INSERT data in table with result of a SELECT - php

I'm trying to populate a table with the result of a select, but I always get the following error :
Duplicate entry '0' for key 'PRIMARY' SQL=INSERT INTO fab_bloquer_jours ( id,day,date ) VALUES ( '','4','2017-12-04 14:55:49' )
My table fab_bloquer_jours is :
1 id Primary int(11)
2 day int(13)
3 date datetime
My query is :
$day=$data['fab_bloquer_jours___day'];
$query = $db->getQuery(true);
$query = "INSERT INTO fab_bloquer_jours (day)
SELECT *
FROM (
SELECT DATE_ADD('2018-01-01',
INTERVAL n4.num*1000+n3.num*100+n2.num*10+n1.num DAY ) AS DATE
FROM (
SELECT 0 AS num
UNION ALL SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3
UNION ALL SELECT 4
UNION ALL SELECT 5
UNION ALL SELECT 6
UNION ALL SELECT 7
UNION ALL SELECT 8
UNION ALL SELECT 9
) AS n1,
(
SELECT 0 AS num
UNION ALL SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3
UNION ALL SELECT 4
UNION ALL SELECT 5
UNION ALL SELECT 6
UNION ALL SELECT 7
UNION ALL SELECT 8
UNION ALL SELECT 9
) AS n2,
(
SELECT 0 AS num
UNION ALL SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3
UNION ALL SELECT 4
UNION ALL SELECT 5
UNION ALL SELECT 6
UNION ALL SELECT 7
UNION ALL SELECT 8
UNION ALL SELECT 9
) AS n3,
(
SELECT 0 AS num
UNION ALL SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3
UNION ALL SELECT 4
UNION ALL SELECT 5
UNION ALL SELECT 6
UNION ALL SELECT 7
UNION ALL SELECT 8
UNION ALL SELECT 9
) AS n4
) AS a
WHERE DATE >= '2018-01-01' AND DATE < '2019-01-01'
AND WEEKDAY(DATE) = '$day'";
$db->setQuery($query);
$query=$db->execute();
I get the $date value through a dropdown.
I would appreciate some help here, since I can't figure out how to make it work.

Remove Id and it's empty value, see below:
INSERT INTO `fab_bloquer_jours` (`day`,`date`) VALUES ('4','2017-12-04 14:55:49');
On your second query, the select statement is wrong. You're trying to insert into one column, but your select statement is saying select all. Anything you make for select statement must be inside of brackets and as one column. e.g.
INSERT INTO fab_bloquer_jours (day) VALUES (your SELECT COLUMNNAME FROM TABLE)

Try setting your id column on your table to auto increment. Then do not include it on your insert statement.
So, for your example, try this query after you update your id field to auto increment:
INSERT INTO fab_bloquer_jours (day,date) VALUES ('4','2017-12-04 14:55:49');

Related

PHP How to query missing values between two numbers?

