I want to add a string between a url string using PHP.
$link = 'http://localhost/wordpress/mypage';
$string = 'nl/';
I want the new link to be like this:
$newlink = 'http://localhost/wordpress/nl/mypage';
Here is one-of-the way to achieve it, using substr_replace():
$someString = 'http://localhost/wordpress/mypage';
$string = 'nl/';
echo substr_replace($someString, $string, strpos($someString, 'mypage'), 0);
Output:
http://localhost/wordpress/nl/mypage
Another method using str_replace():
$someString = 'http://localhost/wordpress/mypage';
echo str_replace('wordpress/', 'wordpress/nl/', $someString);
this is an easiest way you can do.
$string = 'nl/';
$link = 'http://localhost/wordpress/'.$string.'mypage';
You can set the $string dynamic or static as you wanted to.
echo $link; Result : http://localhost/wordpress/nl/mypage
Related
I have a PHP function which converts #Hashtag into a link...
function convertHashtags($str) {
$regex = "/#+([a-zA-Z0-9_]+)/";
$str = preg_replace($regex, '$0', $str);
return($str);
}
It work properly when I use it with a common string
$string = "Hello #World";
$string = convertHashtags($string);
(in this case an output would be: Hello #World
But when I'm trying to insert something from my database to that string it displays, but without that function's effect…
$string = $row["content"];
$string = convertHashtags($string);
(an output: Hello #World)
I am new to the PHP and MySQL stuff… Certainly, there are many things I don't know yet :D
What's wrong with this function?
Thanks!
function convertHashtags($str){
list($str1, $str2) = explode("#", $str) ;
$str2 = '#'.$str2.'';
$str = $str1." ".$str2 ;
return($str);
}
Can you use the above function and test with database entry?
Oh well, I just add new element to a database and it works!
I was testing it on old elements, they was inserted before I wrote the function.
I should try it before writing a this, my bad… thanks for help anyway!
$string = $row["content"];
$string = (string)$string;
$string = convertHashtags($string);
Use the above code and it will work.
I am trying to remove first 51 character of a long URL , I'm using
$sql = $db->Query(some query);
$mysite = $db->FetchArray($sql);
$str = $mysite['url'] ;
$str2 = substr('$str',51);
Above code return blank value, it works fine if i use plan text for $str
e.g.
$str = "I am looking for a way to pull the first 100 characters from a string"
$str2 = substr('$str',10);
my url is like "https://dl.dropbox.com/u/55299544/google.html?urlc=http://example.com"
i want to get http://example.com from database to show on user page,
how can i do this?
You're making this too complicated. If you are trying to get the http://example.com from the long URL then do this.
<?php
sql = $db->Query(some query);
$mysite = $db->FetchArray($sql);
$str = $mysite['url'] ;
$query = parse_url($str, PHP_URL_QUERY );
parse_str($query, $link);
echo $link["urlc"]; //http://example.com
?>
I have a string that looks a little something like this:
$string = 'var1=foo&var2=bar&var3=blahblahblah&etc=etc';
And I would like to make another string from that, and replace it with a value, so for example it will look like this
$newstring = 'var1=foo&var2=bar&var3=$myVariable&etc=etc';
so var3 in the new string will be the value of $myVariable.
How can this be achieved?
No need for regex; built in URL functions should work more reliably.
// Parse the url first
$url = parse_url($string);
// Parse your query string into an array
parse_str($url['query'], $qs);
// Replace the var3 key with your variable
$qs['var3'] = $myVariable;
// Convert the array back into a query string
$url['query'] = http_build_query($qs);
// Convert the $url array back into a URL
$newstring = http_build_url($url);
Check out http_build_query and parse_str. This will append a var3 variable even if there isn't one, it will URL encode $myVariable, and its more readable than using preg_replace.
You can use the method preg_replace for that. Here comes an example
<?php
$string = 'var1=foo&var2=bar&var3=blahblahblah&etc=etc';
$var = 'foo';
echo preg_replace('/var3=(.*)&/', 'var3=' . $var . '&', $string);
How can I use str_replace method for replacing a specified portion(between two substrings).
For example,
string1="www.example.com?test=abc&var=55";
string2="www.example.com?test=xyz&var=55";
I want to replace the string between '?------&' in the url with ?res=pqrs&. Are there any other methods available?
You could use preg_replace to do that, but is that really what you are trying to do here?
$str = preg_replace('/\?.*?&/', '?', $input);
If the question is really "I want to remove the test parameter from the query string" then a more robust alternative would be to use some string manipulation, parse_url or parse_str and http_build_query instead:
list($path, $query) = explode('?', $input, 2);
parse_str($query, $parameters);
unset($parameters['test']);
$str = $path.'?'.http_build_query($parameters);
Since you're working with URL's, you can decompose the URL first, remove what you need and put it back together like so:
$string1="www.example.com?test=abc&var=55";
// fetch the part after ?
$qs = parse_url($string1, PHP_URL_QUERY);
// turn it into an associative array
parse_str($qs, $a);
unset($a['test']); // remove test=abc
$a['res'] = 'pqrs'; // add res=pqrs
// put it back together
echo substr($string1, 0, -strlen($qs)) . http_build_query($a);
There's probably a few gotchas here and there; you may want to cater for edge cases, etc. but this works on the given inputs.
Dirty version:
$start = strpos($string1, '?');
$end = strpos($string1, '&');
echo substr($string1, 0, $start+1) . '--replace--' . substr($string1, $end);
Better:
preg_replace('/\?[^&]+&/', '?--replace--&', $string1);
Depending on whether you want to keep the ? and &, the regex can be mofidied, but it would be quicker to repeat them in the replaced string.
Think of regex
<?php
$string = 'www.example.com?test=abc&var=55';
$pattern = '/(.*)\?.*&(.*)/i';
$replacement = '$1$2';
$replaced = preg_replace($pattern, $replacement, $string);
?>
Hi all i know preg_replace can be used for formatting string but i need help in that concerned area my url will be like this
http://www.example.com/index.php/
also remove the http,https,ftp....sites also
what i want is to get
result as
example.com/index.php
echo preg_replace("~(([a-z]*[:](//))|(www.))~", '', "ftp://www.example.com");
$url = 'http://www.example.com/index.php/';
$strpos = strpos($url,'.');
$output = substr($url,$strpos+1);
$parts=parse_url($url);
unset($parts['scheme']);
//echo http_build_url($parts);
echo implode("",$parts);
EDIT
To use http_build_url you needs pecl_http you can use implode as alternate
Something like this
$url = "http://www.example.com/index.php";
$parts = parse_url($url);
unset($parts['scheme']);
echo preg_replace('/^((ww)[a-z\d][\x2E])/i', '', join('', $parts));
Output
example.com/index.php
Example #2
$url = "http://ww3.nysif.com/Workers_Compensation.aspx";
Output
nysif.com/Workers_Compensation.aspx