I want to get data from the database and display it on a webpage using CodeIgniter. I coded my controller, model and view as follows.
Controller;
//HomeController
<?php
class HomeController extends CI_Controller
{
public function index()
{
$this->load->model('HomeModel');
$data['records'] = $this->HomeModel->getData();
$this->load->view('HomeView',$data);
}
}
?>
Model;
//HomeModel
<?php
class HomeModel extends CI_Model
{
public function getData()
{
$query = $this->db->query('SELECT * FROM data');
return $query->unbuffered_row('object');
}
}
?>
View;
//HomeView
<?php
echo "Recoeds from database<br>";
while($records)
{
echo $records->name." ".$records->age."</br>";
}
?>
But this code doesn't print anything on the screen.(echo "Records from database<br>"; )
So I tried the following code given in the CodeIgniter documentation and echoed the result in the model itself rather than return it to the controller and then to the views.It worked fine.
//HomeModel
<?php
class HomeModel extends CI_Model
{
public function getData()
{
$query = $this->db->query('SELECT * FROM data');
while ($row = $query->unbuffered_row())
{
echo $row->name;
echo $row->age;
}
}
}
?>
My question is how do we return the result of the unbuffered_row() method into the controller and then to the view as per MVC architecture? We can get the output by echoing result at the model itself but it is against the purpose of the MVC architecture.
You should use return $query->result(); and then get the right object in the view or controller (that's up to you).
Try This One
controller
<?php
class HomeController extends CI_Controller
{
public function index()
{
$this->load->model('HomeModel');
$data['records'] = $this->HomeModel->getData();
$this->load->view('HomeView',$data);
}
}
?>
Model
<?php
class HomeModel extends CI_Model
{
public function getData()
{
$data = $this->db->query('SELECT * FROM data');
return array('count'=>$data->num_rows(), 'data'=>$data->result(),'first'=>$data->row());
}
}
?>
View
<?php
echo "Recoeds from database<br>";
foreach($record['data'] as $row)
{
echo $row->name." ".$row->age;
}
?>
I simulated your code in local.Your mistake is here.$records is object .And your while loop has not condition for leaving the loop
<pre>
<?php
var_dump($records);
echo "Recoeds from database<br>";
foreach($records as $value) {
echo $value->name."<br>";
echo $value->age."<br>";
}
?>
</pre>
Related
I am getting an error "Invalid argument supplied for foreach()" while trying to fetch 'id' column using foreach loop:
Codeignitor version: 3.0.1
Controller:
<?php
class Users extends CI_Controller {
public function show(){
$this->load->model('user_model');
$result = $this->user_model->get_users();
foreach($result as $object){
echo $object->id;
}
}
}
?>
Model:
<?php
class User_model extends CI_Model {
public function get_users(){
$this->db->get('users');
}
}
?>
As I checked table name and column names are correct.
<?php
class User_model extends CI_Model {
public function get_users(){
$data=$this->db->get('users');
return $data->result();
}
}
?>
you can fetch by using either result() or result_array() in model
in your case
public function get_users(){ // model
$data=$this->db->get('users');
return $data->result();
}
public function show(){ // controller
$this->load->model('user_model');
$result = $this->user_model->get_users();
foreach($result as $object){
echo $object->id;
}
}
The above method returns the query result as an array of objects, or an empty array on failure.
The below one method returns the query result as a pure array, or an empty array when no result is produced.
you can also do this
public function get_users(){ // model
$data=$this->db->get('users');
return $data->result_array();
}
public function show(){ // controller
$this->load->model('user_model');
$result = $this->user_model->get_users();
foreach($result as $object){
echo $object['id'];
}
}
for more details click here
you need to return result() or result_array()
<?php
class User_model extends CI_Model {
public function get_users(){
$data=$this->db->get('users');
return $data->result(); // or return $data->result_array();
}
}
?>
for result arrray you need to echo $object['id'];
and for result() same as you printing.
it's my model code:
<?php
class Books_model extends CI_Model
{
public function __construct()
{
$this->load->database();
}
public function get_restaurants()
{
$sql = "SELECT id, names FROM restaurants ";
$query = $this->db->query( $sql );
return $query->result();
}
}
controller code:
<?php
class Booking_Controller extends CI_Controller
{
public function __construct(){
parent::__construct();
$this->load->model('Books_model');
}
public function view()
{
$this->user_data['result']=$this->Books_model->get_restaurants();
$this->load->helper(array('form','url'));
$this->load->view('restaurants/booking',$this->user_data);
}
}
What code I written in view file that the data show in text field?
Try the following :
In the Controller
class Booking_Controller extends CI_Controller
{
public function __construct(){
parent::__construct();
$this->load->model('Books_model');
}
public function view()
{
$data['results'] = $this->Books_model->get_restaurants();
$this->load->helper(array('form','url'));
$this->load->view('restaurants/booking',$data);
}
}
In the View:
<?php
foreach ($results as $result)
{?>
<label>Restaurant Name : </label>
<input type="text" value="<?php echo $result->names;?>" />
<?php } ?>
in the controller
<?php
class Booking_Controller extends CI_Controller
{
public function __construct(){
parent::__construct();
$this->load->model('Books_model');
}
public function view()
{
$data["result"]=$this->Books_model->get_restaurants();
//$this->load->helper(array('form','url')); not needed
$this->load->view('restaurants/booking',$data["result"]);
}
}
now in your view
<?php
// notice that CI strip the key "result" from the array $data to become a variable $result in the view
foreach ($result as $row)
{
echo $row->id."<br>";
echo $row->name."<br>";
echo "----";
}
?>
Note:
there is no member like this "$this->user_data['result']" in
codeigniter but there is "$this->session->user_data("data_name")" if
you want to store some data in the session, but then, no need to pass
it to the view as an argument you can call the session data from the
view directly
I did a REST app + codeigniter + database following: https://github.com/chriskacerguis/codeigniter-restserver , works perfect, wonderful.
