What did i do wrong? Html is confusing itself - php

I'm making a page where you have to enter a text in a textbox and the click send, another page will save it.
Also, on the first page, the text that was stored previously in the database, has to load. This is the code that i've got:
<?php
$databaseid = 3;
$servername = "jog4fun.be.mysql";
$username = "jog4fun_be";
$password = "****";
$dbname = "jog4fun_be";
$gettitel1 = null;
$gettext1 = null;
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT Id,Titel,Tekst FROM Teksten";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
if ($row["Id"]== $databaseid ){
$gettitel1 = $row["Titel"];
$gettext1 = $row["Tekst"];
}
}
} else {
echo "0 results";
}
$conn->close();
$gettitel1 = strip_tags($gettitel1, '<br>');
$link1 = '<textarea id = "klein" rows="4" cols="50" name="titel3" form="usrform">' . $gettitel1 . '</textarea>';
$link2 = '<textarea id = "groot" rows="4" cols="50" name="text3" form="usrform">' . $gettext1 . '</textarea>';
echo $link1;
echo $link2;
?>
The problem is that it sends the text from textbox with name text3 as text1 with the post function. Can someone figure out what's wrong with it? I've been tying for an hour and i did not find it.
Thanks for your time and help,
Jonas

Simply here:
while($row = $result->fetch_assoc()) {
if ($row["Id"]== $databaseid ){
$gettitel1 = $row["Titel"];
$gettext1 = $row["Tekst"];
}
you overwrite the value of the two variables each time you iterate. So after this block of code you will keep stored the last values returned from the db.
YOu should add to your query a WHERE clause to identify the one and only record you need so you will fetch only the relevant data. Example:
$sql = "SELECT Id,Titel,Tekst FROM Teksten WHERE Id='1'";

Related

Trying to compare a value from the database from the url after the?

I'm trying to get a value from the database and compare it with whatever id href was set. But nothing happens.
<?php
$servername = "127.0.0.1";
$username = "root";
$password = "";
$dbname = "products";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id FROM items";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$id = $row["id"];
echo <<<EOT
<br>
<form action='index.php?$id' method="POST">
<input type='submit' name="submit" value="more">
</form>
EOT;
}
} else {
echo "0 results";
}
if (isset($_POST['submit'])) {
while($row = $result->fetch_assoc()) {
if ($_SERVER["QUERY_STRING"] == $row) {
echo 'you clicked something from the database' . $id;
}
}
}
$conn->close();
?>
Trying to eventually get a value from the database then individually show a description if the more href is clicked.
your answer has a high time complexity you can easily make you
SQL query
SELECT id FROM items WHERE id = ?
and if the rows number is 0 this is mean there is no record with this id
you can check row's number from num_rows
You will never see "you clicked something from the database" message because you already fetched the result from your query in the first loop, check this question why-cant-i-loop-twice-on-mysqli-fetch-array-results
An option is to save the result in an array to use it later in your second loop
//your first loop
$savedRows = [];
while($row = $result->fetch_assoc()) {
$savedRows[] = $row;
//the rest of your code
}
// ......
// your second loop
if (isset($_POST['submit'])) {
foreach($savedRows as $row) {
if ($_SERVER["QUERY_STRING"] == $row['id']) {
echo 'you clicked something from the database ' . $id;
}
}
}
Also note that if this is your actual code, you need to make the closing identifier of your herodoc EOT; the first character on it's line, otherwise the rest of the file will be part of this string

how to redirect to another page in php an mySql Database?

