This question already has answers here:
Reference - What does this error mean in PHP?
(38 answers)
Closed 5 years ago.
Here is the HTML Form:
<form action="imagematch.php" method="get">
Input Route Number: <input type="text" name="N" />
<input type="submit" />
</form>
And here is the PHP file:
<?php
if(isset($_GET[’N’]))
{
$N = $_GET[’N’];
}
?>
Right now, it is reading the PHP file but it isn't reading the "N" argument correctly.
As best we can tell, the issue seems to be the type of quotes you are using around the letter 'N'. This is very common when copying code from webpages. The angled/curly quotes used in webpages aren't interpreted the same as quotes expected and accepted in most programming languages. If you look at this article, you can see the difference. Note you want to do the opposite of what they recommend as they are making recommendations for publications and not code. You want to use straight quotes only in code.
As a separate recommendation, as mentioned by joeDaigle, you should use the GET method for when you are GETting (or reading) information, and use PUT when PUTting (or writing/updating) information. You can read this RFC for more details, but the main reason is that browsers treat GET and POST requests differently (note when you refresh a regular webpage, versus when you refresh a page after submitting a POST form and your browser prompts asking if you're sure).
Related
This question already has answers here:
what does a question mark mean before a php form action
(4 answers)
Closed 2 years ago.
Can someone explain to me what is the use of ?action=add&code= and what they do in the code below? I have tried to search it on Google but they gave me HTML action atribute instead.
<form method="post" action="index.php?action=add&code=<?php echo $product_array[$key]["code"]; ?>">
Sorry for the noob question.Thanks for the reply.
Those are called query string values or parameters, they are one of several potential parts of a URL. Each key/value pair provides information that the server-side code can use when constructing the response to send back to the client. (Or the server-side code could even simply ignore them, they have no harmful effect.)
For example, given this key/value pair on the query string:
action=add
In the server-side code you can get the value "add" by fetching it from the query string by its key:
$action = $_GET["action"];
// $action now contains the string "add"
Presumably the logic in the code would then do something based on that value.
action is the name of a "normal" GET variable $_GET['action'].
You must look in the further code to see where it appears and what it is used for.
There is no standard for that
In the url after ? we can pass the values onto another webpage which can be used further.
This question already has answers here:
Can I read the hash portion of the URL on my server-side application (PHP, Ruby, Python, etc.)?
(12 answers)
Closed 9 years ago.
I want to echo exact url : http://domain.com/mystuff.html#123456
but it only print http://domain.com/mystuff.html how to include the #123456 ? so become http://domain.com/mystuff.html#123456
my code so far
$urladdress = "http://".$_SERVER['HTTP_HOST'].$_SERVER['SCRIPT_NAME']."?".$_SERVER['QUERY_STRING'];
You cannot. The fragment identifier is handled entirely client side so the browser will not send it to the server.
(The nearest you could come would be to (after the page has loaded) use JavaScript to sent it to the server in another request.)
you cannot get it using php, you can get it done by javascritp. use this test script to check your result.
<script>
alert(document.URL);
var urlDetail = document.URL;//you can use this variable to print in your web page.
</script>
Found the answer:
text
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
How to properly escape html form input default values in php?
I am facing problem on facing </textarea> element.
I am working on whole php file edit. If the php file has </textarea> tag it closes the files codes.
E.g.
$data=file_get_contents($file);
..
'<textarea>'
'.$data.'
'</textarea>'
..
The problem is:
if contain the </textarea> tag in data, my codes truncted by the tag. Because </textarea> is end tag of textarea values. Any solve there to not execute </textarea> tag(which contained $data)?
Try cleaning up $data before outputting it, such as:
'.htmlentities($data).'
Also, take a look at the available flags for the function in the PHP documentation.
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Check if multiple strings are empty
today i got this answer here on stackoverflow:
<input type="text" name="required[first_name]" />
<input type="text" name="required[last_name]" />
...
$required = $_POST['required'];
foreach ($required as $req) {
$req = trim($req);
if (empty($req))
echo 'gotcha!';
}
This is ok, but what if someone change
name="required[first_name]"
To
name=""
Then i will have some data missing in further code (i use form to send submited data to email). How to fix this?
Yes, someone can change the html that submits to your code. So you have to check for the existence of everything you want to have in the code that handles the form. Lots of beginners want to automate that away by looping through $_POST or $_GET. And they almost always miss something or end up with code just as complicated, but harder to read, than just checking each input you want.
Loop through the $_GET array and check if any variables are "" or start with something other than required, and then just error out.
You should always validate data on the server side (i.e. in PHP).
You should list the required field in PHP and check them in PHP.
Never trust user data.
This question already has answers here:
How do I pass variables and data from PHP to JavaScript?
(19 answers)
Closed 8 years ago.
<button class="addToPlaylist" onclick="javascript:myPopup(<?php echo $videos[$counter]?>);
return false;">+</button>
I have a button on an image as a html hyperlink. I want to perform different actions on hyperlink and button. The above code works whenever I do not pass the PHP variable using echo. When i pass PHP variable, the button also performs the same action as of the hyperlink, that means return false does not work.
Any idea why the return false; does not work when i pass PHP variable?
This should be:
<button class="addToPlaylist" onclick="javascript:myPopup('<?php echo $videos[$counter];?>');return false;">+</button>
Note the single quotes in myPopup. As you pass a string to myPopup, you will need to enclose it with single quotes. (Double won't work as there is already double quotes for the onclick)
I am quite sure $videos[$counter] is not numeric, but a string. In this case you have to write the quotes:
onclick="javascript:myPopup('<?php echo $videos[$counter]?>');
And make sure, $videos[$counter] doesn't contain any, something like
onclick="javascript:myPopup('<?php echo addslashes($videos[$counter])?>');
comes to mind.
onclick="javascript:myPopup("";return false;" . This should work and i think it's more clear where you have javascript code and php code.