Hello i have mysql table which named numbers like this;
ID
Number
1
3002
2
3004
2000
7545
When i need to insert a new data products table i have to find first number which is not on this table between(3000 to 35000). I mean i need to find first number between this numbers not on numbers table. How can i find it?
$statement = $con->prepare("SELECT * FROM numbers");
$statement->execute();
$result = $statement->fetchAll(PDO::FETCH_ASSOC);
foreach($result as $row)
{
$arr1[] = $row['numbers'];
}
$arr2 = range(3000,35000);
$missing_numbers = array_diff($arr2,$arr1);
print_r($missing_numbers);
i tried array_diff but i gives results with different keys. When i write $missing_numbers[0] i want to see first missing number.
If you just want the first missing number, it may be easier to read the rows in number order and check for the first one which isn't in the sequence you are after. So a query (with the start and end points as parameters) order by the number and a counter which is what it's expecting to get on each row...
$startPoint = 3000;
$endPoint = 35000;
$statement = $db->prepare("SELECT number
FROM numbers
WHERE number >= :start
and number <= :end
order by number");
$statement->execute([
'start' => $startPoint,
'end' => $endPoint
]);
$expected = $startPoint;
while ($row = $statement->fetch()) {
if ( $row['number'] != $expected ) {
echo "Missing=" . $expected;
break;
}
$expected++;
}
I think your solution will work only thing missing is reordering of the indexes which can be done by using the array_values() function. Update your last lines of code as -
$missing_numbers = array_values(array_diff($arr2,$arr1));
print_r($missing_numbers);
so on printing $missing_numbers[0] you should get the first missing number.
Easy, just need reset keys after array_diff:
...
$missing_numbers = array_values(missing_numbers);
print_r($missing_numbers);
IF you want do it only by using MySQL query and later get the result in PHP you need to do something like this :
Create temporray table with your example :
create table test123(id integer, Number varchar(100))
#insert into test123 (ID, Number) values (1, '3002');
#insert into test123 (ID, Number) values (2, '3004');
#insert into test123 (ID, Number) values (2000, '7545');
CREATE TEMPORARY TABLE WITH RANGE 3000 - 35000
CREATE TEMPORARY TABLE IF NOT EXISTS tableTest AS (
SELECT #row := #row + 1 AS row FROM
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t2,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t3,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t4,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t5,
(SELECT #row:=3000) numbers WHERE #row < 35000
)
AND FINALLY you can just select numbers that's not inside your table with data
select * from tableTest t where t.row not in ( select Number from test123)
The output will be select all numbers as you wanted.

How to separate the row value one by one with count function option in mysql

Mysql Table:
In My facility table is this
facility_name mbid date
yoga,aerobics,table tennis,tai chi, OM1111 2016-06-12
aerobics,tai chi, OM1111 2016-06-12
How to split row value one by one with mbid in mysql:
Facility_name mbid Number of count
yoga OM1111 1
aerobics OM1111 2
table tennis OM1111 1
tai chi OM1111 2
CREATE TABLE facility
(facility_name varchar(35), mbid varchar(6), date varchar(10))
;
INSERT INTO facility
(facility_name, mbid, date)
VALUES
('yoga,aerobics,table tennis,tai chi,', 'OM1111', '2016-06-12'),
('aerobics,tai chi,', 'OM1111', '2016-06-12')
;
Script :
Select T.VALUE,T.mbid,COUNT(T.VALUE)Cnt FROM (
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(t.facility_name, ',', n.n), ',', -1) value,mbid
FROM facility t CROSS JOIN
(
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE n.n <= 1 + (LENGTH(t.facility_name) - LENGTH(REPLACE(t.facility_name, ',', ''))))T
WHERE T.VALUE <> ''
GROUP BY T.VALUE,T.mbid
ORDER BY T.value
How to pass the date function in where condition to get count of activity :
Select facility.mbid,membership.name,membership.organization,
membership.designation,membership.division, facility.VALUE `Facility Name`,
COUNT(facility.VALUE)`Number of Activite` FROM ( SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(facility.facility_name, ',', n.n), ',', -1) value,mbid FROM facility CROSS JOIN
(
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE n.n <= 1 + (LENGTH(facility.facility_name) -LENGTH(REPLACE(facility.facility_name, ',', ''))))T
facility Inner Join membership ON facility.mbid=membership.mbid
where facility.date Between '2016-06-04' and '2016-06-07' &&
facility.VALUE <> ''
GROUP BY facility.VALUE,facility.mbid ORDER BY facility.value
You have a very poor database structure. You should have one row per mbid and facility_name. In fact, I have no idea why mbid and date are the same in the two rows.
If I assume that you have facility names in another table, then you can use:
select fn.facility_name, f.mbid, count(*)
from facility f join
facility_names fn
on find_in_set(fn.facility_name, f.facility) > 0
group by fn.facility_name, f.mbid;
I should emphasize, though, that although you can do a query like this, you really need to fix your data structure. Storing lists of values in a string is the wrong way to store data in a SQL database.

