zend expressive layout variable - php

Zend expressive - Layout
https://github.com/zendframework/zend-expressive-twigrenderer/issues/24
Based on this question, I want to pass a variable to layout from an Action
How can I try to do that?
$toast = [
'level'=>'info',
'msg' =>'rafael',
'url' => null
];
$this->template->addDefaultParam(Template\TemplateRendererInterface::TEMPLATE_ALL,'toast',$this->toastrMessenger->show($toast));
return new HtmlResponse($this->template->render('contentpages::contact',$data));
on my layout/default.phtml
<?php
if ( isset($this->toast) ){
echo $this->toast;
}
?>
</body>
</html>

Did you try "addDefaultParam" method? signeture is;
public function addDefaultParam($templateName, $param, $value)
and you can set star (*) as $templateName (see TemplateRendererInterface::TEMPLATE_ALL) so i think layout can read it.
You can read about it on documentation. Let me know if its working.

Related

Slim - Use variables of a route inside an included file

I'm using Slim 3 to build an application.
In a certain route, I include via include_once the header of the template(slim/php-view 2.2), and there is some variables that I send to the template that I need to use in the header.
Is there a way to do this?
My route:
$app->get('/', function ( $request, $response) {
// some code here...
$somedata = ' this is just a test';
return $this->renderer->render($response, "/home.phtml",[
'somedata' => $somedata,
]);
})
The target template(home.phtml):
<?php include_once('myheader.php'); ?>
<h1>This is my template</h1>
<p> I need to use this variable <?=$somedata?>
in the included myheader.php file</p>
My bad. Reading the docs I found that I can achieve what I want using template variables, like this:
my route:
$templateVariables = [
"title" => "Title"
];
$phpView = new PhpRenderer("./path/to/templates", $templateVariables);
my included file(myheader.php):
<?php echo $title ?>

Yii, Is it good MVC practice to echo in the controller?

It seems like i am not following the MVC design structure.
I'm making an ajax call from my view to a Controller function
Controller
public function actionGetClient()
{
$user = Client::model()->findByAttributes(array('email'=>$_POST['email'], 'password'=>$_POST['pass']));
echo $user->fullname;
}
View (the calling ajax)
CHtml::ajaxLink(
$text = 'get user',
$url = Yii::app()->createUrl('[my controller]/getClient'),
$ajax=array (
'type'=>'POST',
'data' => array('email'=>email, 'pass'=>pass),
'beforeSend' => "function( request )
{
$(\".result\").html(\"fetching...\")
}",
'success'=>"function(data){
$(\".result\").html(\"user is :\"+data)
}
"
));
Is it good to "echo" the $user->fullname inside the controller for the ajax success function to display it? My boss doesn't like it when i print stuff in my controller, how can i approach this
because when i use return instead, the ajax success gets a null value
return $user->fullname;
No,
It's not a good practice.
You need to create a view to use echo.
You can use return $this->renderPartial('VIEW_NAME'); to render a view without Layout.
You should write 'return' instead of 'echo'. 'echo' is not a good practice for ajax response. You don't need to make a new view for just return a name in your case.
public function actionGetClient()
{
$user = Client::model()->findByAttributes(array('email'=>$_POST['email'],'password'=>$_POST['pass']));
return $user->fullname;
}
No. A controller’s supposed to pass its results to a view for rendering.
I would avoid echoing in the controller what we usually do is have a ajax view folder and a json view and render with that so:
public function actionGetClient()
{
$user = Client::model()->findByAttributes(array(
'email'=>$_POST['email'],
'password'=>$_POST['pass']
));
$this->render("json",array("outputData"=>$user));
}
then add this to the controller as well:
public function getViewPath(){
if(Yii::app()->request->isAjaxRequest){
if(($module=$this->getModule())===null)
$module=Yii::app();
return $module->getViewPath().DIRECTORY_SEPARATOR."ajax";
}
return parent::getViewPath();
}
and in the ajax views folder add a json.php file like so
header('Content-Type: application/json');
// output data
echo json_encode($outputData);
please degug the code as I wrote it free hand. You can also set a marker in the controller like $viewPath and set it before the rendering

