How does Symfony's autowiring work behind the scenes? - php

This is not about instructions (the docs are sufficient), but a question of how things work.
Symfony 4's autowiring system allows us to auto-inject services by simply typehinting
use App\Util\Rot13Transformer;
class TwitterClient
{
public function __construct(Rot13Transformer $transformer)
{
$this->transformer = $transformer;
}
}
To gain a deeper understanding of PHP, I have looked around in the symfony-bundle source code but can't find the spot where the "magic" happens.
How can Symfony prevent PHP from protesting that not enough arguments were fed to the constructor (or any function that uses autowiring)?

They use Refection
How can Symfony prevent PHP from protesting that not enough arguments were fed to the constructor
Reflection allows you to inspect the definition of other "things" in PHP. Among them are Classes their methods, and the arguments for those methods.
<?php
class bar
{
//just a placeholder class
};
$bar = new bar(); //instance of bar
//class to inspect
class foo
{
public function __construct( bar $bar)
{
//do something fancy with $bar
}
}
//get the Reflection of the constructor from foo
$Method = new ReflectionMethod('foo', '__construct');
//get the parameters ( I call them arguments)
$Args = $Method->getParameters();
//get the first argument
$Arg = reset($Args);
//export the argument definition
$export = ReflectionParameter::export(
array(
$Arg->getDeclaringClass()->name,
$Arg->getDeclaringFunction()->name
),
$Arg->name,
true
);
//parse it for the typehint
$type = preg_replace('/.*?(\w+)\s+\$'.$Arg->name.'.*/', '\\1', $export);
echo "\nType: $type\n\n";
var_dump(is_a($bar, $type));
Outputs:
Type: bar
bool(true)
You can see it here
Then you just use is_a() or whatever to see if an "input" object has bar as one of it's ancestors. And as you can see in this simplified example if we had object $bar, we would know that it's perfectly good as an input to our constructor because it returns true.
I should note SO is probably not the right place to ask this, but i could use it in one of my many projects so I didn't mind figuring it out. Also I never used Symphony...
Special thanks to this SO question for the last bit on parsing the type hint:
PHP Reflection - Get Method Parameter Type As String
That said I would have figured the Regx out in about 10 seconds, the export method no so much.
This is the extent of the documentation on it
http://php.net/manual/en/reflectionparameter.export.php
Literally
public static string ReflectionParameter::export ( string $function , string $parameter [, bool $return ] )

As others mentioned, they use Reflection. If you want to see how exactly Symfony is doing this, start with autowire() method here

