PHP and Mysql trying to run code on DB [duplicate] - php

Question

This question already has answers here:
mysqli_real_escape_string not working properly
(2 answers)
Closed 5 years ago.
Good Day
I am new to html, php I am trying to set up a page to run a sql query to move data from one table into another one. The trouble I am having is that I require a user to input a date that needs to pass to the query.
I have checked on the net and viewed the question that this is marked as a duplicate of. And am still unable to get this working.
My Html is as follows for the submit part.
<div class = "boxed">
<p> First Date to be used for comparasion</p>
<form method="post">
Date1: <input type="text" name="date1"/>
<input type="Submit" value="submit"/>
</form>
</div>
My Php is
<?php
session_start();
include_once 'include/dbconf.php';
if(isset($_POST['date1']))
$d1 = mysqli_real_escape_string($_POST['date1']);
$sql1 = "insert ignore into compare2 SELECT * FROM Compare where Date =
'$d1'";
$sqldata = mysqli_query($sql1,$conn) or die ('error updaing Table');
echo "Table updated";
mysql_close($con)
?>
My include/dbconfig.php works as I use it on another page and connect succesfully to the DB.
It looks like my query doesn't get the user defined input passed to it.
I don't get any errors either in the httpd error.log.
You advise and help would be most appreciated.
Updated PHP
<?php
session_start();
include_once 'include/dbconf.php';
if(isset($_POST['date1']))
{
$d1 = mysqli_real_escape_string($conn, $_POST['date1']);
$sql1 = "insert ignore into compare2 SELECT * FROM Compare where Date =
'$d1'";
$sqldata = mysqli_query($conn, $sql1) or die ('error updaing Table');
echo "Table updated";
}
mysqli_close($conn)
?>
Still not running the sql to update the table.

Answer 1

Change your code to:
session_start();
include_once 'include/dbconf.php';
if(isset($_POST['date1'])) {
$d1 = mysqli_real_escape_string($conn, $_POST['date1']);
$sql1 = "insert ignore into compare2 SELECT * FROM Compare where Date = '$d1'";
$sqldata = mysqli_query($conn, $sql1) or die ('error updaing Table');
echo "Table updated";
}
mysql_close($con);