how can I redirect the user to another php page based on the button he is pressing?
For example .. I want that once loaded the page, in it are generated buttons containing the "id" of the table taken from a database ... At the click of the button you are redirected to a page in which there are textbox with the fields belonging to the table id ..
<?php
$servername = "localhost";
$username = "";
$password = "";
$dbname = "";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT idCantiere,nomeCantiere,codiceCommessa,indirizzoCantiere FROM Cantiere";
$result = $conn->query($sql);
echo'<h1> <font face="verdana" color="green">Quale Cantiere desideri Modificare?</font> </h1>';
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo'<br><br><br>';
echo'' . $row["nomeCantiere"] . '';
// echo '';
//''<input type="button" value="' . $row["nomeCantiere"] . '" />'
}
echo'<br><br><br>';
echo 'Nuovo Cantiere +';
} else {
echo "0 results";
}
$idCantierePerSelect = $_POST["idCantiere"];
global = $idCantierePerSelect;
function navigaButton()
{
// FUNCTION That redirect to the page
};
$conn->close();
?>
So I have to pick up the "idCantiere" and I have to make sure that by clicking on the button on the page that opens me there are textBox with the data of the table of the "idCantiere"
I think you are confusing the static html between dynamic server page.
1.PHP is responsible for fecthing data from database or server file system ,and send html tags to front end
2.the browser receives strings from php , and parse the strings to html elements ,finally starts to run javascript
If you want to redirect page.
In php header('Location: /your/path')
In javascript , window.location.href='/your/path'
Very quickly written and not tested - you could perhaps do like this. The function has to be javascript to interact with the client's actions ( ie: button press ) but the processing of the task is done by php. So, in the loop pass the ID of the record to the function as an inline argument and reload the same page with a new querystring. PHP will process the querystring, find the ID and then do a different database lookup to find the page that you want to redirect to.
<?php
$servername = "localhost";
$username = "";
$password = "";
$dbname = "";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) die("Connection failed");
/*
This section should be ignored when page loads normally
but will be processed when the `navigaButton` is called
and the url changes.
*/
if( $_SERVER['REQUEST_METHOD']=='GET' && isset( $_GET['action'],$_GET['id'] ) ){
$sql='select NEWLOCATION from TABLE where ID=?';
$stmt=$conn->prepare( $sql );
if( $stmt ){
$stmt->bind_param('i',$id);
$id=filter_input( INPUT_GET, 'id', FILTER_SANITIZE_NUMBER_INT );
$stmt->execute();
$stmt->store_result();
$stmt->bind_result( $url );
$stmt->close();
/* read the recordset and .... */
exit( header( 'Location: '.$url) );
}
}
?>
<!doctype html>
<html lang='en'>
<head>
<meta charset='utf-8' />
<title>.... </title>
<script>
function navigaButton(id){
location.search='action=redirect&id='+id
};
</script>
</head>
<body>
<?php
$sql = "SELECT idCantiere,nomeCantiere,codiceCommessa,indirizzoCantiere FROM Cantiere";
$result = $conn->query($sql);
echo'<h1> <font face="verdana" color="green">Quale Cantiere desideri Modificare?</font> </h1>';
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
echo'
<br><br><br>
' . $row["nomeCantiere"] . '
';
}
echo'<br><br><br>
Nuovo Cantiere +';
} else {
echo "0 results";
}
$idCantierePerSelect = $_POST["idCantiere"];
/* below is incorrect */
/*global = $idCantierePerSelect;*/
$conn->close();
?>
</body>
</html>

