I am new to programming and am experimenting with sessions. I believe the code I have written is correct but after spending time trying to wrap my head around the concept, I am not able to figure out why the program isn't working.
When I debugged the code in the session-page.php, control goes to if(isset...) but then instead of entering the code block or showing a submit button on the browser, simply moves to the next session variable. Someone please be kind enough to explain it to me why this thing ain't working.
Also, can I not use <form> and simply use isset($_GET[ ])?
session-page.php[CODE]
<?php
session_start();
if(isset($_POST['sub']))
{
$_SESSION['xyz']="Hello World";
}
$_SESSION['abc']="Hey Buddy!";
?>
<form method="post">
<input type='submit' name='sub' value='redirect'>
</form>
test-page.php[CODE]
<?php
session_start();
if($_SESSION['xyz']!="Hello World")
{
header("location:session-page.php");
}
echo $_SESSION['abc'];
?>
You want to have this type of workflow (based on what you currently have):
/session-page.php
<?php
session_start();
if(!empty($_POST['sub'])) {
$_SESSION['xyz'] = "Hello World";
header('Location: test-page.php');
exit;
}
if(empty($_SESSION['abc']))
$_SESSION['abc']="Hey Buddy!";
?>
<form method="post" action="#">
<input type='submit' name='sub' value='redirect'>
</form>
/test-page.php
<?php
session_start();
if($_SESSION['xyz'] != "Hello World") {
header("location:session-page.php");
exit;
}
echo $_SESSION['abc'];
?>
try this.
<form method="post" action="" >
<input type='submit' name='sub'value='redirect'>
</form>
Related
I am trying to make a form that echos out whatever the user inputs into the 'name' field, but, I cannot figure out why when I add an if statement, nothing in the code shows up.
Here is my index.php code:
<?
if (empty($_POST['name'])) {
echo "Hello world!";
} else {
echo "Hello $_POST['name']";
}
?>
<html>
<head>
<?php include 'header.php'; ?>
</head>
<body>
<form action="index.php" method="post">
<p>Name: <input type="text" name="name"></p>
<input type="submit" name="submit" value="Go">
</form>
</body>
<footer>
<?php include 'footer.php'; ?>
</footer>
</html>
The valid syntax for adding an array into echo is:
echo "Hello {$_POST['name']}";
Or concatenate it using:
echo "Hello " . $_POST['name'];
Reference: echo
Make sure you enable errors while debugging:
error_reporting(E_ALL);
ini_set('display_errors', 1);
Problem, seems to be with php short tag <? which might not enabled, try using <?php or enable short tag in php.ini
The page is reloading index.php with your form. change <form action="index.php" method="post"> to <form action="" method="post">
You can't echo array inside "" quotes.
Try this (var in {}):
echo "Hello {$_POST['name']}";
Or this (with string operator):
echo "Hello " . $_POST['name'];
Simple php code to post a value and echo it inside if(isset()), when click on submit button, but it's not working.
<?php
if(isset($_GET['q']))
{
$q=$_GET['q'];
//echo "thisss iss qqqq".$q; this is working
$_SESSION['q']=$q;
if($q=="1")
{
?>
<form action='#'>
<tr>
<input type='text' name='txt_code' >
<input type='submit' name='code_sub' value='Showcd'>
</tr>
</form>
<?php
}
//here I wrote code for to echo $bkCode when click on 'showcd' button but it's not working
<?php
if (isset($_POST["code_sub"]))
{
echo $bkCode=$_POST['txt_code']; // THIS IS NOT WORKING
}
}
?>
It doesn't even enter inside the if (isset($_POST["code_sub"])) part
Default action of a form is GET. You have to specify that u want to do a POST :
<form action="#" method="POST">
A first, you should set the var, and after that a simple output:
<?php
if (isset($_POST["code_sub"]))
{
$bkCode=$_POST['txt_code']; // THIS IS WORKING
echo $bkCode;
}
?>
Also you need to set the form method to "POST"!
<form action='the_link' method="POST">
For using the post method
<form action='the_link' method="POST">
This will help ..:)
I have a PHP form that is located on file contact.html.
The form is processed from file processForm.php.