Related

Parameter to define a type of class

I have a constructor that asks for a type of class, but it doesn't define that as a type hint. You are able to pass anything you want to it, and it will accept it. Is there a way to pass a class type to the constructor, and in the add() method it only accepts that type?
Currently what I have, is the ability to pass anything to the constructor such as an int, string, bool, etc. Is there a way to make it so that the constructor only accepts class types?
class Main{
protected $items = [];
protected $type = '';
public function __construct($type){
$this->type = $type;
}
public function add($object){
if($object instanceof $this->type){
$this->items[] = $object;
}
}
}
class Test{}
class Awesome{}
$main1 = new Main(Test::class);
$main2 = new Main(Awesome::class);
// Successful:
$main1->add(new Test());
// Fail:
$main1->add(new Awesome());
// Successful:
$main2->add(new Awesome());
// Fail:
$main2->add(new Test());
If I were to do it in C# it would look something like this:
Main main1 = new Main<Test>();
Main main2 = new Main<Awesome>();
Basically it says that add() will only allow instances of Test. Is there a way to do some
Php doesn't support template like declarations like e.g. c++.
The best way you may be able to achive this is by passing a lambda which then in return gets used in order to validate the passed parameter in add.
<?php
class Test {
private $validator = null;
public function __construct($validator) {
$this->validator = $validator;
}
public function add($value) {
$func = $this->validator;
$validated = $func($value);
echo $validated ? 'OK' : 'NG';
}
}
$obj = new Test(function($value) {
return is_int($value);
});
$obj->add(11);
$obj->add('string');
Another possibility would be to pass the type e.g. "ClassName" in your constructor and use get_class() and gettype() for the validation.
In the future there may be smarter solutions since you'll be able to write anonymous classes but I haven't really thought about that but in the end they would work similarly to lambdas.
Basically it says that add() will only allow instances of Test.
It's possible to achieve this in PHP by simply adding the type before the argument name in the function definition (similar with C/C++/C# types):
class Main {
protected $items = [];
public function add(Test $object) {
$this->items[] = $object;
}
}
PHP 5 accepts classes, interfaces, array and callable as type hints. If Test is a class then Main::add() accepts objects of class Test and its children. If Test is an interface, then the method Main::add() accepts objects that implement Test or one of its children.
PHP 7 (coming soon to a server near you) introduces type hinting for scalar types too.
PHP does not support anything similar with C++ templates or C# generics. If you want to create a class that works with objects of type A and another class that has identical behaviour but works with objects of type B you have several options but none of them is as elegant as the templates/generics:
Create two classes having identical behaviour, one for objects of type A, another for objects of type B; use different type hints (A and B) in the arguments lists of the methods of the two classes to enforce the separation - not scalable;
Something similar to your code, use the allowed class name as a string property and check it on any operation; you can also validate the argument of the constructor using class_exists() - the code becomes cluttered with tests and less readable;
Use OOP polymorphism; extend both A and B from the same class T or, even better, make A and B implement the same interface I. A PHP interface can be empty, it doesn't need to declare anything; empty interfaces used just for type hinting are common practice in PHP.
Then write a single class Main and use I as type hint for all its methods that accept objects. It will accept objects of both types A and B but if you also declare functions in I (and implement them in A and B, of course) then use them in Main you can be sure nothing breaks (I becomes a contract between Main and the objects its accepts as arguments for its methods).
I would choose option #3 because it gets the most help from the interpreter; it verifies the type of the arguments on each function call that has type hints and triggers a recoverable fatal error (in PHP 5) or throws an exception (in PHP 7).
Also some IDEs and static code analysis tools can validate the calls without running the code and help you fix it.
Is there a way to make it so that the constructor only accepts class
types?
Nope!
It is not possible in PHP. Not like C#, at least.
You need either set a type hint or set any types.
However, there's a closer solution in order to accept only class when instancing a class: Using ReflectionClass!
class Main {
protected $items = [];
protected $type = null;
public function __construct($type) {
$reflector = new ReflectionClass($type);
$this->type = $reflector->getName(); # or: $this->type = $type;
}
public function add($object) {
if($object instanceof $this->type) {
$this->items[] = $object;
}
}
}
As ReflectionClass contructor argument only accpets a string containing the name of the class to reflect, you can take advantage that, so passing scalars strings will cause an exception.
$main = new Main(Test::class); # Okay!
$main = new Main('Test'); # Okay!
However
$main = new Main('bool');
// Results
# PHP Fatal error: Uncaught exception 'ReflectionException'
# with message 'Class bool does not exist' in ...
Change your constructor to this:
public function __construct(Type $type){
$this->type = $type;
}
This is based on the assumption that $type is an instance of Type.

Can PHP objects be constructed and their variables set in one operation?

