PHP Fetches two rows but uploads file from last row only - php

Question

Im trying to fetch records from database, then i have to upload a image which should be stored in folder and also link to be updated in table.. Everything working fine only with last row.. For first row its not updating.. Please help me where im goin on.. Below is my code
<?php
$email1 = $_SESSION['email'];
$Vendor_id = "SELECT Vendor_id FROM vendors where email = '$email1' ";
$result = mysqli_query($conn, $Vendor_id);
$row = mysqli_fetch_row($result);
$sql = "select Vendor_wallet_id, total_amount, request, amount, status, amt_pdflink from vendor_wallet";
$query = mysqli_query($conn, $sql);
?>
<form action="upload.php" method="post" enctype="multipart/form-data">
<table id="example1" class="table table-bordered table-striped">
<thead>
<tr>
<th>Transfer ID</th>
<th>Request</th>
<th>Amount</th>
<th>Status</th>
<th>Upload</th>
<th>Submit</th>
</tr>
</thead>
<tbody>
<?php
while ($row = mysqli_fetch_array($query))
{
$cpid = $row['Vendor_wallet_id'];
$tid = $row['request'];
$type = $row['amount'];
$pays = $row['status'];
$amt = $row['amt_pdflink'];
?>
<tr>
<td value="<?php echo $cpid; ?>" name="cpid"><?php echo $cpid; ?></td>
<td><?php echo $tid; ?></td>
<td><?php echo $type; ?></td>
<td><?php echo $pays; ?></td>
<td><input type="file" value="<?php echo $amt; ?>" name="fileToUpload" id="fileToUpload" ></td>
<td><input type="submit" value="Submit" name="submit" >
</button>
</td> </tr>
<?php } ?>
</tbody>
</table>
</form>
upload.php is taken from https://www.w3schools.com/php/php_file_upload.asp

Answer 1

on your form
<?php
$email1 = $_SESSION['email'];
$Vendor_id = "SELECT Vendor_id FROM vendors where email = '$email1' ";
$result = mysqli_query($conn, $Vendor_id);
$row = mysqli_fetch_row($result);
$sql = "select Vendor_wallet_id, total_amount, request, amount, status, amt_pdflink from vendor_wallet";
$query = mysqli_query($conn, $sql);
?>
<form action="upload.php" method="post" enctype="multipart/form-data">
<table id="example1" class="table table-bordered table-striped">
<thead>
<tr>
<th>Transfer ID</th>
<th>Request</th>
<th>Amount</th>
<th>Status</th>
<th>Upload</th>
<th>Submit</th>
</tr>
</thead>
<tbody>
<?php
while ($row = mysqli_fetch_array($query))
{
$cpid = $row['Vendor_wallet_id'];
$tid = $row['request'];
$type = $row['amount'];
$pays = $row['status'];
$amt = $row['amt_pdflink'];
?>
<tr>
<td value="<?php echo $cpid; ?>" name="cpid"><?php echo $cpid; ?></td>
<td><?php echo $tid; ?></td>
<td><?php echo $type; ?></td>
<td><?php echo $pays; ?></td>
<td><input type="file" name="fileToUpload []" class="fileToUpload" ></td>
<input type="hidden" value="<?php echo $amt; ?>" name="fileToUploadLink []" class="fileToUploadLink" >
<td><input type="submit" value="Submit" name="submit" >
</button>
</td> </tr>
<?php } ?>
</tbody>
</table>
</form>
on upload.php
<?php
if(isset($_FILES['fileToUpload']['tmp_name'])&&isset($_POST['fileToUploadLink'])){
for($i=0;$i<=(count($_FILES['fileToUpload']['tmp_name'])-1);$i++){
move_uploaded_file($_FILES['fileToUpload']['tmp_name'][$i],$_POST['fileToUploadLink'][$i]);
}
}
?>