Mysql same row copy-same table 120 times

Simple mysql table:
CREATE TABLE `users` (
`id` INT NOT NULL AUTO_INCREMENT ,
`name` TEXT NOT NULL ,
`surname` text NOT NULL ,
`city` text NOT NULL ,
PRIMARY KEY ( `id` )
) ENGINE = MYISAM
And inserted like:
INSERT INTO `users` (`id`, `name`, `surname`, `city`) VALUES (1,`rock`,`fixed`,`london`);
How can i enter same table detail of one row 100 times with different primary id?
with php you can do it this way:
for($i=0; $i< 119; $i++)
{
//execute your query here, do not include your id column
INSERT INTO `users` (`name`, `surname`, `city`)
VALUES (`rock`,`fixed`,`london`);
}
OR
You can also do it with a mysql store procedure like:
//Loop stored procedure
DELIMITER $$
DROP PROCEDURE IF EXISTS test$$
CREATE PROCEDURE test()
BEGIN
DECLARE count INT DEFAULT 0;
WHILE count < 119 DO
INSERT INTO `users` (`name`, `surname`, `city`)
VALUES (`rock`,`fixed`,`london`);
SET count = count + 1;
END WHILE;
END$$
DELIMITER ;
execute the stored procedure
call test();
EDIT BASED ON COMMENTS:
Your code is not working because you are executing your query "outside" the loop, you code should look like this:
<?php
*/here mysql connection
for($x=0; $x<100; $x++)
{
$sql =INSERT INTO users (name, surname, city)
VALUES (rock,fixed,london);
$status = $conn->query($sql);
}
if ($status)
{ echo "New record created successfully"; }
else { echo "Error: " . $sql . "<br>" . $conn->error; }
$conn->close();
?>
try the following code
for ($i=0; $i<= 119; $i++){
//exclude id and do auto increament and primary key
$qry = "INSERT INTO `users` (`name`, `surname`, `city`) VALUES (`rock`,`fixed`,`london`)";
}
Doing it as a single SQL statement with no loop:-
INSERT INTO `users` (`id`, `name`, `surname`, `city`) VALUES (1,`rock`,`fixed`,`london`);
SELECT NULL, `rock`, `fixed`, `london`
FROM
(
SELECT 0 AS aCnt UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
) units
CROSS JOIN
(
SELECT 0 AS aCnt UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10 UNION SELECT 11
) tens
The 2 sub queries just return ranges of numbers. With 10 in one and 12 in the other when cross joined they will return in total 120 rows. Those 120 rows are just your fixed values, but with NULL for the id which the auto increment will sort out into a unique value.
Note that you can do larger ranges like this. For example if you wanted to insert 653 rows (just a fairly random choice of number):-
SELECT NULL, `rock`, `fixed`, `london`
FROM
(
SELECT 0 AS aCnt UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
) units
CROSS JOIN
(
SELECT 0 AS aCnt UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
) tens
CROSS JOIN
(
SELECT 0 AS aCnt UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
) hundreds
WHERE (units.aCnt + 10 * tens.aCnt + 100 * hundreds.aCnt) < 653
Or specifying the id field as the calculated value:-
SELECT 1 + units.aCnt + 10 * tens.aCnt + 100 * hundreds.aCnt, `rock`, `fixed`, `london`
FROM
(
SELECT 0 AS aCnt UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
) units
CROSS JOIN
(
SELECT 0 AS aCnt UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
) tens
CROSS JOIN
(
SELECT 0 AS aCnt UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
) hundreds
WHERE (units.aCnt + 10 * tens.aCnt + 100 * hundreds.aCnt) < 653
Since the id has the property AUTO_INCREMENT this should generate a unique ID every time you enter data.
So your insert string can be like this:
INSERT INTO `users` (`name`, `surname`, `city`) VALUES (`rock`, `fixed`, `london`);
The id field will then auto-increment each time, giving you unique IDs
Just Use this query:
INSERT INTO users ( name, surname, city) VALUES ('rock','fixed','london');