how to use forward in view zend 2

I want to write a plugin in ZF2,
An example of the plugin is a like button that shows in every post. It should for example print in PostsAction,
I know I can use:
$like = $this->forward()->dispatch('Application\Controller\Index', array(
'action' => 'like',
'postId' => $Id
));
$like variable returns a button that users can click on.
But I want to echo this in the view. In forward the view is not defined.
Also if I use
return $this->getView()->render('application/index/like', array('postId' => $Id));
I don't have access to postId in likeController, because it is set in the view. How I can implement these type of plugins that need a dynamic variables?
Looks like you only need partials. A partial in ZF2 is only a view which you print in another view and give some params to it.
So you could define a View:
// application/partials/button.phtml
<button data-postId="<?php echo $this->postId ?>">Like It!</button>
And use it in other View:
echo $this->partial('application/partials/button.phtml', array(
'postId' => $thePostId
));
Official Documentation
Nice Answer on SO to implement with template_map
Solution using view helper
I think what you are looking for is a custom view helper. You can read on this in the official ZF2 documentation.
You have to write your custom button view helper, register it and then you can use it in your view.
The helper class:
namespace Application\View\Helper;
use Zend\View\Helper\AbstractHelper;
class LikeButtonHelper extends AbstractHelper
{
public function __invoke($post)
{
//return here your button logic, you will have access to $post
}
}
Register your helper within a configuration file:
'view_helpers' => array(
'invokables' => array(
'likeButtonHelper' => 'Application\View\Helper\LikeButtonHelper',
),
)
And finally in the view you can use it like this:
foreach($posts as $post){
echo( ... your code to show the post ...);
echo $this->likeButtonHelper($post);
}
UPDATE - Solution using forward plugin
I think I get what you mean now. I also think the example you are talking about is what in the ZF2 forward plugin documentation is referred to as “widgetized” content.
I think you are doing it correctly. You can attach the return value $like as a child to the view of the original controller (from where you forwarded in the first place).
So in your WidgetController:
use Zend\View\Model\ViewModel;
class WidgetController extends AbstractActionController
{
public function likeAction()
{
$post= $this->params()->fromRoute('post');
$viewModel = new ViewModel(array('post' => $post));
$viewModel->setTemplate('view/widgets/like');
return $viewModel;
}
}
So in your PostController:
use Zend\View\Model\ViewModel;
class PostController extends AbstractActionController
{
public function postsAction()
{
$likeWidget = $this->forward()->dispatch('Application\Controller\WidgetController', array(
'action' => 'like',
'post' => $post
));
$viewModel = new ViewModel();
$viewModel->setTemplate('view/posts/post');
$viewModel = new ViewModel(array(
//...add your other view variables...
));
// Add the result from the forward plugin as child to the view model
if ($likeWidget instanceof ViewModel)
{
$viewModel->addChild($likeWidget , 'likeWidget');
}
return $view;
}
}
And finally in your post view template add:
echo($this->likeWidget);
That is where the widget will eventually output.
The problem remains that you can not do this inside a foreach loop (a loop for printing your posts) in the view. That is why I suggested using a view helper and #copynpaste suggests using a partial, those are more suitable for adding additional logic inside a view.
Note:
Personally I don't like this forward solution for something so simple as a like button. There is hardly any logic in the controller and it seems overly complicated. This is more suitable for reusing a whole view/page that will be both rendered by itself as well as nested in another view.
The partials or view helpers seem much more suitable for what you want to do and those are very proper ZF2 solutions.
I found it ,developed by Mohammad Rostami,Special thanks to him :
Plugin In ZF2

yii - how to create a completely independant extension using nusoap 0.9.5 in yii 1.1.13

