I've been trying to use ajax to insert data into my database but it didn't work. So I wrote a code to try a basic call for a php file and it didn't work either:
here is my html code :
<form >
<h4 class="header-title m-t-0 m-b-30">Cordonnées de facturation</h4>
<div class="form-group">
<label class="col-md-4 control-label">code facture</label>
<div class="col-md-6">
<input type="text" id="code_facture" class="code_facture form-control" placeholder="Ex : 008A00098">
</div>
</div>
<div class="form-group">
<label class="col-md-4 control-label">Numéro du dossier</label>
<div class="col-md-6">
<input type="text" id="code_dossier" class="code_dossier form-control" placeholder="Ex : 008A00098">
</div>
</div>
<div class="form-group">
<label class="col-md-4 control-label">TPS</label>
<div class="col-md-6">
<input type="text" id="tps" class="tps form-control" placeholder="Ex : 0">
</div>
</div>
<div class="form-group">
<label class="col-md-4 control-label">TVQ</label>
<div class="col-md-6">
<input type="text" id="tvq" class="tvq form-control" placeholder="Ex : 0">
</div>
</div>
<div class="form-group">
<label class="col-md-4 control-label">Référence</label>
<div class="col-md-6">
<input type="text" id="reference" class="reference form-control" placeholder="Ex : VAR R4055555">
</div>
</div>
<div class="form-group">
<label class="col-md-4 control-label">PNR</label>
<div class="col-md-6">
<input type="text" id="pnr" class="pnr form-control" placeholder="Ex : M15478LD265">
</div>
</div>
<div class="form-group">
<label class="col-md-4 control-label">Date de facturation</label>
<div class="col-md-6">
<input type="text" placeholder="12/12/2012" data-mask="99/99/9999" id="date_facturation" class="date_facturation form-control">
<span class="font-13 text-muted">jj/mm/aaaa</span>
</div>
</div>
<div class="form-group">
<button type="submit" class="btn" id="addfacturebutton"> ajouter</button>
</div>
and here is my ajax script
<script>
$('#addfacturebutton').click(function(e){
e.preventDefault();
$.ajax({
type: 'POST',
url: 'insertFacture.php',
data:{
code_facture:$('input[id=code_facture').val(),
code_dossier:$('input[id=code_dossier').val(),
tps:$('input[id=tps').val(),
tvq:$('input[id=tvq').val(),
reference:$('input[id=reference').val(),
pnr:$('input[id=pnr').val(),
date_facturation:$('input[id=date_facturation').val(),
},
success:function(data){
},
});
});
</script>
so in my php file I tried to write die('test'); but inserting into database didn't work either.
it doesn't call the functions
here is my php file:
<?php
include('functions.php');
$data = $_POST['code_dossier'];
die('works');
?>
Have you tried to dump $_POST of your insertFacture.php file? It seems like you do have wrong php filename or something wrong with the functions.php
Your code does not confirm if the js code works or not.
Try this:
Change this line:
success:function(data){
}
to:
success:function(data){
alert(data)
}
And change every occurrence of:
').val()
to
]').val()
If there is an alert, then the js is working. And I cannot see anything related to database in your php code.
To reduce the lines of code in ajax, you can alternatively add an id attribute on the form tag and then either serialize() or use FormData()
<form id='myFormTag'>
Then in ajax, simply call FormData() on submit()
$('#myFormTag').submit(function(e){
e.preventDefault();
$.ajax({
data: new FormData(this),
//other AJax Stuff
success:function(data){
alert(data)
}
});
});
Related
I am doing a project in laravel with a create form in ajax. I need to join two tables after the form is done, so in ajax code because I need to take some selection. Here there is the ajax code:
$.ajax({
data: $('#hourForm').serialize(),
url: "{{ route('others.store') }}",
type: "POST",
dataType: 'json',
success: function (data) {
var name = <?php DB::select('SELECT projects.nameP from projects, data where projects.id = data.project_id?>
var hour = '<tr id="hour_id_' + data.id + '"><td>' + data.day + '</td><td>'+ data.project_id+'</td><td>' + name + '</td><td>' + data.nHours + '</td><td>' + data.notesH + '</td>';
And here the form:
<form id="hourForm" name="hourForm" class="form-horizontal">
<input type="hidden" name="hour_id" id="hour_id">
<div class="form-group">
<label for="day" class="col-sm-2 control-label">DATA</label>
<div class="col-sm-12">
<input type="date" class="form-control" id="day" name="day" value="" required="">
</div>
</div>
<div class="form-group">
<label class="col-sm-2 control-label">Progetto</label>
<div class="col-sm-12">
<select name="project_id" id="project_id">
<option value="" selected disabled hidden><b>Scegli un'opzione</b></option>
#foreach($projects as $project)
<option value="{{$project->id}}">{{$project->nameP}}</option>
#endforeach
</select>
</div>
</div>
<div class="form-group">
<label for="nHours" class="col-sm-2 control-label">Ore</label>
<div class="col-sm-12">
<input type="text" class="form-control" id="nHours" name="nHours" value="" required="">
</div>
</div>
<div class="form-group">
<label for="notesH" class="col-sm-2 control-label">Note</label>
<div class="col-sm-12">
<input type="text" class="form-control" id="notesH" name="notesH" value="">
</div>
</div>
<div class="col-sm-offset-2 col-sm-10">
<button type="submit" class="btn btn-primary" id="btn-save" value="create">Aggiungi
</button>
</div>
</form>
I don't know how to replace data that is only the variable in ajax function. Can anyone help me?
