bid` (
`aid` int(11) unsigned NOT NULL,
`uid` int(11) unsigned NOT NULL,
`name` varchar(20) NOT NULL,
`amount` smallint(6) unsigned NOT NULL,
`time` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP
);
CREATE TABLE IF NOT EXISTS `item` (
`aid` int(11) unsigned NOT NULL AUTO_INCREMENT,
`name` varchar(40) NOT NULL,
`description` varchar(120) NOT NULL,
`img` int(11) unsigned NOT NULL,
`amount` smallint(6) unsigned NOT NULL,
`strtdate` date NOT NULL,
`enddate` date NOT NULL,
`uid` int(11) unsigned NOT NULL,
`uname` varchar(20) NOT NULL,
`uamount` int(11) unsigned NOT NULL,
PRIMARY KEY (`aid`)
);
CREATE TABLE IF NOT EXISTS `user` (
`uid` int(11) unsigned NOT NULL AUTO_INCREMENT,
`email` varchar(40) NOT NULL,
`password` varchar(40) NOT NULL,
`nameF` varchar(20) NOT NULL,
`nameL` varchar(20) NOT NULL,
`sex` varchar(1) NOT NULL,
`img` int(11) unsigned NOT NULL,
`country` varchar(10) NOT NULL,
`state` varchar(20) NOT NULL,
`address` varchar(120) NOT NULL,
`code` varchar(8) NOT NULL,
`isAdmin` varchar(1) NOT NULL,
PRIMARY KEY (`uid`),
UNIQUE KEY `email` (`email`)
);
SQL_CODE;
$sql2 = 'CREATE DATABASE `'.$db.'`;';
$sql3 = 'USE `'.$db.'`; ';
$sql4 = 'drop Database `'.$db.'``;';
if (!mysql_query($sql2)) echo mysql_error();
if (!mysql_query($sql3)) echo mysql_error();
//sleep(1);
if (!mysql_query($sql)) echo mysql_error();
echo $sql2.' '.$sql3.' '.$sql;
Error I'm getting
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CREATE TABLE IF NOT EXISTS item ( aid int(11) unsigned NOT NULL AUTO_INCREMENT,' at line 1CREATE DATABASE auction; USE auction; CREATE TABLE IF NOT EXISTS bid ( aid int(11) unsigned NOT NULL, uid int(11) unsigned NOT NULL, name varchar(20) NOT NULL, amount smallint(6) unsigned NOT NULL, time timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP); CREATE TABLE IF NOT EXISTS item ( aid int(11) unsigned NOT NULL AUTO_INCREMENT, name varchar(40) NOT NULL, description varchar(120) NOT NULL, img int(11) unsigned NOT NULL, amount smallint(6) unsigned NOT NULL, strtdate date NOT NULL, enddate date NOT NULL, uid int(11) unsigned NOT NULL, uname varchar(20) NOT NULL, uamount int(11) unsigned NOT NULL, PRIMARY KEY (aid));CREATE TABLE IF NOT EXISTS user ( uid int(11) unsigned NOT NULL AUTO_INCREMENT, email varchar(40) NOT NULL, password varchar(40) NOT NULL, nameF varchar(20) NOT NULL, nameL varchar(20) NOT NULL, sex varchar(1) NOT NULL, img int(11) unsigned NOT NULL, country varchar(10) NOT NULL, state varchar(20) NOT NULL, address varchar(120) NOT NULL, code varchar(8) NOT NULL, isAdmin varchar(1) NOT NULL, PRIMARY KEY (uid), UNIQUE KEY email (email));
From the mysql_query manual;
mysql_query() sends a unique query (multiple queries are not
supported)...
You need to split your triple CREATE TABLE statement into 3 separate statements and it will work.
I think that is a problem with multiple queries. I think that is solution.
http://php.net/manual/en/function.mysql-query.php
*mysql_query() sends a unique query (multiple queries are not supported) to the currently active database on the server that's associated with the specified link_identifier*
Just split them up and it will work.