Compare dates in different years php [duplicate] - php

How can I compare two dates in PHP?
The date is stored in the database in the following format
2011-10-2
If I wanted to compare today's date against the date in the database to see which one is greater, how would I do it?
I tried this,
$today = date("Y-m-d");
$expire = $row->expireDate //from db
if($today < $expireDate) { //do something; }
but it doesn't really work that way. What's another way of doing it?

If all your dates are posterior to the 1st of January of 1970, you could use something like:
$today = date("Y-m-d");
$expire = $row->expireDate; //from database
$today_time = strtotime($today);
$expire_time = strtotime($expire);
if ($expire_time < $today_time) { /* do Something */ }
If you are using PHP 5 >= 5.2.0, you could use the DateTime class:
$today_dt = new DateTime($today);
$expire_dt = new DateTime($expire);
if ($expire_dt < $today_dt) { /* Do something */ }
Or something along these lines.

in the database the date looks like this 2011-10-2
Store it in YYYY-MM-DD and then string comparison will work because '1' > '0', etc.

Just to compliment the already given answers, see the following example:
$today = new DateTime('');
$expireDate = new DateTime($row->expireDate); //from database
if($today->format("Y-m-d") < $expireDate->format("Y-m-d")) {
//do something;
}
Update:
Or simple use old-school date() function:
if(date('Y-m-d') < date('Y-m-d', strtotime($expire_date))){
//echo not yet expired!
}

I would'nt do this with PHP.
A database should know, what day is today.( use MySQL->NOW() for example ), so it will be very easy to compare within the Query and return the result, without any problems depending on the used Date-Types
SELECT IF(expireDate < NOW(),TRUE,FALSE) as isExpired FROM tableName

$today = date('Y-m-d');//Y-m-d H:i:s
$expireDate = new DateTime($row->expireDate);// From db
$date1=date_create($today);
$date2=date_create($expireDate->format('Y-m-d'));
$diff=date_diff($date1,$date2);
//echo $timeDiff;
if($diff->days >= 30){
echo "Expired.";
}else{
echo "Not expired.";
}

Here's a way on how to get the difference between two dates in minutes.
// set dates
$date_compare1= date("d-m-Y h:i:s a", strtotime($date1));
// date now
$date_compare2= date("d-m-Y h:i:s a", strtotime($date2));
// calculate the difference
$difference = strtotime($date_compare1) - strtotime($date_compare2);
$difference_in_minutes = $difference / 60;
echo $difference_in_minutes;

You can convert the dates into UNIX timestamps and compare the difference between them in seconds.
$today_date=date("Y-m-d");
$entered_date=$_POST['date'];
$dateTimestamp1 = strtotime($today_date);
$dateTimestamp2 = strtotime($entered_date);
$diff= $dateTimestamp1-$dateTimestamp2;
//echo $diff;
if ($diff<=0)
{
echo "Enter a valid date";
}

I had that problem too and I solve it by:
$today = date("Ymd");
$expire = str_replace('-', '', $row->expireDate); //from db
if(($today - $expire) > $NUMBER_OF_DAYS)
{
//do something;
}

Here's my spin on how to get the difference in days between two dates with PHP.
Note the use of '!' in the format to discard the time part of the dates, thanks to info from DateTime createFromFormat without time.
$today = DateTime::createFromFormat('!Y-m-d', date('Y-m-d'));
$wanted = DateTime::createFromFormat('!d-m-Y', $row["WANTED_DELIVERY_DATE"]);
$diff = $today->diff($wanted);
$days = $diff->days;
if (($diff->invert) != 0) $days = -1 * $days;
$overdue = (($days < 0) ? true : false);
print "<!-- (".(($days > 0) ? '+' : '').($days).") -->\n";

Found the answer on a blog and it's as simple as:
strtotime(date("Y"."-01-01")) -strtotime($newdate))/86400
And you'll get the days between the 2 dates.

