How to count entry by refrenceName?
my sql query is
SELECT GROUP_CONCAT(refrenceName)
FROM attendance
where event='4'
GROUP BY refrenceName
HAVING ( COUNT(refrenceName) > 0 )
and showing result below
but how to count? I want Ashish(6), Babli(1)Rebecca(5) pls help me
SELECT concat(refrenceName,"(",count(refrenceName),")")
FROM attendance
where event='4'
GROUP BY refrenceName
HAVING ( COUNT(refrenceName) > 0 );
If you use GROUP_CONCAT for reference name, it will show result as reference name with comma separated values
(like : Ashish,Ashish,Ashish,Ashish,Ashish,Ashish)
As per your expected output, you want to show only the name-not to be duplicated in the result, along with count.
So Hereby concatnating the referenceName with count(referenceName) as we have already groupped by the same column referenceName.
Related
i query to check if a point(input) is intersect with polygons in php:
$sql1="SELECT ST_intersects((ST_SetSRID( ST_Point($startlng, $startlat),4326))
, zona_bahaya.geom) as intersek
FROM zona_bahaya";
$query1 = pg_query($conn,$sql1);
$check_location = pg_fetch_array($query1);
if (in_array('t',$check_location)) {
dosemthing1;}
else {dosomething2;}
it's work peroperly before i update the data
after data updated, it's only show the first row when i check the pg_fetch_array result. here is the result {"0":"f","intersek":"f"} .
i try to check from pgadmin and it's can show 8 result (1 true(intersected) and 7 false(not intersect)) using updated data with this query:
SELECT ST_intersects((ST_SetSRID( ST_Point(110.18898065505843, -7.9634510320131175),4326))
, zona_bahaya.geom) as intersek
FROM zona_bahaya;
to solve it, i order the query result descended so the 'true' gonna be the first like this:
order by intersek desc
anybody can help me to findout way it just only show the first row???
here some geom from STAsText(zonabahaya.geom) not all of them : MULTIPOLYGON(((110.790892426072 -8.19307615541514,110.791999687385 -8.19318330973567,110.794393723931 -8.1927980624753,110.794586347561 -8.19205508561603,110.795329324421 -8.19120203811094,110.796540101525 -8.19023891996003,110.797503219676 -8.18933083713203,110.798576408472 -8.18919324882476,110.79929186767 -8.18957849608512,110.800337538805 -8.19059664955894,110.800585197758 -8.19150473238694,110.80022746816 -8.19238529755349,110.799787185576 -8.19290813312112,110.799589319279 -8.19300706626968,110.798788231202 -8.19299429992581,110.798537293576 -8.19311976873883,110.79850269889 -8.1933090511224,110.798620939451 -8.19433728092441)))
In order to filter only the records that intersect you have to use ST_Intersects in the WHERE clause:
SELECT *
FROM zona_bahaya
WHERE ST_Intersects(ST_SetSRID(ST_Point(110.18, -7.96),4326),zona_bahaya.geom);
Since you're dealing with points and polygons, perhaps you should take a look also at ST_Contains.
In case you want to fetch only the first row you must set a limit in your query - either using LIMIT 1 or FETCH FIRST ROW ONLY -, but it would only make sense combined with a ORDER BY, e.g.
SELECT *
FROM zona_bahaya
JOIN points ON ST_Intersects(points.geom,zona_bahaya.geom)
ORDER BY gid
FETCH FIRST ROW ONLY;
Demo: db<>fiddle
I was working with a project where I want to get the count of values in a column. I will explain with an example.
I have a table column named name. Where it's values are A,B,C,D,A,D,B,A,C.
Now I want the output as
Count: A-3,B-2,C-2,D-2.
I have tried using group by and distinct. but both don't give me what I want. It all getting the total count of that item. In the code given below is the query I tried. There I want the count of particulars_id and the $public_page_id will be common for all particulars_id I am fetching. There will be a number of public_page_id in the table, and each will have some particulars_id under them.
$output = '';
$this->db->select('COUNT(service_appointment_details.particulars_id)
as count,particulars.particulars_name');
$this->db->from('particulars');
$this->db->group_by('particulars.particulars_id');
$this->db->where('particulars.public_page_id',$public_page_id);
$this->db-
>join('service_appointment_details','particulars.public_page_id =
service_appointment_details.public_page_id','right');
$this->db->where($where_date);
$query = $this->db->get();
Expected Result
Expected Result is (based on the above example)
Count: A-3,B-2,C-2,D-2.
Actual Result
But what I'm getting now is
Count: A-9,B-9,C-9,D-9.
I need to fetch count of each particulars_id under the given public_page_id
You should use count(*)
$this->db->select('COUNT(*) as count,particulars.particulars_name');
........