SOLVED Thanks to #JPR and tuned-up thanks to #PeterM
/* The only dependance is when */ class NuSoap extends CApplicationComponent
v-Below, the initial question -v
I would like to know how to create a basic extenstion in yii 1.1.13 using nusoap 0.9.5?
My simple code looks like this :
<?php
require("libs/nusoap-0.9.5/lib/nusoap.php");
// namespace
$ns = "https://my-namespace-site";
// client
$client = new soapclient('https://ip-to-webservice-server');
// header
$headers = "<credentials><ns1:username xmlns:ns1=\"$ns\">username</ns1:username>
<ns2:password xmlns:ns2=\"$ns\">password</ns2:password></credentials>";
$client->setHeaders($headers);
// searching
$params = array(
'local_user_array' => array(
'limit' => 10
)
);
$result = $client->call('local_users_search', $params, $ns );
if( $client->getError() ) {
echo $client->getError();
}
else {
foreach( $result['data'] as $offer ) {
echo "<div>".$offer['firstname']."</div>";
}
}
?>
My code works perfectly. Now, what coud I do to use $result in yii to be able to show results in a view?
The best answer will be a concrete example with file structure and code plus meaningful explanations.
Any help would be greatly appreciated. Thanks for your help in advance. I'm looking forward to it ;-)
PS: please do not reference any links to yiiframework site because it doesn't help much as I also know how to search.
Make a class that extends from CApplicationComponent.
class NuSoap extends CApplicationComponent
{
protected $params = array();
protected $client, $ns;
public function init() {
require("libs/nusoap-0.9.5/lib/nusoap.php");
$this->client = new soapclient('https://ip-to-webservice-server');
$this->ns = "https://my-namespace-site";
}
public function getResults() {
$results = $this->client->call(
'local_users_search',
$this->params,
$this->ns
);
return $results;
}
public function setParams(array $params) {
$this->params = $params;
}
// whatever other methods you need for it to work
}
Then in your main config file, under the components array:
array(
'nuSoap' => array(
'class' => 'application.components.NuSoap' // name your class NuSoap.php
)
......
)
Make sure the application/components or application/extensions directory is imported in the main.php config file as well. Put your class file in NuSoap.php in the application/components or applcation/extensions directory.
You can now refer to your component anywhere in your Yii app:
Yii::app()->nuSoap->setParams($params);
$results = Yii::app()->nuSoap->getResults();
This should be plenty to get you started in the right direction. The Yii documentation would be very helpful in understanding how application components work, but since you don't want to read it you'll just have to guess on some things. If you want to use Yii it makes absolutely no sense to avoid reading the documentation.

PHP MVC - adding more Views

I recently implemented the following MVC code using this tiny mvc boilerplate.
I did not want to use Zend or Symfony as I only require a small structure but i really need to expend this one slightly.
I am new to PHP so wondered if anyone has used this or knows how i go about adding another View. I have got the link version working which i use to load my layout but would like to add a Content section within this layout which is able to call other pages.
Any help with this would be great!
Gods below .. that video is horrible.
In that existing example, if you want to add another "view" (which is no really what view is), you will need another method in the controller:
class Controller
{
// -- snip --
// you need to change the constructor too
public function __construct()
{
$this->load = new Load;
$this->model = new Model;
}
// -- snip --
public function gallery()
{
$list = $this->model->get_urls();
if ( count($list) > 0 )
{
$this->load->view('gallery.php' , $list);
}
else
{
$this->load->view('error.php', array(
'source' => 'gallery',
'reason' => 'empty'
));
}
}
// -- snip --
}
And you also would need to change the tinyMvc.php file:
$c = new Controller;
$action = 'home';
if ( isset( $_GET['page']))
{
$action = $_GET['page'];
}
if ( method_exists( $c, $action) )
{
$c->{$action}();
}
else
{
echo 'no such action !';
}
Anyway. Whole that "tutorial" uses the terms of MVC, that isn't really whats made there. His "view" is actually just a simple template. Which is not completely a thing to learn how to do for a beginner, but his implementation sucked too .. If you want to learn how to make simple native php templates, you might find this article quite useful.

Categories