getting array value from json array PHP

getting array value from json array PHP - php

Checking at the structure of the json got from the call, to access the value you want to need to do like this.
$string = file_get_contents("https://maps.googleapis.com/maps/api/place/nearbysearch/json?location=-33.8670522,151.1957362&rankby=distance&types=food&key=AIzaSyCpOG91fkAzPTZiFq7G9HbLfbmVyW8Wgyc");
$json_a = json_decode($string, true);
print_r($json_a['results'][0]['name']));
Results is an array, and you want to access to its first element ([0]). From that first element you want to get the property name. And all the properties on the element are set inside an array, so you need to access it by the property name.
You were using the object operator (->) to access elements from an array, that's why it didn't work.

echo print_r(....); is in a way redundant. print_r it self prints result to output in similar way as echo and returns TRUE which is what you are printing.
From documentation:
mixed print_r ( mixed $expression [, bool $return = false ] )
When the return parameter is TRUE, this function will return a string. Otherwise, the return value is TRUE.
Either do not use echo or set the return param to TRUE.
echo print_r($array, true);

Related

Show multiple api result photos on google map

you should first check if photo key is exist in $resp['results'][$i] array by using isset function in php
for example
if(isset($resp['results'][$i]['photos']) && count($resp['results'][$i]['photos']) > 0)
{
// write your code
}
and also you should use phpenter code here count function to check $resp['results'][$i]['photos'] array has multi entry
so you can write $resp['results'][$i]['photos'][0] without have out of scope error

get country, region and city name from longitude and latitude (PHP)

Proper way to extract values of address components is done as following :
if (results[0]) {
$("input[name=lat]").val(results[0].geometry.location.lat());
$("input[name=lng]").val(results[0].geometry.location.lng());
var addressArr = [];
$.each(results[0].address_components, function (key, val) {
if (!$.inArray("country", results[0].address_components[key].types)) {
addressArr['country'] = results[0].address_components[key].long_name;
}
if (!$.inArray("administrative_area_level_1", results[0].address_components[key].types)) {
addressArr['state'] = results[0].address_components[key].long_name;
}
if (!$.inArray("administrative_area_level_2", results[0].address_components[key].types)) {
addressArr['city'] = results[0].address_components[key].long_name;
}
});
console.log(addressArr);
}
}

I have some similar code that is known to work. Basically it can return a results array if there are more than one results possible or just an object if only one result is found. My use-case is slightly different, but hopefully it helps. Try this:
$ch = curl_init();
$geoCodeUrl = 'https://maps.googleapis.com/maps/api/geocode/json?address=' . $zip . ',+United+States&key=' . $googleApiKey;
curl_setopt($ch,CURLOPT_URL, $geoCodeUrl);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_TIMEOUT, 5);
$result = curl_exec($ch);
curl_close($ch);
$GeoCode = json_decode($result);
$GeoLocator = new \stdClass();
if( isset($GeoCode->results[0]) ){
$GeoLocator->lat = $GeoCode->results[0]->geometry->location->lat;
$GeoLocator->lon = $GeoCode->results[0]->geometry->location->lng;
foreach($GeoCode->results[0]->address_components as $comp){
if( in_array('locality',$comp->types) ){
$GeoLocator->city = trim($comp->short_name);
}
else if( in_array('administrative_area_level_1',$comp->types) ){
$GeoLocator->state = strtoupper(trim(preg_replace('/\d/', '', $comp->short_name)));
}
}
}
else if( isset($GeoCode->results) && isset($GeoCode->results->geometry) ){
$GeoLocator->lat = $GeoCode->results->geometry->location->lat;
$GeoLocator->lon = $GeoCode->results->geometry->location->lng;
foreach($GeoCode->results->address_components as $comp){
if( in_array('locality',$comp->types) ){
$GeoLocator->city = trim($comp->short_name);
}
else if( in_array('administrative_area_level_1',$comp->types) ){
$GeoLocator->state = strtoupper(trim(preg_replace('/\d/', '', $comp->short_name)));
}
}
}

Getting the distance between two locations using Google Maps Api (JSON)

For finding the first value of routes, you can use below code :-
$json_a['routes'][0]['legs'][0]['distance']['text']
If you want to show all values then use foreach.
For sorting on values
function cmp($a, $b)
{
if ($a == $b) {
return 0;
}
return ($a < $b) ? -1 : 1;
}
$a = array(3, 2, 5, 6, 1);
usort($a, "cmp");
foreach ($a as $key => $value) {
echo "$key: $value\n";
}

Php foreach remove duplicate using value [duplicate]

Since the sub-arrays are not identical then the serialize solution will not work. This assumes removing based on identical idvox_business:
$ids = array();
foreach($array as $key => $vals) {
if(in_array($vals['idvox_business'], $ids)) {
unset($array[$key]);
} else {
$ids[] = $vals['idvox_business'];
}
}
Or possibly:
foreach(array_column($array, 'idvox_business') as $key => $id) {
$result[$key] = $array[$key];
}

Postcode of visitor location PHP

On my page I have a number of registered users, each user has a postcode stored in their row in my table.
I'm wondering if its possible and if so how to get the postcode of my website visitors and then show them the nearest users going of the data in my table?

You can use HTML 5 Geolocation to ask them to provide their location to you. Then you could lookup what the nearest postal code is based on their longitude/latitude.
You can get free postal/zip data with long/lat for North America here:
http://geocoder.ca/?freedata=1

If you can determine the coordinates of the visiting user in an accurate way you could use the google reverse geocoding API to translate the coordinates to an address and use the zipcode from that address.
Determining accurate coordinates of a visitor could prove difficult though. You'll have to rely on a GeoLocation api like http://www.maxmind.com/app/php or do an implementation of the HTML5 GeoLocation API.

You need to populate latitude/longitude for each record, then use Google Maps to find out nearest users, I believe following links will help you out.
Get latitude and longitude based on location name with Google Autocomplete API
Google Maps Api v3 - find nearest markers

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getting array value from json array PHP - php

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