create drop down to view month and year in php - php

Question

I am using this function to create a dropdown for months and year my problem is am getting an error like below:
Unknown column 'format' in 'where clause'
below is the code anyone help to get rid of this error
date_condition = ' and 1=1 ';
if($date_type==1)
{
$date_condition = ' and m.submittimestamp BETWEEN DATE_SUB(NOW(), INTERVAL 300 DAY) AND NOW() ';
}
else if($date_type==2)
{
$date_condition = ' and YEAR(m.submittimestamp) = YEAR(CURRENT_DATE - INTERVAL 1 MONTH) and MONTH(m.submittimestamp)=MONTH(CURRENT_DATE - INTERVAL 1 MONTH) ';
}
else if($date_type==3)
{
$date_condition = ' and YEAR(m.submittimestamp) = YEAR(date(format)) AND MONTH(m.submittimestamp)=MONTH(date) ';
}
conditions 1 and 2 are working perfectly but condition 3 is getting error
Below is the code for drop down and script
<div class="form-group ">
<input name="filter_options"
<?php echo $option3; ?>
value="3" onchange="toggleDate(1)" type="radio" class="form-control" id="from_date">
<label for="from_date">show status for the month of </label>
<select name="month" class="form-control">
<?php
for ($i = 0; $i <= 12; ++$i) {
$time = strtotime(sprintf('-%d months', $i));
$value = date('m', $time);
$label = date('F ', $time);
printf('<option value="%s">%s</option>', $value, $label);
}
?>
</select>
<select name="year" class="form-control">
<?php
for ($i = 0; $i <= 12; ++$i) {
$time = strtotime(sprintf('-%d years', $i));
$value = date('Y', $time);
$label = date('Y ', $time);
printf('<option value="%s">%s</option>', $value, $label);
}
?>
<option value=" ">year</option>
</select>
</div>

Answer 1

The error is telling you everything you need to know, you have a syntax error. Remove the letter "e" at the beginning of the code noted in your error.
e) AND MONTH(m.submittimestamp)=MONTH(date) GROUP
should be
) AND MONTH(m.submittimestamp)=MONTH(date) GROUP