You won't be able to perform such a query inside your javascript.
Why don't you perform the query within the route('others.store')? I believe that its calling a controller's function so: just run that join back there and bring the name along with the rest of the data.
Right now I am facing a problem : I am trying to insert records in the database with the help of jQuery & Ajax. Unfortunately, I tried to alert inserted values but It doesn't show. I also checked through serialize function and I am unable to do that.
Here is my code of ajax
<script type="text/javascript">
$(document).ready(function(){
$("#add_new").click(function(){
$("#add").slideToggle();
});
$("#submit").click(function(){
var stud_no=$("#roll").val();
if(stud_no==''){
$("#msg").html("Input Roll Number");
} else {
var datastr = $("#sampleform").serialize();
alert(datastr);
$.ajax({
type:'POST',
url:'add_it.php',
data:datastr,
success:function(response){
$("#my_form")[0].reset();
$("#msg").html("Student Successfully Added");
},
error: function (xhr, ajaxOptions, thrownError) {
}
});
}
});
});
</script>
Here is body code :
<body>
<a id="add_new">+add new item</a><br /><br />
<div id="msg"></div><br />
<div id="add">
<form id="sampleform">
<fieldset>
<div class="form-group row">
<label for="roll" class="col-sm-2 col-form-label">Roll Number</label>
<div class="col-sm-6">
<input type="text" name="roll" class="form-control" id="roll">
</div>
</div>
<div class="form-group row">
<label for="name" class="col-sm-2 col-form-label">Name</label>
<div class="col-sm-6">
<input type="text" name="name" class="form-control" id="name">
</div>
</div>
<div class="form-group row">
<label for="clas" class="col-sm-2 col-form-label">Class</label>
<div class="col-sm-6">
<input type="text" name="standard" class="form-control" id="standard">
</div>
</div>
<div class="form-group row">
<label for="mail" class="col-sm-2 col-form-label">Email</label>
<div class="col-sm-6">
<input type="email" name="mail" class="form-control" id="mail">
</div>
</div>
<button type="submit" id="submit" class="btn btn-primary">Submit</button>
<button type="reset" class="btn btn-default">Reset</button>
</fieldset>
</fieldset>
</form>
</div>
Here is my add_it.php
<?php
include('connectdb.php');
$stud_no = trim($_POST['stud_no']);
$name = trim($_POST['name']);
$standard = trim($_POST['standard']);
$mail = trim($_POST['mail']);
$query = "insert into student (stud_no,name,standard,email) values ('$stud_no','$name','$standard','$mail')";
mysqli_query($con,$query) or die (mysqli_error());
?>
Your HTML form fields doesnt have any of these variables sent. You need to add name="email" etc to your form fields.
So for example the email field has to look like this:
<input type="email" name="email" class="form-control" id="mail">
id, class etc is not sent in POST - and therefor can not be recieved in the other end.
Jquery's serialize() function also only handles "name" fields.
https://api.jquery.com/serialize/
Snippet :
For a form element's value to be included in the serialized string, the element must have a name attribute
I have this form
<form name="main" id="main" class="form-horizontal" method="post">
<div class="form-group">
<label for="value" class="col-sm-2 control-label">Enter Value</label>
<div class="col-sm-3">
<input type="text" class="form-control" name="value" id="value" placeholder="Enter value">
</div>
</div>
<div class="form-group">
<label for="value" class="col-sm-2 control-label">Result</label>
<div class="col-sm-3">
<input type="text" class="form-control" name="result" id="result" placeholder="result" value="">
</div>
</div>
<div class="form-group">
<div class="col-sm-offset-2 col-sm-3">
<button type="submit" class="btn btn-default" id="Convert" name="Convert" value="Convert">Submit</button>
</div>
</div>
</form>
and the jquery file is:
$( document ).ready(function() {
console.log("ready");
$('#main').submit(function(e){
e.preventDefault();
$.ajax({
type: "GET",
url : "index.php", //your processing page URL instead of ???
data: "&example=2",
success: function(){
alert("success");
$("#result").html("Example content");
}
});
});
});
I want to display the example content string on the #result field when the form submits. It seems simple but I have tried everything and nothing works. I get no http and console errors and the alert shows "success"
You are making a mistake when you are writing $("#result").html("Example content"); because it is a input not an element holder.