This works because of PHP's string comparison logic. Simply you can check...
if ($startdate < $date) {// do something}
if ($startdate > $date) {// do something}
Both dates must be in the same format. Digits need to be zero-padded to the left and ordered from most significant to least significant. Y-m-d and Y-m-d H:i:s satisfy these conditions.

If you want a date ($date) to get expired in some interval for example a token expiration date when performing a password reset, here's how you can do:
$date = $row->expireDate;
$date->add(new DateInterval('PT24H')); // adds 24 hours
$now = new \DateTime();
if($now < $date) { /* expired after 24 hours */ }
But in your case you could do the comparison just as the following:
$today = new DateTime('Y-m-d');
$date = $row->expireDate;
if($today < $date) { /* do something */ }

first of all, try to give the format you want to the current date time of your server:
Obtain current date time
$current_date = getdate();
Separate date and time to manage them as you wish:
$current_date_only = $current_date[year].'-'.$current_date[mon].'-'.$current_date[mday];
$current_time_only = $current_date['hours'].':'.$current_date['minutes'].':'.$current_date['seconds'];
Compare it depending if you are using donly date or datetime in your DB:
$today = $current_date_only.' '.$current_time_only;
or
$today = $current_date_only;
if($today < $expireDate)
hope it helps

Related

PHP Dates Condition [duplicate]

How can I compare two dates in PHP?
The date is stored in the database in the following format
2011-10-2
If I wanted to compare today's date against the date in the database to see which one is greater, how would I do it?
I tried this,
$today = date("Y-m-d");
$expire = $row->expireDate //from db
if($today < $expireDate) { //do something; }
but it doesn't really work that way. What's another way of doing it?
If all your dates are posterior to the 1st of January of 1970, you could use something like:
$today = date("Y-m-d");
$expire = $row->expireDate; //from database
$today_time = strtotime($today);
$expire_time = strtotime($expire);
if ($expire_time < $today_time) { /* do Something */ }
If you are using PHP 5 >= 5.2.0, you could use the DateTime class:
$today_dt = new DateTime($today);
$expire_dt = new DateTime($expire);
if ($expire_dt < $today_dt) { /* Do something */ }
Or something along these lines.
in the database the date looks like this 2011-10-2
Store it in YYYY-MM-DD and then string comparison will work because '1' > '0', etc.
Just to compliment the already given answers, see the following example:
$today = new DateTime('');
$expireDate = new DateTime($row->expireDate); //from database
if($today->format("Y-m-d") < $expireDate->format("Y-m-d")) {
//do something;
}
Update:
Or simple use old-school date() function:
if(date('Y-m-d') < date('Y-m-d', strtotime($expire_date))){
//echo not yet expired!
}
I would'nt do this with PHP.
A database should know, what day is today.( use MySQL->NOW() for example ), so it will be very easy to compare within the Query and return the result, without any problems depending on the used Date-Types
SELECT IF(expireDate < NOW(),TRUE,FALSE) as isExpired FROM tableName
$today = date('Y-m-d');//Y-m-d H:i:s