In perl I'm used to doing
my $foo = new WhatEver( bar => 'baz' );
and now I'm trying to figure out if PHP objects can ever be constructed this way. I only see this:
my $foo = new WhatEver();
$foo->{bar} = 'baz';
is it possible to do it in one step?
You can lay out your constructor as follows:
class MyClass {
public function __construct($obj=null) {
if ($obj && $obj instanceof Traversable || is_array($obj)) {
foreach ($obj as $k => $v) {
if (property_exists($this,$k)) {
$this->{$k} = $v;
}
}
}
}
}
This has a serie of drawbacks:
This is inefficient
The variables you create will not show up on any doc software you use
This is the open door to all forms of slackery
However, it also presents the following benefits:
This can be extended pretty safely
It allows you to lazy-implement variables
It also allows you to set private variables, provided that you know their names. It is pretty good in that respect if not abused.
The parameters passed in the parentheses (which can be omitted, by the way, if there aren't any) go to the constructor method where you can do whatever you please with them. If a class is defined, for example, like this:
class WhatEver
{
public $bar;
public function __construct($bar)
{
$this -> bar = $bar;
}
}
You can then give it whatever values you need.
$foo = new WhatEver('baz');
There are a few ways to accomplish this, but each has its own drawbacks.
If your setters return an instance of the object itself, you can chain your methods.
my $foo = new WhatEver();
$foo->setBar("value")->setBar2("value2");
class WhatEver
{
public $bar;
public $bar2;
public function setBar($bar)
{
$this->bar = $bar;
return $this;
}
public function setBar2($bar2)
{
$this->bar2 = $bar2;
return $this;
}
}
However, this doesn't reduce it to one step, merely condenses every step after instantiation.
See: PHP method chaining?
You could also declare your properties in your constructor, and just pass them to be set at creation.
my $foo = new WhatEver($bar1, $bar2, $bar3);
This however has the drawback of not being overtly extensible. After a handful of parameters, it becomes unmanageable.
A more concise but less efficient way would be to pass one argument that is an associative array, and iterate over it setting each property.
The implicit assumption here is that objects have meaningful, presumably public, properties which it is up to the calling code to provide values for. This is by no means a given - a key aspect of OOP is encapsulation, so that an object's primary access is via its methods.
The "correct" mechanism for initialising an object's state is its constructor, not a series of property assignments. What arguments that constructor takes is up to the class definition.
Now, a constructor might have a long series of named parameters, so that you could write $foo = new WhatEver(1, "hello", false, null) but if you want these to act like options, then it could take a single hash - in PHP terms, an Array - as its argument.
So, to answer the question, yes, if your constructor is of the form function __construct(Array $options) and then iterates over or checks into $options. But it's up to the constructor what to do with those options; for instance passing [ 'use_safe_options' => true ] might trigger a whole set of private variables to be set to documented "safe" values.
As of PHP 5.4 (which introduced [ ... ] as an alternative to array( ... )), it only takes a few more character strokes than the Perl version:
$foo = new WhatEver( ['bar' => 'baz'] );

php: Instantiate class on-the-fly

Is it possible to instantiate a class from a string, without declaring another variable before ?
It's usually done writing
$className = 'myClass'
$instance = new $className();
but it could be handy to have it shorter like for example
$instance = new ${'className'}();
The purpose is to have objects created (under condition) inside a loop without use of extra vars...
Edit : $className is dynamic, it is hard coded above to explain the situation
See factory pattern.
class Foo {
static function factory($class, array $args = null) {
return new $class($args);
}
}
// class factoring; returns a new instance of requested class ($className)
Foo::factory($className);
I added optional arguments array if you want to set some class properties.
// pass some values for class constructor
Foo::factory($className, array('arg1' => 1, 'arg2' => 2, 'args3' => 3));
Furthermore, you can build "fluid" interfaces so you can "chain" methods when you use that pattern:
Foo::factory($className)->method1()->method2(array('param' => 'value'))->etc();
where method1(), method2() must return $this (the object itself) to chain multiple method calls in one line.
You could make a factory function (or class/method) that takes a class name as a parameter, and then call it with the result of your dynamic PHP code that generates the string. You might consider it a bit cleaner but it's not going to save you any memory or speed.
class foo { }
function factory($class) { return new $class(); }
foreach (...) {
$instance = factory(<some code that returns the string 'foo'>);
}
It's one extra variable, does it really make much of a difference? The answer is that unless you use eval (which comes with security issues) it isn't possible to do it any shorter than your first example.

call_user_func_array passing arguments to a constructor [duplicate]