Change your code to
$('#result').val("Example Content");
I have a page called page2.php. It has a form that allows you to search via jquery ajax call. The code is below. My question is, I have a different form on page1.php. How can I submit the form on page1.php to go to page2.php and have it execute the page2.php code below using the data from the form on page1.php? I know this is most likely simple, having a brain fart right now.
$(function() {
$.validate({
form: '#form_search',
validateOnBlur: false,
errorMessagePosition: 'top',
onSuccess: function(form) {
var formval = $(form).serialize();
var formurl = '/page2.php?a=search';
$('#form_results').html('<div class="form_wait_search">Searching, please wait...<br><img src="/images/search-loader.gif"></div>');
$.ajax({
type: 'POST',
url: formurl,
data: formval,
success: function(data){
var json = $.parseJSON(data);
$('#form_errors').html(json.message);
$('#form_results').html(json.results);
}
});
return false;
}
});
});
UPDATE
Here is the forms Im referring to.
On page1.php this is like a module on the right side bar. Just a form that I want to post to page2.php
<div class="scontent_box1">
<strong class="box_title"><i class="fa fa-search fa-flip-horizontal"></i> Find Locations</strong>
<form method="post" action="/page2.php">
<div class="form-group">
<label>Street Address</label>
<input type="text" class="form-control" name="ad" placeholder="Enter Street Address...">
</div>
<div class="form-group">
<label>City, State or Zip Code</label>
<input type="text" class="form-control" name="ct" placeholder="Enter City, State or Zip Code...">
</div>
<button type="submit" class="btn btn-default blue_btn">Search</button>
</form>
</div>
Now here is the form on page2.php that executes the ajax code above. I want page1.php to submit to page2.php and envoke the same jquery code above.
<div class="row no_gutters">
<div class="search_page">
<div id="form_errors"></div>
<form method="post" id="form_search">
<div class="form-group">
<label for="ad">Street Address<span class="reqfld">*</span></label>
<input type="text" class="form-control" data-validation="required" id="ad" name="ad" placeholder="Enter Street Address..." value="">
</div>
<div class="row">
<div class="col-md-12">
<div class="form-group">
<label for="ct">City, State or Zip Code<span class="reqfld">*</span></label>
<input type="text" class="form-control input-sm" data-validation="required" id="ct" name="ct" placeholder="Enter City Name..." value="">
</div>
</div>
</div>
<div class="row">
<div class="col-md-4 col-xs-12">
<button type="submit" class="btn btn-default blue_btn btn-block">Search Locations</button>
</div>
<div class="col-md-8"></div>
</div>
</form>
</div>
<div id="form_results"></div>
</div>
i use the following code to load the form as below code
as Ajax code as below
function assessment_form() {
$this = $(this);
$.ajax({
url: 'view/assessment/assessment_form.php',
datatype: 'html',
success: function (data) {
$box = $('.span12');
$box.after(data);
$box.remove();
}
});
}
$(document).on('click', '#assessment_form', $(this), assessment_form);
and the form page as below in directory view/assessment/assessment_form.php
Add New User
<div class="box span12">
<div class="box-header well" data-original-title>
<h2> Add New User</h2>
</div>
<div class="box-content">
<form class="form-horizontal" id="user_form_data" enctype="multipart/form-data">
<fieldset>
<div class="control-group">
<label class="control-label" for="firstname">ROTC NO</label>
<div class="controls">
<input class="input-xlarge focused" id="rotc_no" name="rotc_no" type="text" />
</div>
</div>
<div class="control-group">
<label class="control-label" for="lastname">Password</label>
<div class="controls">
<input class="input-xlarge focused" id="password" name="password" type="text" />
</div>
</div>
Simply, You can load html page into a div by using jquery's load() function.
Try this:
$('#yourDiv').load('pages/page1.html');
use this $(document).on('click','#assessment_form', assessment_form);
instead of $(document).on('click','#assessment_form',$(this),assessment_form);
Take a look for more information $.get()
// Make it little more flexible and easy
function assessment_form() {
$.get('your_url', function(data){
$box = $('.span12');
$box.after(data);
$box.remove();
});
}