I have a file manager and I want to add an option of editing files (html,php,css), but if I try with fgets() it displays the page and its graphic. How to get only lines from file and then send them as response to ajax request.
This is what I tried so far:
<?php
$handle = fopen('/location/', "r");
if ($handle) {
while (($line = fgets($handle)) !== false) {
echo $line;
}
fclose($handle);
} else {
// error opening the file.
}
?>
Use
show_source("/location/file.php"); to get the source code.
You can refer it from W3School - PHP show_source() Function
If the file is on the same server you can use
$content = #file_get_contents($filename);
if($content){
echo $content;
}else{
echo 'File:"'.$filename.'" couldn\'t be found.';
}
Related
I am trying to make a file manager with php , so when I open it in browser it would give a list of the current directory and the file would be clickable using the anchor tag in html (which I have done so far) , and when the file is clicked , it would open it in the text mode and shows whatever the source code inside the file is.
I am facing two problems which I couldn't figure out
Problem #1:
The first problem is that I want my file manager to read any source code weather its an image or pdf , just like the tinyfilemanager that I found here this master piece can read any file, even if you open an image with a notepad and insert some php code at the very end of the file it will read render that too, so here's my source code:
<?php
function list_all_files($directory){
//opening the dir
if($handle=opendir($directory.'/')){
echo "looking inside '$directory'"."<br>";
}
while($file=readdir($handle)){
//listing all the directories without ".." (dots)
if($file!='.'&&$file!='..') {
echo ''.$file.'<br>';
} //if ends here
} //while loop endds here
} //list_all_files ends here
function read_file($file)
{
$handle = fopen($file, "r");
if ($handle) {
while (($line = fgets($handle)) !== false) {
echo($line);
}
fclose($handle);
} else {
echo "error opening the file";
}
}
//main function
if(!isset($_GET['dir'])) {
$dir='images';
}else{
$dir=$_GET['dir'];
}
list_all_files($dir);
if(isset($_GET['read'])){
$file1 = $_GET['read'];
read_file($file1);
}
?>
the above program I made can also read files code but when I click on any PHP file that contains an html code, it just displays it rather than giving its source code in text mode, image below:
and not only this, if I put some php code at the very end of the image file using a notepad it wouldn't display it. check this:
I did a lot of research on why my code isn't working while the tinyFilemanager is perfect with any of the above mention cases , and I found that the whenever I execute the page file via browser it by default uses this
header("Content-Type: text/html");
so If I wanted to do what I wanted , then I would have to use this:
header("Content-Type: text/x-php");
which covers both of the above cases, but leads to the 2nd problem.
Problem #2:
<?php
function list_all_files($directory){
//opening the dir
if($handle=opendir($directory.'/')){
echo "looking inside '$directory'"."<br>";
}
while($file=readdir($handle)){
//listing all the directories without ".." (dots)
if($file!='.'&&$file!='..') {
echo ''.$file.'<br>';
} //if ends here
} //while loop endds here
} //list_all_files ends here
function read_file($file)
{
$handle = fopen($file, "r");
if ($handle) {
while (($line = fgets($handle)) !== false) {
echo($line);
}
fclose($handle);
} else {
echo "error opening the file";
}
}
//main function
if(!isset($_GET['dir'])) {
$dir=getcwd();
}else{
$dir=$_GET['dir'];
}
//listing all the directories and files in text/html format so that our anchor tag would be available.
ob_start();
header('Content-Type: text/html; charset=UTF-8');
list_all_files($dir);
ob_end_flush();
if(isset($_GET['read'])){
//changing the header to text/php-x so that the php code in any jpg file can be viewed clearly
ob_clean();
header('Content-Type: text/x-php; charset=UTF-8');
ob_start();
$file1 = $_GET['read'];
read_file($file1);
ob_end_flush();
}
?>
The above codes works perfectly fine, but there is this one problem. since its content-type is not text/html anymore, it wouldn't display the html content on the web page. which is good but bad at the same time because then I wouldn't get the list of directory in the anchor tag form, because I thought ob_start and ob_end_flush(). if I use these two, it would just solve the problem by creating a buffer for each of the function separately and executes it. so when it executes it the above function would be render with the content-type text/html and would show the directory listing with anchor tag, and the 2nd would just be in text/x-php which would solve the above two cases, but I was soooooo wrong.
With the grace and help of God , and suggestion from kikoSoftware in the Comments , the Problem is solved, there's a function name show_source(); ,which takes two arguement , the 2nd argument however is optional , hence we don't need to do filing or send a content-type response with the header() function , we can just use that function , source codes are below.
<?php
function list_all_files($directory){
//opening the dir
if($handle=opendir($directory.'/')){
echo "looking inside '$directory'"."<br>";
}
while($file=readdir($handle)){
//listing all the directories without ".." (dots)
if($file!='.'&&$file!='..') {
echo ''.$file.'<br>';
} //if ends here
} //while loop endds here
} //list_all_files ends here
function read_file($file)
{
$handle = fopen($file, "r");
if ($handle) {
while (($line = fgets($handle)) !== false) {
echo($line);
}
fclose($handle);
} else {
echo "error opening the file";
}
}
//main function
if(!isset($_GET['dir'])) {
$dir=getcwd();
}else{
$dir=$_GET['dir'];
}
//listing all the directories and files in text/html format so that our anchor tag would be available.
list_all_files($dir);
if(isset($_GET['read'])){
//changing the header to text/php-x so that the php code in any jpg file can be viewed clearly
$file1 = $_GET['read'];
show_source($file1);
}
?>
appreciate ya guys for helping out ♥
Hi I am trying to get this external text file to print inside my php document. The code looks fine to me however when I echo it does not output anything and I am not sure why this is. Can anybody help me out as I am new to this.