$expireDate = new DateTime($row->expireDate);// From db
$date1=date_create($today);
$date2=date_create($expireDate->format('Y-m-d'));
$diff=date_diff($date1,$date2);
//echo $timeDiff;
if($diff->days >= 30){
echo "Expired.";
}else{
echo "Not expired.";
}
Here's a way on how to get the difference between two dates in minutes.
// set dates
$date_compare1= date("d-m-Y h:i:s a", strtotime($date1));
// date now
$date_compare2= date("d-m-Y h:i:s a", strtotime($date2));
// calculate the difference
$difference = strtotime($date_compare1) - strtotime($date_compare2);
$difference_in_minutes = $difference / 60;
echo $difference_in_minutes;
You can convert the dates into UNIX timestamps and compare the difference between them in seconds.
$today_date=date("Y-m-d");
$entered_date=$_POST['date'];
$dateTimestamp1 = strtotime($today_date);
$dateTimestamp2 = strtotime($entered_date);
$diff= $dateTimestamp1-$dateTimestamp2;
//echo $diff;
if ($diff<=0)
{
echo "Enter a valid date";
}
I had that problem too and I solve it by:
$today = date("Ymd");
$expire = str_replace('-', '', $row->expireDate); //from db
if(($today - $expire) > $NUMBER_OF_DAYS)
{
//do something;
}
Here's my spin on how to get the difference in days between two dates with PHP.
Note the use of '!' in the format to discard the time part of the dates, thanks to info from DateTime createFromFormat without time.
$today = DateTime::createFromFormat('!Y-m-d', date('Y-m-d'));
$wanted = DateTime::createFromFormat('!d-m-Y', $row["WANTED_DELIVERY_DATE"]);
$diff = $today->diff($wanted);
$days = $diff->days;
if (($diff->invert) != 0) $days = -1 * $days;
$overdue = (($days < 0) ? true : false);
print "<!-- (".(($days > 0) ? '+' : '').($days).") -->\n";
Found the answer on a blog and it's as simple as:
strtotime(date("Y"."-01-01")) -strtotime($newdate))/86400
And you'll get the days between the 2 dates.
This works because of PHP's string comparison logic. Simply you can check...
if ($startdate < $date) {// do something}
if ($startdate > $date) {// do something}
Both dates must be in the same format. Digits need to be zero-padded to the left and ordered from most significant to least significant. Y-m-d and Y-m-d H:i:s satisfy these conditions.
If you want a date ($date) to get expired in some interval for example a token expiration date when performing a password reset, here's how you can do:
$date = $row->expireDate;
$date->add(new DateInterval('PT24H')); // adds 24 hours
$now = new \DateTime();
if($now < $date) { /* expired after 24 hours */ }
But in your case you could do the comparison just as the following:
$today = new DateTime('Y-m-d');
$date = $row->expireDate;
if($today < $date) { /* do something */ }
first of all, try to give the format you want to the current date time of your server:
Obtain current date time
$current_date = getdate();
Separate date and time to manage them as you wish:
$current_date_only = $current_date[year].'-'.$current_date[mon].'-'.$current_date[mday];
$current_time_only = $current_date['hours'].':'.$current_date['minutes'].':'.$current_date['seconds'];
Compare it depending if you are using donly date or datetime in your DB:
$today = $current_date_only.' '.$current_time_only;
or
$today = $current_date_only;
if($today < $expireDate)
hope it helps