As pointed out by #scaisEdge, you need to use count(*) instead of count(service_appointment_details.particulars_id). By using count(service_appointment_details.particulars_id), you basically count the number of rows from your select which is not what you want.
Final snippet would be:
$output = '';
$this->db->select('COUNT(*) as count, particulars.particulars_name');
$this->db->from('particulars');
$this->db->group_by('particulars.particulars_name');
$this->db->where('particulars.public_page_id',$public_page_id);
$this->db->join('service_appointment_details','particulars.public_page_id = service_appointment_details.public_page_id','right');
$this->db->where($where_date);
$query = $this->db->get();
Whenever you want to count occurrence of a column values, you'd do
SELECT column_to_count, count(*) FROM table GROUP BY column_to_count
I need some help with a query as I don't seem to get my head around it.
First table vacancies:
vac_id
vac_title
vac_location
vac_description
is_deleted
status
Second table vacancies_labels:
vac_id
Label_id
Now I would like to get an output containing all vacancies within a certain location but they also cannot contain the label_id '10' nonetheless of the location.
SELECT `v`.*
FROM `vacancies` AS `v`
LEFT JOIN `vacancies_labels` as `vl` ON `v`.`vacancy_id` = `bl`.`vacancy_id`
WHERE `v`.`vac_location` = 'russia'
AND `v`.`is_deleted` != 1
AND `v`.`status` = 1
AND `vl`.`label_id` NOT IN ('10')
GROUP BY `v`.`vacancy_id`
This results only in the vacancies that have a record in the vacancies_labels table that are not 10. It leaves out however all vacancies that have no records at all in the vacancies_labels table but fit within the location range.
What am I missing here?
Thx!
Using a LEFT JOIN, if the record is not found, then the values will return null. But in your WHERE clause, you have
AND `vl`.`label_id` NOT IN ('10')
as NOT IN doesn't consider nulls you have to do something like...
AND ( `vl`.`label_id` NOT IN ('10') OR `vl`.`label_id` IS NULL)
Hello I have been working on an sql code I found online that said that it check if there duplicates online.
What I want to do is that it checks whether if a value has a duplicate in the table it is inserting then I need to return a booleon in PHP but I am having a problem in MYSQL code. I have this code I have found online:
SELECT schedday,schedtime COUNT(schedday, schedtime) as count
FROM scstock
GROUP BY schedday, schedtime
HAVING COUNT(schedday, schedtime) > 1
But I am having this error
Then I tried to modify it to this which is I wanted to accomplish
SELECT schedday,schedtime COUNT(schedday, schedtime) as count
FROM scstock
WHERE schedday = 'M/T' AND schedtime = '7:00-9:00/7:00-9:00'
HAVING count > 1
But this appears
Can you help me?
Try this below query for your result
SELECT schedday,schedtime, COUNT(*) as count FROM scstock GROUP BY schedday, schedtime HAVING count > 1
you have syntax error you should put an "," after schedtime
SELECT schedday,schedtime , COUNT(schedday, schedtime) as count
FROM scstock
GROUP BY schedday, schedtime
HAVING count > 1
It seems that I have to edit my question again - these down votes are getting frustrating...
I have an array of ids and a table to check it with. This is the query I use:
SELECT COUNT(*) FROM orders WHERE order_id IN (...
When this number isn't equal to the number of ids in the array, I need to get those values from the array that I have, that do not exist in the table. Is there a more optimal way to do this than making some temporary table, and selecting from it?
EDIT: For all those suggesting inserting NOT in the first query - I do not need all the rows from my table that do not match the values in the array - I need the values from the ARRAY itself...
For example, I have an array of three ids - "1","2","3". In the table I have ids "2" and "3". I check the array with my query:
SELECT COUNT(*) FROM orders WHERE order_id IN (1,2,3)
I get the number 2 as a result of this query, and that doesn't match the number of ids I have in the array, which is 3. I need a query that will get the missing id from the array I submitted, in this case the id I need is "1"
I don't think there's a clean SQL-only solution, because there's no way to SELECT from an array. However, instead of using a temporary table, you could return all the IDs that are found in the table, and do the NOT on the PHP side.
So select the result of this into an array, $existing_orders:
SELECT order_id FROM orders WHERE order_id IN (...);
Then you have:
$all_orders = array(1, 2, 3); // IDs you're looking for
$existing_orders = array(2, 3); // IDs that were found in the table
$not_existing_orders = array_diff($all_orders, $existing_orders);
print_r($not_existing_orders); // Array( [0] => 1 )
OK THAT´S clear now:
Then you will have to make something like this:
select id from order where id IN ( your list )
create a second array with the found values
and then use php array function array_diff
select * from orders where order_id NOT in (...