Trouble with PHP updating a database

Can I please have some help with a problem I'm having updating a mysql database with PHP.
I'm sorry to ask a question that has been asked a lot of times before, it's just driving me a bit nuts, and I've looked through similar questions but the answers don't seem to help with my problem.
I'm using two files, an admin page (admin.php) to edit content with, and an update file that is meant to update the database when the submit button is pressed.
Everything seems to be working fine, the values are being posted to the update.php page (I can see them when I echo them out) but it wont update the database.
If anyone can please point me in the right direction or tell me what I'm doing wrong I'd be very grateful!
Thank you very much:)
This is my admin.php page;
<head>
<?php
/*
Check to see if the page id has been set in the url.
If it has, set it as the $pageid variable,
If it hasn't, set the $pageid variable to 1 (Home page)
*/
if (isset($_GET['pageid'])) {
$pageid = $_GET['pageid'];
}
else {
$pageid = '1';
}
//Database connection variables
$servername = "localhost";
$username = "root";
$password = "";
$database = "cms";
// Create connection
$conn = new mysqli($servername, $username, $password, $database);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//Get information from the database
$sql = "SELECT title, sub_title, tab1, tab2, tab3, content FROM data WHERE id='$pageid'";
$result = $conn ->query($sql);
if ($result->num_rows > 0)
{
while($row = $result->fetch_assoc()) {
$conn->close();
//Store database information in variables to display in the form
$title = $row["title"];
$sub_title = $row["sub_title"];
$tab1 = $row["tab1"];
$tab2 = $row["tab2"];
$tab3 = $row["tab3"];
$content = $row["content"];
}
} else {
echo "0 results";
}
?>
</head>
<body>
//basic navigation
Page 1 | Page 2 | Page 3
<form action="update.php" method="post" name="adminform">
<input type="hidden" name="pageid" value="<?php echo "$pageid";?>">
NAME:<br>
<input type="text" name="title" value="<?php echo $title;?>"><br><br>
EMAIL:<br>
<input type="text" name="sub_title" value="<?php echo $sub_title;?>"><br><br>
CONTENT:<br>
<input type="text" name="tab1" value="<?php echo $tab1;?>"><br><br>
CONTENT:<br>
<input type="text" name="tab2" value="<?php echo $tab2;?>"><br><br>
CONTENT:<br>
<input type="text" name="tab3" value="<?php echo $tab3;?>"><br><br>
CONTENT:<br>
<textarea rows="4" cols="50" name="content">
<?php echo $content;?>
</textarea>
<br><br>
<input type="submit">
</form>
</body>
And this is the update.php page;
<?php
/*Values passed from the admin form, to be used as update variables*/
if (isset($_POST['adminform']))
{
$pageid = $_POST["pageid"];
$titleu = $_POST["title"];
$sub_titleu = $_POST["sub_title"];
$tab1u = $_POST["tab1"];
$tab2u = $_POST["tab2"];
$tab3u = $_POST["tab3"];
$contentu = $_POST["content"];
}
?>
<?php
if(isset($_POST['adminform']))
{
// Create connection
$conn = new mysqli($servername, $username, $password, $database);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//Update the database
$sql = "UPDATE data SET title='$titleu', sub_title='$sub_titleu', tab1='$tab1u', tab2='$tab2u', tab3='$tab3u', content='$contentu' WHERE id =='$pageid'";
$result = $conn ->query($sql);
$conn->close();
}
?>
You're using == instead of = on the where clause.
On the other hand, don't pass user values to the query without validation and sanitization if you don't want to be vulnerable to sql injection attacks.
$sql = "UPDATE data SET title='" . $conn->real_escape_string($titleu) . "', sub_title='" . $conn->real_escape_string($sub_titleu) . "', tab1='" . $conn->real_escape_string($tab1u) . "', tab2='" . $conn->real_escape_string($tab2u) . "', tab3='" . $conn->real_escape_string($tab3u) . "', content='" . $conn->real_escape_string($contentu) . "' WHERE id = " . (int)$pageid;
This will work, but is not very elegant solution. You may use prepared statements instead, to pass the correct types and prevent sql injection.
Check your DB Connections and test whether you are connected to DB or not.
Change your query as below
$sql = "UPDATE data SET title='".$titleu."', sub_title='".$sub_titleu."', tab1='".$tab1u."', tab2='".$tab2u."', tab3='".$tab3u."', content='".$contentu."' WHERE id ='$pageid'";

How to UPDATE only filled input with a submit button?

PROBLEM: I got a problem updating my input into sql using PHP, the PHP updates all empty values into sql which I don't want to.
ACHIEVEMENT: So I hope to achieve when user submit their data either empty or filled then PHP might be able to pickup and update only filled data into my sql. I tried using input with value=">php echo here<" but it won't work with textarea, so I couldn't find any solution since I'm new to PHP and SQL. Tried to find similar posts but I couldn't make them work like I wanted to :(
<?php include 'config/sqlconnect.php'; ?>
<form method="post" action"config/sqlconnect.php">
</p>MainPage info</p>
<input type="text" name="mainPageInfo"/>
<br>
</p>MiddlePage info</p>
<textarea name="middlePageInfo"></textarea>
<br>
</p>Container info</p>
<input type="text" name="containerInfo"/>
<br>
</p>Content</p>
<input type="text" name="content"/>
<br>
</p>Second content</p>
<input type="text" name="secondContent"/>
<input type="submit" name="submit" class="btn-block"/>
<br>
</form>
in PHP script
<?php
$servername = "localhost";
$username = "root";
$password = "pass";
$dbname = "pagesDb";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
mysqli_set_charset($conn,"utf8");
$sql = "SELECT * FROM myPages";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$mainPageInfo = $row['mainPageInfo'];
$middlePageInfo = $row['middlePageInfo'];
$containerInfo = $row['containerInfo'];
$content = $row['content'];
$secondContent = $row['secondContent'];
}
} else {
echo "0 results";
}
if (isset($_POST['submit'])) {
$mainPageInfo = $_POST['mainPageInfo'];
$middlePageInfo = $_POST['middlePageInfo'];
$containerInfo = $_POST['containerInfo'];
$content = $_POST['content'];
$secondContent = $_POST['secondContent'];
$sql = "UPDATE myPages SET mainPageInfo='$mainPageInfo',
middlePageInfo='$middlePageInfo',
containerInfo='$containerInfo',
content='$content',
secondContent='$secondContent'
WHERE id=0";
if ($conn->query($sql) === TRUE) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . $conn->error;
}
}
$conn->close();
?>
Second Attempts: It doesn't update my data somehow... please help I tried more than 8 hours with no results :(
if (isset($_POST['submit'])) {
foreach($_POST as $name => $value) {
$sql = "UPDATE myPages SET $name = '$value' WHERE id=1";
}
if ($conn->query($sql) === TRUE) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . $conn->error;
}
}
Help would be appreciated, thanks everyone!
Using your Second Attempt as a starting point.
The problem with just using the POST array without being specific is that, in this example you are going to try an update a column on the database called submit i.e. your submit button. Later there may be data on the page that belongs in 2 or more tables.
So create an controlling array containing all the field names from the form that you want to process onto your table.
$db_fields = array('mainPageInfo', 'middlePageInfo', 'containerInfo',
'content', 'secondContent');
$sql = ''; // will hold the query we build dynamically
// was this a user sending data
if ( $_SERVER['REQUEST_METHOD' == 'POST' ) {
foreach($db_fields as $fieldname) {
if ( ! empty($_POST[$fieldname] ) {
$sql .= "$fieldname = '{$_POST[$fieldname]}', ";
}
}
}
$sql = rtrim($sql, ','); // remove the trailing comma
$sql = "UPDATE myPages SET $sql WHERE id=1";
if ($conn->query($sql) === TRUE) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . $conn->error;
}