Count unique id separeted by commas in single row

I have the following details in MySQL as
user_id follow_user_id
1 2,3,3,3,3
5 1,2,3,3,3,3
6 1,2,3,3,3,3
i write the following code to get the unique code as follow:
SELECT LENGTH( follow_user_id ) - LENGTH( REPLACE( follow_user_id, ',', '' ) ) +1 AS no_of_follow FROM follow WHERE user_id =1;
But it provide the result:6
I need exactly unique rows: i.e:4
Apart from DB design questions you could use in PHP after fetching the row to $result:
count(array_unique(explode(",",$result["follow_user_id")));
$query="SELECT follow_user_id FROM follow WHERE user_id ='".$_POST['user_id']."' "; $query_run=mysql_query($query); $row= mysql_fetch_assoc($query_run);
$count= count(array_unique(explode(",",$row['follow_user_id'])));
$count;
This is better and faster ;)
count(array_flip(explode(",", $result["follow_user_id")));
Or doing it in SQL:-
SELECT COUNT(DISTINCT SUBSTRING_INDEX(SUBSTRING_INDEX(follow_user_id, ',', units.i + tens.i * 10), ',', -1) AS col1)
FROM sometable
CROSS JOIN (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9)units
CROSS JOIN (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9)tens
WHERE user_id = 1
(copes with up to 100 comma separated values).
But this would be so much easier with a properly normalised database design

Fastest way to generate 11,000,000 unique ids

I am trying to create php script that generates 11,000,000 million unique ids in sequential order. However, I am trying to do it very quickly within 20 min it should generate these 11 million unique ids. Also, once it reaches 12,000,000 it should wrap around and start back at zero.
Here is what I have so far. This script would would only return one id at a time. I just added a loop to see how long it would take to generate the ids.
while(true){
try {
$this->getAdapter()->query('INSERT INTO generate_ids (assigned_id) SELECT (MAX(assigned_id)+1) FROM generate_ids');
$id = $this->getAdapter()->lastInsertId();
$sql = 'SELECT assigned_id FROM generate_ids WHERE id = $id';
$query = $this->getAdapter()->query($sql);
$result = $query->fetchAll();
//Live system would return id here
$assigned_id = $result[0]['assigned_id'];
} catch (Exception $e) {
//do nothing
}
if($count == 11000000){
die();
}
$count++;
}
}
If you create the following table:
CREATE TABLE sequence (
sequence_id BIGINT NOT NULL AUTO_INCREMENT,
PRIMARY KEY (`sequence_id`)
)
Then issue these three queries one after the other:
INSERT INTO sequence () VALUES ();
DELETE FROM sequence WHERE sequence_id < LAST_INSERT_ID();
SELECT LAST_INSERT_ID() AS sequence;
The third query is guaranteed to return a unique sequence number. This guarantee holds even if you have dozens of different client programs connected to your database. That's the beauty of AUTO_INCREMENT.
Instead of just generating eleven million of these sequence numbers up front, you can use these SQL queries to get a unique sequence number whenever you need it.
If you must wrap around at sequence number 12 million you can use these queries instead.
INSERT INTO sequence () VALUES ();
DELETE FROM sequence WHERE sequence_id < LAST_INSERT_ID();
SELECT LAST_INSERT_ID() MOD 12000000 AS sequence;
The trick here is to use an auto-increment sequence number for uniqueness, but to also delete the rows in the table so it doesn't gobble up lots of space.
Note that you can also use the sequence number of LAST_INSERT_ID() for other purposes, like so for example.
INSERT INTO sequence () VALUES ();
DELETE FROM sequence WHERE sequence_id < LAST_INSERT_ID();
INSERT INTO user (userid, username, phone)
VALUES (LAST_INSERT_ID() MOD 12000000, 'Joe', '800-555-1212');
SELECT LAST_INSERT_ID() MOD 12000000 AS sequence;
If you need to insert all your ids at once (for some reason) the fastest approach would be to do it in pure SQL
insert into generate_ids (assigned_id)
select N
from
(
select a.N + b.N * 10 + c.N * 100 + d.N * 1000 + e.N * 10000 + f.N * 100000 + g.N * 1000000 + h.N * 10000000 + 1 as N
from (select 0 as N union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) a
,(select 0 as N union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) b
,(select 0 as N union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) c
,(select 0 as N union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) d
,(select 0 as N union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) e
,(select 0 as N union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) f
,(select 0 as N union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) g
,(select 0 as N union all select 1) h
order by N
) q
where N <= 11000000
It takes less than a minute to complete on my laptop.

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