$location = '/Applications/MAMP/htdocs/PHPLabs/branches.txt';
$fp = fopen($location, 'r');
if ($fp) {
$readin = fread($fp);
fclose($fp);
} else {
echo 'Can\'t open input.txt';
}
Not sure what you're trying to 'echo' but have you checked if the file exists in the first place?
Your code could be written as:
$location = '/Applications/MAMP/htdocs/PHPLabs/branches.txt';
if (file_exists($location) && $data = file_get_content($location)){
echo $data;
} else {
echo 'File not found';
}
if (file_exists($location) && $file = fopen($location, 'r')){
$file_content = fread($file, filesize($location));
fclose($file);
} esle {
echo 'File not found';
}
See here for more: http://php.net/manual/en/function.file-get-contents.php, http://php.net/manual/en/function.filesize.php
I have a csv file placed at path
#http://thevowapp.com/brandstore/values.csv
$f = fopen("http://thevowapp.com/brandstore/values.csv", "w+");
if(!f)
{
echo "Error";
}
$line = fgetcsv($f);
echo json_encode($line);
I am trying to parse it, however the fgetCsv keeps on returning null. What could be the error?
Problems:
You try to open a remote file with w+ (write) access. Use r for read.
You check f (undefined constant). Use$f`.
You don't loop fgetcsv, so you won't get more than the header line.
Try:
$f = fopen('http://thevowapp.com/brandstore/values.csv', 'r');
if(!$f) {
echo 'Error';
exit;
}
$out = array();
while ($line = fgetcsv($f)) {
$out[] = $line;
}
echo json_encode($out, JSON_PRETTY_PRINT);
Remove the pretty print option when you're happy.
I need a php script that will open an external php file (from the same server folder), go through it line by line, and then normally display the page in the browser, as it would by just opening the external php page directly.
I need to open the external file line by line, so I can do some processing on the content of the file before showing it.
My current code is:
<?php
$handle = fopen("test.php", "r");
if ($handle) {
while (($line = fgets($handle)) !== false) {
// process the line here, and change if needed
echo "$line\n";
}
fclose($handle);
}
else {
// error opening the file.
}
?>
This works, and the page is displayed, but any php code in the original external file is not honored - it is written out as text, and not rendered by the browser.
I need the external file to fully display, just as it would if I opened the file (in this case "test.php") by itself.
Other questions I have seen on SO deal with opening or displaying a full file at once, but I need to loop through my file and do some processing on the contents first, so need to evaluate it line by line.
Any ideas would be appreciated.
Thanks
I would save the changes to a temporary file, and then include it.
<?php
$handle = fopen("test.php", "r");
if ($handle) {
while (($line = fgets($handle)) !== false) {
// process the line here, and change if needed
$newCode .= "$line\n";
}
fclose($handle);
}
else {
// error opening the file.
}
// temporary file name
$temp_file = tempnam(sys_get_temp_dir(), 'myfile').".php";
// save modified code
file_put_contents($temp_file, $newCode);
// include modified code
include $temp_file;
// delete file
unlink($temp_file);
?>
Retrieve the content, process it, keep it in memory then eval() it:
<?php
$newCode = "";
$handle = fopen("test.php", "r");
if ($handle) {
while (($line = fgets($handle)) !== false) {
// process the line here, and change if needed
//$line = myLineProcess($line);
$newCode .= "$line\n";
}
fclose($handle);
}
else {
// error opening the file.
}
//run the code
eval('?>'.$newCode.'<?php;');
?>
I have a form from which I save the given input into a textfile,
but I have trouble reading from the saved file:
while(!feof($fileNotizen)) {
$rawLine = fgets($fileNotizen);
if($rawLine==false) {
echo "An error occured while reading the file";
}
$rawLine seems to be always false, even though I use this function before, to fill the textfile:
function addToTable($notizFile) {
fwrite($notizFile, $_POST["vorname"]." ".$_POST["nachname"]."#");
$date = date(DATE_RFC850);
fwrite($notizFile, $date."#");
fwrite($notizFile, $_POST["notiz"].PHP_EOL);
}
And after I submit the form and get the error message, if I check the textfile, everything is there, so the function works correctly.
If it is of value, I open the file with this command:
$fileNotizen = fopen("notizen.txt", "a+");
Could the problem be that the pointer is already at the end of the file and thus returns false?
$fileNotizen = fopen("notizen.txt", "a+");
a+ opens for read/write but places file pointer AT THE END. So you must fseek() to the beginning first or look into fopen() flags and choose more wisely based on your needs.
Use fseek($fileNotizen, 0, SEEK_SET); to rewind the file.
To read/get content of the file try this function:
function read_file($file_name) {
if (is_readable($file_name)) {
$handle = fopen($file_name, "r");
while (!feof($handle)) {
$content .= fgets($handle);
}
return !empty($content) ? $content : "Empty file..";
} else {
return "This file is not readable.";
}
}
and if you want to see content of the file displayed on separate lines then use <pre></pre> tag like this:
echo "<pre>" . read_file("notizen.txt") . "</pre>";
and if you want to write/add content to the file then try this function:
function write_file($file_name, $content) {
if (file_exists($file_name) && is_writable($file_name)) {
$handle = fopen($file_name, "a");
fwrite($handle, $content . "\n");
fclose($handle);
}
}
and you can use it like this:
$content = "{$_POST["vorname"]} {$_POST["nachname"]}#" . date(DATE_RFC850) . "#{$_POST["notiz"]}";
write_file("notizen.txt", $content);