Date Variables not working as accepted in php? [duplicate]

How can I compare two dates in PHP?
The date is stored in the database in the following format
2011-10-2
If I wanted to compare today's date against the date in the database to see which one is greater, how would I do it?
I tried this,
$today = date("Y-m-d");
$expire = $row->expireDate //from db
if($today < $expireDate) { //do something; }
but it doesn't really work that way. What's another way of doing it?
If all your dates are posterior to the 1st of January of 1970, you could use something like:
$today = date("Y-m-d");
$expire = $row->expireDate; //from database
$today_time = strtotime($today);
$expire_time = strtotime($expire);
if ($expire_time < $today_time) { /* do Something */ }
If you are using PHP 5 >= 5.2.0, you could use the DateTime class:
$today_dt = new DateTime($today);
$expire_dt = new DateTime($expire);
if ($expire_dt < $today_dt) { /* Do something */ }
Or something along these lines.
in the database the date looks like this 2011-10-2
Store it in YYYY-MM-DD and then string comparison will work because '1' > '0', etc.
Just to compliment the already given answers, see the following example:
$today = new DateTime('');
$expireDate = new DateTime($row->expireDate); //from database
if($today->format("Y-m-d") < $expireDate->format("Y-m-d")) {
//do something;
}
Update:
Or simple use old-school date() function:
if(date('Y-m-d') < date('Y-m-d', strtotime($expire_date))){
//echo not yet expired!
}
I would'nt do this with PHP.
A database should know, what day is today.( use MySQL->NOW() for example ), so it will be very easy to compare within the Query and return the result, without any problems depending on the used Date-Types
SELECT IF(expireDate < NOW(),TRUE,FALSE) as isExpired FROM tableName
$today = date('Y-m-d');//Y-m-d H:i:s
$expireDate = new DateTime($row->expireDate);// From db
$date1=date_create($today);
$date2=date_create($expireDate->format('Y-m-d'));
$diff=date_diff($date1,$date2);
//echo $timeDiff;
if($diff->days >= 30){
echo "Expired.";
}else{
echo "Not expired.";
}
Here's a way on how to get the difference between two dates in minutes.
// set dates
$date_compare1= date("d-m-Y h:i:s a", strtotime($date1));
// date now
$date_compare2= date("d-m-Y h:i:s a", strtotime($date2));
// calculate the difference
$difference = strtotime($date_compare1) - strtotime($date_compare2);
$difference_in_minutes = $difference / 60;
echo $difference_in_minutes;
You can convert the dates into UNIX timestamps and compare the difference between them in seconds.
$today_date=date("Y-m-d");
$entered_date=$_POST['date'];
$dateTimestamp1 = strtotime($today_date);
$dateTimestamp2 = strtotime($entered_date);
$diff= $dateTimestamp1-$dateTimestamp2;
//echo $diff;
if ($diff<=0)
{
echo "Enter a valid date";
}
I had that problem too and I solve it by:
$today = date("Ymd");
$expire = str_replace('-', '', $row->expireDate); //from db
if(($today - $expire) > $NUMBER_OF_DAYS)
{
//do something;
}
Here's my spin on how to get the difference in days between two dates with PHP.
Note the use of '!' in the format to discard the time part of the dates, thanks to info from DateTime createFromFormat without time.
$today = DateTime::createFromFormat('!Y-m-d', date('Y-m-d'));
$wanted = DateTime::createFromFormat('!d-m-Y', $row["WANTED_DELIVERY_DATE"]);
$diff = $today->diff($wanted);
$days = $diff->days;
if (($diff->invert) != 0) $days = -1 * $days;
$overdue = (($days < 0) ? true : false);
print "<!-- (".(($days > 0) ? '+' : '').($days).") -->\n";
Found the answer on a blog and it's as simple as:
strtotime(date("Y"."-01-01")) -strtotime($newdate))/86400
And you'll get the days between the 2 dates.
This works because of PHP's string comparison logic. Simply you can check...
if ($startdate < $date) {// do something}
if ($startdate > $date) {// do something}
Both dates must be in the same format. Digits need to be zero-padded to the left and ordered from most significant to least significant. Y-m-d and Y-m-d H:i:s satisfy these conditions.
If you want a date ($date) to get expired in some interval for example a token expiration date when performing a password reset, here's how you can do:
$date = $row->expireDate;
$date->add(new DateInterval('PT24H')); // adds 24 hours
$now = new \DateTime();
if($now < $date) { /* expired after 24 hours */ }
But in your case you could do the comparison just as the following:
$today = new DateTime('Y-m-d');
$date = $row->expireDate;
if($today < $date) { /* do something */ }
first of all, try to give the format you want to the current date time of your server:
Obtain current date time
$current_date = getdate();
Separate date and time to manage them as you wish:
$current_date_only = $current_date[year].'-'.$current_date[mon].'-'.$current_date[mday];
$current_time_only = $current_date['hours'].':'.$current_date['minutes'].':'.$current_date['seconds'];
Compare it depending if you are using donly date or datetime in your DB:
$today = $current_date_only.' '.$current_time_only;
or
$today = $current_date_only;
if($today < $expireDate)
hope it helps

how to understand if one date in php is less than another minus one day?