This question already has an answer here:
How to call the constructor with call_user_func_array in PHP
(1 answer)
Closed 7 years ago.
I have searched many a page of Google results as well as here on stackoverflow but cannot find a solution that seems to fit my situation. I appear to have but one last snag in the function I am trying to build, which uses call_user_func_array to dynamically create objects.
The catchable fatal error I am getting is Object of class Product could not be converted to string. When the error occurs, in the log I get five of these (one for each argument): PHP Warning: Missing argument 1 for Product::__construct(), before the catchable fatal error.
This is the code of the function:
public static function SelectAll($class, $table, $sort_field, $sort_order = "ASC")
{
/* First, the function performs a MySQL query using the provided arguments. */
$query = "SELECT * FROM " .$table. " ORDER BY " .$sort_field. " " .$sort_order;
$result = mysql_query($query);
/* Next, the function dynamically gathers the appropriate number and names of properties. */
$num_fields = mysql_num_fields($result);
for($i=0; $i < ($num_fields); $i++)
{
$fetch = mysql_fetch_field($result, $i);
$properties[$i] = $fetch->name;
}
/* Finally, the function produces and returns an array of constructed objects.*/
while($row = mysql_fetch_assoc($result))
{
for($i=0; $i < ($num_fields); $i++)
{
$args[$i] = $row[$properties[$i]];
}
$array[] = call_user_func_array (new $class, $args);
}
return $array;
}
Now, if I comment out the call_user_func_array line and replace it with this:
$array[] = new $class($args[0],$args[1],$args[2],$args[3],$args[4]);
The page loads as it should, and populates the table I am building. So everything is absolutely functional until I try to actually use my $args array within call_user_func_array.
Is there some subtle detail about calling that array that I am missing? I read the PHP manual for call_user_func_array once, and then some, and examples on that page seemed to show people just building an array and calling it for the second argument. What could I be doing wrong?
You can't call the constructor of $class like this:
call_user_func_array (new $class, $args);
That's no valid callback as first parameter. Let's pick this apart:
call_user_func_array (new $class, $args);
Is the same as
$obj = new $class;
call_user_func_array ($obj, $args);
As you can see, the constructor of $class has been already called before call_user_func_array comes into action. As it has no parameters, you see this error message:
Missing argument 1 for Product::__construct()
Next to that, $obj is of type object. A valid callback must be either a string or an array (or exceptionally a very special object: Closure, but that's out of discussion here, I only name it for completeness).
As $obj is an object and not a valid callback, so you see the PHP error message:
Object of class Product could not be converted to string.
PHP tries to convert the object to string, which it does not allow.
So as you can see, you can't easily create a callback for a constructor, as the object yet not exists. Perhaps that's why you were not able to look it up in the manual easily.
Constructors need some special dealing here: If you need to pass variable arguments to a class constructor of a not-yet initialize object, you can use the ReflectionClass to do this:
$ref = new ReflectionClass($class);
$new = $ref->newInstanceArgs($args);
See ReflectionClass::newInstanceArgs
Not possible using call_user_func_array(), because (as the name suggest) it calls functions/methods, but is not intended to create objects, Use ReflectionClass
$refClass = new ReflectionClass($class);
$object = $refClass->newInstanceArgs($args);
Another (more design-based) solution is a static factory method
class MyClass () {
public static function create ($args) {
return new self($args[0],$args[1],$args[2],$args[3],$args[4]);
}
}
and then just
$object = $class::create($args);
In my eyes it's cleaner, because less magic and more control
I use this for singleton factory pattern, becouse the ReflectionClass brokes the dependence tree, I hate the use of eval but its the only way to i find to simplificate the use of singleton pattern to inject mockObjects whith PHPUnit whitout open the class methods to that injection, BE CAREFULL WHITH THE DATA WHAT YOU PASS TO eval FUNCTION!!!!!!!! YOU MUST BE SURE THAT IS CLEANED AND FILTERED!!!
abstract class Singleton{
private static $instance=array();//collection of singleton objects instances
protected function __construct(){}//to allow call to extended constructor only from dependence tree
private function __clone(){}//to disallow duplicate
private function __wakeup(){}//comment this if you want to mock the object whith php unit jejeje
//AND HERE WE GO!!!
public static function getInstance(){
$a=get_called_class();
if(!array_key_exists($a, self::$instance)){
if(func_num_args()){
/**HERE IS THE CODE **//
$args=func_get_args();
$str='self::$instance[$a]=new $a(';
for($i=0;$i<count($args);$i++){
$str.=(($i)?",":"").'$args['.$i.']';
}
eval($str.");");//DANGER, BE CAREFULLY...we only use this code to inject MockObjects in testing...to another use you will use a normal method to configure the SingletonObject
/*--------------------------*/
}else{
self::$instance[$a]=new $a();
}
}
return self::$instance[$a];
}
}
And to use that:
class MyClass extends Singleton{
protected function __construct(MyDependInjection $injection){
//here i use the args like a normal class but the method IS PROTECTED!!!
}
}
to instanciate the object:
$myVar= MyClass::getInstance($objetFromClassMyDependInjection);
it calls the constructor whith the args I pased. i know that i can get the same result extending the static method getInstance but to teamworking its more easy to use this way

Is it a bad practice to define class options through an array?

