Update data array in the same row - php

Question

I would like to approve leave application based on dates for example as below :
echo "<select name='app_status[]' required>
<option value='' selected>Pending</option>
<option value='1'>Approve</option>
<option value='2'>Reject</option></select>";
$app_status = array();
if(is_array($app_status)) {
foreach($_POST['app_status'] as $key1=>$value1) {
$app_status[]=$value1;
}
}
for($loop = 0; $loop < count($app_status); $loop++) {
if($app_status[$loop]=="" || $app_status[$loop]==null)
$error=1;
}
if(isset($error))
$error=1;
else
$error=0;
if($error==0) {
for ($i = 0; $i < count($app_status); $i++) {
$str = $app_status[$i];
$sql= "UPDATE leaves_apply SET app_status ='$str' WHERE app_id='$app_id'";
$query2 = mysqli_query($sql);
}
}
For example if I approve the leaves for 12/8/2017 - 15/8/2017 except for 16/8/2017, I will get an output like this 11112 And when I check the database, the column app_status will only update 2, as if it only read the last data and not the first four data. If possible I would like the data 11112 to be update in the app_status column for app_id no 1357. I'm not sure if this is the right way, please help me as I'm new to this. Thank you.

Answer 1

I think this modification should do what you would like...
if($error==0) {
// Declare the string for the app_status
$str = "";
// Loop though the statuses and put together the statuses
for ($i = 0; $i < count($app_status); $i++) {
$str .= $app_status[$i];
}
// Update the database record
$sql= "UPDATE leaves_apply SET app_status = '$str' WHERE app_id='$app_id'";
$query2 = mysqli_query($sql);
}
Please remember to escape your database queries to prevent SQL injection.