how to understand if one date in php is less than another minus one day? I mean if for example a date is set to "2018/07/03"; how can I understand if a given date is less than "2018/07/02"
date1 : year1/month1/day1
date2: year2/month2/day2
<?php
if ($year1 >= $year2) {
if ($month1 >= $month2) {
if (($day1 - 1) > $day2) {
echo 'you could do something..';
}
}
}
?>
the above code fails if forexample $year2 = 2017 and $month2 = 11.. can anybody help me? thanks a lot..
Here, this should work.
$date_to_check = new DateTime($yesterday);
$today = new DateTime();
$time_diff = $today->diff($date_to_check)->d;
if($time_diff > 1) {
echo "This is greater than one day.";
}else{
echo "This is not greater than one day.";
$date = strtotime("2018/07/01");
$date2 = strtotime("2018/07/02");
if($date > $date2){
print('date is bigger');
// do stuff when date is bigger than date2
} else {
// else ...
print('date2 is bigger');
}
To convert string to date php has function named strtotime().
Compairing date objects is simple.
There is full information about strtotime()
http://php.net/manual/ru/function.strtotime.php
Another way:
$date = new DateTime("2018/07/01");
$date2 = new DateTime("2018/07/02");
if($date->modify("+1day") > $date2){
print('date is bigger');
// do stuff when date is bigger than date2
} else {
// else ...
print('date2 is bigger or equal');
}
Notice modify modifies $date object itself.
Read more here http://php.net/manual/en/class.datetime.php

Comparing in PHP if today is between 2 different dates if so then print a value

I am new in php.
I have 2 dates that I am getting from 2 drupal fields and each field is saved in database with it´s own date format so the formats:
$old_format_starts -> has this date format: date('Y-m-d H:i:s'); and
$old_format_ends -> has this date format: date('jS F Y H:i:s');
So I am using the following code:
$old_format_starts = $entity->field_video_available_d[LANGUAGE_NONE][0]['value'];
$old_format_ends = $entity->field_video_until[LANGUAGE_NONE][0]['value'];
After that, I am converting those date information to this date format: date('Y-m-d'); like this:
$starts = date("Y-m-d", strtotime($old_format_starts));
$ends = date('Y-m-d', strtotime($old_format_ends));
In order later I can use that information for comparing if today is between the dates $starts and &ends, and if today is between those dates then I will print something.
So here is the total code that I am using, but I have problems with the date formats... something I am doing wrong because the page is just taking long time in load the page and in the end it does not load.... The problem is coming when I am using the WHILE bucle, because I tried just using the code before the WHILE and the page loads in a normal way. So I dont know If I am using wrong the WHILE BUCLE or the strtotime function or dates format...?
<?php
$old_format_starts = $entity->field_video_available_d[LANGUAGE_NONE][0]['value'];
$old_format_ends = $entity->field_video_until[LANGUAGE_NONE][0]['value'];
$starts = date("Y-m-d", strtotime($old_format_starts));
$ends = date('Y-m-d', strtotime($old_format_ends));
$to= date("Y-m-d", strtotime($to));
$i = date("Y-m-d", strtotime($starts));
while ($i <= $ends) {
if ($i==$to) {
print date('Y-m-d', strtotime($i));
break;
}
$i=date("Y-m-d", strtotime('+1 day', $i));
}
?>
I really have tried already many ways.. but without success.... here is the same code but using the FOR bucle... and also without success..
<?php
$old_format_starts = $entity->field_video_available_d[LANGUAGE_NONE][0]['value'];
$old_format_ends = $entity->field_video_until[LANGUAGE_NONE][0]['value'];
$starts = date("Y-m-d", strtotime($old_format_starts));
$ends = date('Y-m-d', strtotime($old_format_ends));
$to= date("Y-m-d");
for ($i = $starts; $i <= $ends; $i++) {
if ($i==$to) {
print $i;
break;
}
}
?>
PLEASE HELP!!!! Any sugestion is welcome!!! There has to be a solution... Something I am doing wrong in the bucles (While) or (FOR) because the page is not loading!!!
Thank you!!! :)
If you compared the strtotime() values directly, it would work. strtotime() returns simple integers and >/</= type comparisons will work as expected. In your code, you're converting them to strings using date(), in a least-significant-value-first ordering, so your comparisons won't work as expected.
Comparing the dates using strtotime():
$start = strtotime($old_format_starts);
$end = strtotime($old_format_ends);
$today = time();
if ($today > $start && $today < $end) {
// code
}
Comparing the dates using the DateTime class:
$start = new DateTime($old_format_starts);
$end = new DateTime($old_format_ends);
if ($today > $start && $today < $end) {
// code
}
Once the comparison is over, you can format the date strings using date() function (if you're using strtotime()) or the format() method (if you're using DateTime class).
The while loop is not necessary here
I suggest the use of the DateTime native class like this :
$old_format_starts = $entity->field_video_available_d[LANGUAGE_NONE][0]['value'];
$old_format_ends = $entity->field_video_until[LANGUAGE_NONE][0]['value'];
$starts = DateTime::createFromFormat('Y-m-d H:i:s', $old_format_starts);
$ends = DateTime::createFromFormat('jS F Y H:i:s', $old_format_ends);
$today = new DateTime() ;
if(($today > $start) && ($today < $end)){
//Do your thing
}