PHP : to display only new row of a table in bold and rest without any formating (data will be entered by the user)

I need to display every new row in bold that will be stored in database in php and and then display it. Only the new row should be bold. Here's what I did
<?php
//connection
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "resultdb"; //my database name
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
?>
<?php
$name=$_POST['name'];
$roll=$_POST['roll'];
$m1=$_POST['m1'];
$m2=$_POST['m2'];
$m3=$_POST['m3'];
//ISNERT DATA INTO TADABASE
$sql="INSERT INTO markstb(name,rollno,sub1,sub2,sub3) VALUES('$name','$roll','$m1','$m2','$m3')";
if($conn->query($sql)===true)
{
//ketp id column in DB to auto_increment
$last_id=mysqli_insert_id($conn);
echo " NEW RECORD INSERTED"."<br>";
if($last_id>0)
{
$sql3="SELECT * FROM markstb WHERE id='$last_id'";
$result = $conn->query($sql3);
echo "<table border='2' bordercolor='black' ";
echo"<tr><td>NAME</td><td>ROLLNO</td><td>SUB1</td><td>SUB2</td><td>SUB3</td></tr>";
while($row=$result->fetch_assoc())
{
echo"<tr><td><b>".$row['name']."</td><td><b>".$row['rollno']."</td><td><b>".$row['sub1']."</td>"
."<td><b>".$row['sub2']."</td><td><b>".$row['sub3']."</td>";
}
echo "</table>";
}
else
{
echo"check last_id";
}
echo "<br><br><br><br>";
}
else
{
echo "ERROR".$sql."<br>".$conn->error;
}
//RETRIVE DATA FROM DATABASE
$sql2="SELECT * FROM markstb ORDER BY name";
//$result=$conn->query($sq2);
$result = $conn->query($sql2);
echo "<table border='2' bordercolor='black' ";
if($result->num_rows > 0)
{
echo"<tr><td>NAME</td><td>ROLLNO</td><td>SUB1</td><td>SUB2</td><td>SUB3</td></tr>";
while($row=$result->fetch_assoc())
{
echo"<tr><td>".$row['name']."</td><td>".$row['rollno']."</td><td>".$row['sub1']."</td>"
."<td>".$row['sub2']."</td><td>".$row['sub3']."</td>";
}
echo "</table>";
}
else
{
echo" 0 rows";
}
$conn->close();
?>
In above program I have ony fetched the row which is new and made it bold
but I have to show all data that is in database and make only row bold which is new, which is entered by the user.
In your last while loop you could try:
if($row['id'] == $last_id){
//echo "your row that is
//bold
}else{
// echo you regular row
}
When you are printing out the data, you can do this type of thing inside of the echo statement:
echo "<tr" . $last_id === (int) $row['id] ? . ' class="bold"' : null; . "><td>...";
So that means, when you are printing the tag, you are checking if the row id matches the last id, if so you are additionally printing a html class of "bold".
Of course, it's up to you to use css to target this selector and actually make it bold.
That is called the 'ternary if'. It looks like this:
condition ? do this if true : do this if false;

Categories