Right now my json file getting static data, how can i get data from database?
i wrote a file and i can get from database the data, but i have no idea how to get the data from database in json, can you guys help me? thank you.
That file return to me that static json, works perfect, I would like get data from database.
/controllers/hello.php
<?php
include (APPPATH.'/libraries/REST_Controller.php');
class Hello extends REST_Controller {
function world_get(){
$data = new stdClass();
$data->name = 'Mark ';
$this->response($data, 200);
}
}
These files below I can get data from database but in html, how can I get data in json format?
/controllers/site.php
<?php
Class Site extends CI_Controller {
function __construct()
{
// Call the Model constructor
parent::__construct();
}
function index(){
$this->load->model('data_model');
$data['rows'] = $this->data_model->getAll();
$this->load->view('home', $data);
}
}
/models/data_model.php
<?php
class Data_model extends CI_Model {
function getAll(){
$q = $this->db->query("SELECT * from data");
if($q->num_rows() > 0) {
foreach ($q->result() as $row) {
$data [] = $row;
}
return $data;
}
}
}
views/home.php
<htmL>
<body>
<pre>
<?php foreach ($rows as $r)
{
echo '<h1>' . $r->title . '</h1>';
}
?>
</pre>
<?php foreach ($rows as $r) : ?>
<h1> <?php echo $r->author; ?></h1>
<h1> <?php echo $r->contents; ?></h1>
<?php endforeach; ?>
</body>
</htmL>
You are making API.To return data you don't need to call view.You can do it simply this way
function index()
{
$this->load->model('data_model');
$data = $this->data_model->getAll();
$this->response($data, 200);
}
Your model function is OK but you can make it simple.
function getAll()
{
return $this->db->get('data')->result();
}
just use json_encode in your controller and little change in your model file
Controller
function index(){
$this->load->model('data_model');
$result= $this->data_model->getAll();// change this line
$data['rows']= json_encode($result);// add this line
$this->load->view('home', $data);
}
Model
<?php
class Data_model extends CI_Model {
function getAll(){
$q = $this->db->query("SELECT * from data");
if($q->num_rows() > 0) {
return $q->result();
}else{
return false;
}
}
}
I'm working on simple application consisting of simple form. My code really works fine in local environment. But when i uploaded it on a live server gives an error, unable to fetch database fields and i think there is an error in my model.
Here is my model class
class Model_get extends CI_Model
{
function getData($page) {
$query = $this->db->get_where('ci_tbl', array('page' => $page));
print_r($query->result());
return $query->result();
}
}
Here goes my view
<div id="content">
<?php
foreach ($results as $row) {
$title = $row->title;
$para1 = $row->para1;
$para2 = $row->para2;
}
echo heading($title, 1);
?>
<p><?php echo $title;?></p>
<p><?php echo $para1;?></p>
<p><?php echo $para2;?></p>
</div>
My controller goes as
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class Site extends CI_Controller {
public function index()
{
$this->home();
}
public function home() {
$this->load->model('model_get');
$data['results'] = $this->model_get->getData('home');
$this->load->view('header');
$this->load->view('nav');
$this->load->view('main_content',$data);
$this->load->view('footer');
}
public function about() {
$this->load->model('model_get');
$data['results'] = $this->model_get->getData('about');
$this->load->view('header');
$this->load->view('nav');
$this->load->view('about_page',$data);
$this->load->view('footer');
}
Make sure you actually return the results of the query:
//print_r($query->result());
return $query->result();
At the moment you've commented out return $query->result(); and you're just printing the result. The controller calling the model isn't going to get that information and therefore isn't passing through to the view.
Also check that the database connection is correct if moving from local to a public environment.
Actually you had an error
foreach ($results as $row) {
$title=$ row->title;
^^^^
It should be
$title = $row->title;
^^^
You need to update your query within model as
class Model_get extends CI_Model {
function getData($page) {
$query = $this - > db - > get_where('ci_tbl', array('page' => $page));
return $query->result_array();
}
}
What is the best way to create my model so I can call it from my controller like this?
$this->model_model->function->dbname
I have the following model but its rubbish:
Model:
function systemName()
{
$query = $this->db->query("SELECT cms_name FROM options");
return $query->result();
}
Update:
function systemOptions($options)
{
$this->db->select($options);
$query = $this->db->get('options');
return $query->num_rows();
}
Why would you want to? Why not call it like this?:
$this->model_model->functionname('dbname');
A complete skeleton of a model is like this:
<?php
class Mymodel extends Model
{
function get_some_entries($number_rows)
{
return $result = $this -> db -> query("SELECT id, name
FROM tablename
LIMIT $number_rows");
}
}
?>
Best way? You can probably read on CodeIgniter general guide and alter to your situation. But the basic idea is that, you create the model class then load from your controller. Then just call the model function accordingly. For example,
class Custom_model extends CI_Model {
function __construct()
{
parent::__construct();
}
function systemName()
{
$query = $this->db->query("SELECT cms_name FROM options");
return $query->result();
}
...
...
function systemOptions($options)
{
$this->db->select($options);
$query = $this->db->get('options');
return $query->num_rows();
}
}
<?php
class CustomController extends CI_Controller {
public function __construct()
{
parent::__construct();
$this->load->model('custom_model', 'fubar');
}
public function index()
{
$result = $this->fubar->systemName('dbname');
print_r ($result);
}
}
?>