Calculating age from date of birth in PHP

What's the most precise function you have come across to work out an age from the users date of birth. I have the following code and was wondering how it could be improved as it doesn't support all date formats and not sure if it's the most accurate function either (DateTime compliance would be nice).
function getAge($birthday) {
return floor((strtotime(date('d-m-Y')) - strtotime($date))/(60*60*24*365.2421896));
}
$birthday = new DateTime($birthday);
$interval = $birthday->diff(new DateTime);
echo $interval->y;
Should work
Check this
<?php
$c= date('Y');
$y= date('Y',strtotime('1988-12-29'));
echo $c-$y;
?>
Use this code to have full age including years, months and days-
<?php
//full age calulator
$bday = new DateTime('02.08.1991');//dd.mm.yyyy
$today = new DateTime('00:00:00'); // Current date
$diff = $today->diff($bday);
printf('%d years, %d month, %d days', $diff->y, $diff->m, $diff->d);
?>
Try using DateTime for this:
$now = new DateTime();
$birthday = new DateTime('1973-04-18 09:48:00');
echo $now->diff($birthday)->format('%y years'); // 49 years
See it in action
This works:
<?
$date = date_create('1984-10-26');
$interval = $date->diff(new DateTime);
echo $interval->y;
?>
If you tell me in what format your $birthday variable comes I will give you exact solution
WTF?
strtotime(date('d-m-Y'))
So you generate a date string from the current timestamp, then convert the date string back into a timestamp?
BTW, one of the reasons it's not working is that strtotime() assumes numeric dates to be in the format m/d/y (i.e. the US format of date first). Another reason is that the parameter ($birthday) is not used in the formula.
Change the $date to $birthday.
For supper accuracy you need to account for the leap year factor:
function get_age($dob_day,$dob_month,$dob_year){
$year = gmdate('Y');
$month = gmdate('m');
$day = gmdate('d');
//seconds in a day = 86400
$days_in_between = (mktime(0,0,0,$month,$day,$year) - mktime(0,0,0,$dob_month,$dob_day,$dob_year))/86400;
$age_float = $days_in_between / 365.242199; // Account for leap year
$age = (int)($age_float); // Remove decimal places without rounding up once number is + .5
return $age;
}
So use:
echo get_date(31,01,1985);
or whatever...
N.B. To see your EXACT age to the decimal
return $age_float
instead.
This function works fine.
function age($birthday){
list($day,$month,$year) = explode("/",$birthday);
$year_diff = date("Y") - $year;
$month_diff = date("m") - $month;
$day_diff = date("d") - $day;
if ($day_diff < 0 && $month_diff==0){$year_diff--;}
if ($day_diff < 0 && $month_diff < 0){$year_diff--;}
return $year_diff;
}
See BLOG Post
Here is my long/detailed version (you can make it shorter if you want):
$timestamp_birthdate = mktime(9, 0, 0, $birthdate_month, $birthdate_day, $birthdate_year);
$timestamp_now = time();
$difference_seconds = $timestamp_now-$timestamp_birthdate;
$difference_minutes = $difference_seconds/60;
$difference_hours = $difference_minutes/60;
$difference_days = $difference_hours/24;
$difference_years = $difference_days/365;

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