Answer 2

I have a few suggestions:
In your "php.ini" file, search for the file_uploads directive, and set it to On: file_uploads = On
...</button><!-- <<-- How are you using this? -->
Could try to echo $amt; at the bottom of the loop to see if the path is correct.
May want to check if the $amt with IF Empty condition/statement and maybe check the condition of your other variables.
$email1 = $_SESSION['email'];
$Vendor_id="SELECT Vendor_id FROM vendors where email = '$email1' ";
$result=mysqli_query($conn,$Vendor_id);
$row = mysqli_fetch_row($result);
$sql = "select Vendor_wallet_id, total_amount, request, amount, status, amt_pdflink from vendor_wallet";
$query = mysqli_query($conn, $sql);
?>
<form action="upload.php" method="post" enctype="multipart/form-data">
<table id="example1" class="table table-bordered table-striped">
<thead>
<tr>
<th>Transfer ID</th>
<th>Request</th>
<th>Amount</th>
<th>Status</th>
<th>Upload</th>
<th>Submit</th>
</tr>
</thead>
<tbody>
<?php
while ($row = mysqli_fetch_array($query))
{
$cpid=$row['Vendor_wallet_id'];
$tid=$row['request'];
$type=$row['amount'];
$pays=$row['status'];
$amt=$row['amt_pdflink'];
?>
<tr>
<td value="<?php echo $cpid; ?>" name="cpid"><?php echo $cpid;?></td>
<td><?php echo $tid;?></td>
<td><?php echo $type;?></td>
<td><?php echo $pays;?></td>
<td><input type="file" value="<?php echo $amt;?>" name="fileToUpload" id="fileToUpload" ></td>
<td><input type="submit" value="Submit" name="submit" >
</button> <!-- WHY IS THIS HERE? -->
</td></tr>
<?php
echo $amt; //See if it is correct path
}//END WHILE ?>
</tbody>
</table>
</form>

Answer 3

There are a few ways in which you could do the file upload, one of which would be to make the form a child of a single table cell and have the file field as a direct child of that form. The submit button, to keep the layout, would not be a child of the form and would need to be changed to a simple button input type then use javascript to submit the form
<?php
$email1 = $_SESSION['email'];
$Vendor_id = "SELECT Vendor_id FROM vendors where email = '$email1' ";
$result = mysqli_query($conn, $Vendor_id);
$row = mysqli_fetch_row($result);
$sql = "select Vendor_wallet_id, total_amount, request, amount, status, amt_pdflink from vendor_wallet";
$query = mysqli_query($conn, $sql);
?>
<table id="example1" class="table table-bordered table-striped">
<thead>
<tr>
<th>Transfer ID</th>
<th>Request</th>
<th>Amount</th>
<th>Status</th>
<th>Upload</th>
<th>Submit</th>
</tr>
</thead>
<tbody>
<?php
while( $row = mysqli_fetch_array( $query ) ) {
$cpid = $row['Vendor_wallet_id'];
$tid = $row['request'];
$type = $row['amount'];
$pays = $row['status'];
$amt = $row['amt_pdflink'];
?>
<tr>
<td value="<?php echo $cpid; ?>" name="cpid"><?php echo $cpid; ?></td>
<td><?php echo $tid; ?></td>
<td><?php echo $type; ?></td>
<td><?php echo $pays; ?></td>
<td>
<form action="upload.php" method="post" enctype="multipart/form-data">
<input type="file" value="<?php echo $amt; ?>" name="fileToUpload" />
</form>
</td>
<td><input type="button" value="Submit" name="submit" /></td>
</tr>
<?php
}
?>
</tbody>
</table>
<script>
var bttns=Array.prototype.slice.call(document.querySelectorAll('input[type="button"][name="submit"]'));
bttns.forEach(function(bttn){
bttn.addEventListener('click',function(evt){
this.parentNode.parentNode.querySelector('form').submit();
}.bind(bttn),false );
});
</script>

Answer 4

Seems like You want to make a form per row.
<tr>
<td value="<?php echo $cpid; ?>" name="cpid"><?php echo $cpid; ?></td>
<td><?php echo $tid; ?></td>
<td><?php echo $type; ?></td>
<td><?php echo $pays; ?></td>
<td colspan="2">
<form action="upload.php" method="post" enctype="multipart/form-data">
<input type="hidden" name="Vendor_wallet_id" value="<?php echo $cpid;?>" />
<input type="file" value="<?php echo $amt; ?>" name="fileToUpload" />
<button>Submit</button>
</form>
</td>
</tr>
</form>
and remove <form> tag that wraps table