No records displayed in PHP search form - php

Question

can anyone tell me why this code doesn't give me any records and display my "else" error message instead ? table which I'm trying to get data from( attached) uses two foreign keys ( emp number ,and project code) from two other tabels
( Please note I'm new to PHP )
$emp_no="";
$project_code="";
$p_hours="";
require_once 'connect.php';
function getposts()
{
$posts= array();
if (isset($_POST['EMPNo']))
{
$posts[0] = $_POST['EMPNo'];
}
if (isset($_POST['ProjectCode']))
{
$posts[1] = $_POST['ProjectCode'];
}
if (isset($_POST['Hours']))
{
$posts[2] = $_POST['Hours'];
}
return $posts;
}
if(isset($_POST['search']))
{
#$data = getposts();
#$searchquery = "SELECT * FROM `enrolment` WHERE `EMPNo`='$data[0]' AND
`ProjectCode`='$data[1]'";
#$search_Result =mysqli_query($connect, $searchquery);
if($search_Result)
{
if(mysqli_num_rows($search_Result))
{
while($raw = mysqli_fetch_array($search_Result))
{
$emp_no = $raw ['EMPNo'] ;
$project_code = $raw ['ProjectCode'] ;
$p_hours = $raw ['Hours'] ;
}
}else {
echo 'Unable to find the record please check input data!';
}
}else {
echo ' Result Error ';
}
}
//html part
<Form action="updateenrolment.php" method="post" style="color:blue;margin-
left:500px;">
<input type="text" name ="empno" placeholder="Employee No" value="<?php
echo $emp_no;?>"><br><br>
<input type="text" name ="pcode" placeholder="Project Code" value="<?php
echo $project_code;?>"><br><br>
<input type="number" name ="hours" placeholder="Hours" value="<?php echo
$p_hours;?>"><br><br>
<div>
<input type="submit" name ="search" value="Find" >

Answer 1

mysqli_fetch_array print the array result but you are fetching result using string element. you need to change this.
while($raw = mysqli_fetch_array($search_Result))
{
$emp_no = $raw [1] ;
$project_code = $raw [2] ;
$p_hours = $raw [3] ;
}
To replace it.
while($raw = mysqli_fetch_array($search_Result))
{
$emp_no = $raw ['EMPNo'] ;
$project_code = $raw ['ProjectCode'] ;
$p_hours = $raw ['Hours'] ;
}