When we take a look at Javascript frameworks like Dojo, Mootools, jQuery, JS Prototype, etc. we see that options are often defined through an array like this:
dosomething('mainsetting',{duration:3,allowothers:true,astring:'hello'});
Is it a bad practice to implement the same idea when writing a PHP class?
An example:
class Hello {
private $message = '';
private $person = '';
public function __construct($options) {
if(isset($options['message'])) $this->message = $message;
if(isset($options['person'])) $this->person = $person;
}
public function talk() {
echo $this->person . ' says: ' . $this->message;
}
}
The regular approach:
class Hello {
private $message = '';
private $person = '';
public function __construct() {}
public function setmessage($message) {
$this->message = $message;
}
public function setperson($person) {
$this->person = $person;
}
public function talk() {
echo $this->person . ' says: ' . $this->message;
}
}
The advantage in the first example is that you can pass as much options as you want and the class will only extract those that it needs.
For example, this could be handy when extracting options from a JSON file:
$options = json_decode($options);
$hello = new Hello($options);
This is how I do this regulary:
$options = json_decode($options);
$hello = new Hello();
if(isset($options['message'])) $hello->setmessage($options['message']);
if(isset($options['person'])) $hello->setperson($options['person']);
Is there a name for this pattern and do you think this is a bad practice?
I have left validation etc. in the examples to keep it simple.
There are good and bad aspects.
The good:
No need for multiple method signatures (i.e. overloading, where supported)
In keeping with the previous point: methods can be invoked with arguments in any order
Arguments can be dynamically generated, without needing to specify each one that will be present (example: you dynamically create an array of arguments based on user input and pass it to the function)
No need for "boilerplate" methods like setName, setThis, setThat, etc., although you might still want to include them
Default values can be defined in the function body, instead of the signature (jQuery uses this pattern a lot. They frequently $.extend the options passed to a method with an array of default values. In your case, you would use array_merge())
The bad:
Unless you properly advertise every option, your class might be harder to use because few will know what options are supported
It's one more step to create an array of arguments when you know ahead of time which you will need to pass
It's not always obvious to the user that default values exist, unless documentation is provided or they have access to the source code
In my opinion, it's a great technique. My favorite aspect is that you don't need to provide overloaded methods with different signatures, and that the signature isn't set in stone.
There's nothing wrong with that approach, especially if you have a lot of parameters you need to pass to a constructor. This also allows you to set default values for them and array_merge() them inside a constructor (kinda like all jQuery plugins do)
protected $default_params = array(
'option1' => 'default_value'
);
public function __construct($params = array()) {
$this->params = array_merge($this->default_params, $params);
}
If you want live examples of this "pattern", check out symfony framework, they use it almost every where: here's an example of sfValidatorBase constructor
When you give the arguments names it's called "Named Notation" v.s. "Positional Notation" where the arguments must be in a specific order.
In PHP you can pass an "options" parameter to give the same effect as other languages (like Python) where you can use a genuine Named Notation. It is not a bad practice, but is often done where there is a good reason to do it (i.e. in your example or a case where there are lots of arguments and they do not all need to set in any particular order).
I don't know the name, but i really doubt it is a bad practice, since you usally use this when you wan't to declare a small o quick function or class property
If there are mandatory options, they should be in the constructor's parameter list. Then you add the optional options with default values.
public function __construc($mandatory1, $mandatory2, $optional1="value", $optional2="value") { }
If all of your options are optional, then it can be useful to create a constructor taking an array. It would be easier to create the object than with a "normal constructor" : you could provide just the options you want, while with a "normal constructor" if you want to provide $optional2, you have to provide $optional1 (even setting it to the default value).
I wouldn't say its bad practice, at least if you trust the source of the data.
Another possibility would be dynamically calling the setters according to the options array key, like the following:
public function __construct($options) {
foreach($options as $option => $value) {
$method = 'set'.$option;
if(method_exists($this, $method)
call_user_func(array($this, $method, $value);
}
}
Why not do both? Have your constructor cake and eat it too with a static factory "named constructor":
$newHello = Hello::createFromArray($options);
You first have your constructor with the options in order. Then add a static method like this to the same class:
public static function createFromArray($options){
$a = isset($options['a']) ? $options['a'] : NULL;
$b = isset($options['b']) ? $options['b'] : NULL;
$c = isset($options['c']) ? $options['c'] : NULL;
return new Hello($a, $b, $c);
}
This will keep new developers and IDE's happy as they can still see what it takes to construct your object.
I agree with the general attitude of the answers here in that either way is a viable solution depending on your needs and which is more beneficial for your app.

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