When a user fills out the form and clicks on submit,
processForm.php sends the email and direct the user to - processForm.php
with a message on that page "Success! Your message has been sent."
I do not know much about PHP, but I know that the action that is calling for this is:
// Die with a success message
die("<span class='success'>Success! Your message has been sent.</span>");
How can I keep the message inside the form div without redirecting to the
processForm.php page?
I can post the entire processForm.php if needed, but it is long.
In order to stay on the same page on submit you can leave action empty (action="") into the form tag, or leave it out altogether.
For the message, create a variable ($message = "Success! You entered: ".$input;") and then echo the variable at the place in the page where you want the message to appear with <?php echo $message; ?>.
Like this:
<?php
$message = "";
if(isset($_POST['SubmitButton'])){ //check if form was submitted
$input = $_POST['inputText']; //get input text
$message = "Success! You entered: ".$input;
}
?>
<html>
<body>
<form action="" method="post">
<?php echo $message; ?>
<input type="text" name="inputText"/>
<input type="submit" name="SubmitButton"/>
</form>
</body>
</html>
The best way to stay on the same page is to post to the same page:
<form method="post" action="<?=$_SERVER['PHP_SELF'];?>">
There are two ways of doing it:
Submit the form to the same page: Handle the submitted form using PHP script. (This can be done by setting the form action to the current page URL.)
if(isset($_POST['submit'])) {
// Enter the code you want to execute after the form has been submitted
// Display Success or Failure message (if any)
} else {
// Display the Form and the Submit Button
}
Using AJAX Form Submission which is a little more difficult for a beginner than method #1.
You can use the # action in a form action:
<?php
if(isset($_POST['SubmitButton'])){ // Check if form was submitted
$input = $_POST['inputText']; // Get input text
$message = "Success! You entered: " . $input;
}
?>
<html>
<body>
<form action="#" method="post">
<?php echo $message; ?>
<input type="text" name="inputText"/>
<input type="submit" name="SubmitButton"/>
</form>
</body>
</html>
Friend. Use this way, There will be no "Undefined variable message" and it will work fine.
<?php
if(isset($_POST['SubmitButton'])){
$price = $_POST["price"];
$qty = $_POST["qty"];
$message = $price*$qty;
}
?>
<!DOCTYPE html>
<html>
<head>
<title></title>
</head>
<body>
<form action="#" method="post">
<input type="number" name="price"> <br>
<input type="number" name="qty"><br>
<input type="submit" name="SubmitButton">
</form>
<?php echo "The Answer is" .$message; ?>
</body>
</html>
You have to use code similar to this:
echo "<div id='divwithform'>";
if(isset($_POST['submit'])) // if form was submitted (if you came here with form data)
{
echo "Success";
}
else // if form was not submitted (if you came here without form data)
{
echo "<form> ... </form>";
}
echo "</div>";
Code with if like this is typical for many pages, however this is very simplified.
Normally, you have to validate some data in first "if" (check if form fields were not empty etc).
Please visit www.thenewboston.org or phpacademy.org. There are very good PHP video tutorials, including forms.
You can see the following example for the Form action on the same page
<form action="" method="post">
<table border="1px">
<tr><td>Name: <input type="text" name="user_name" ></td></tr>
<tr><td align="right"> <input type="submit" value="submit" name="btn">
</td></tr>
</table>
</form>
<?php
if(isset($_POST['btn'])){
$name=$_POST['user_name'];
echo 'Welcome '. $name;
}
?>
simple just ignore the action attribute and use !empty (not empty) in php.
<form method="post">
<input type="name" name="name">
<input type="submit">
</form>
<?PHP
if(!empty($_POST['name']))
{
echo $_POST['name'];
}
?>
Try this... worked for me
<form action="submit.php" method="post">
<input type="text" name="input">
<input type="submit">
</form>
------ submit.php ------
<?php header("Location: ../index.php"); ?>
I know this is an old question but since it came up as the top answer on Google, it is worth an update.
You do not need to use jQuery or JavaScript to stay on the same page after form submission.
All you need to do is get PHP to return just a status code of 204 (No Content).
That tells the page to stay where it is. Of course, you will probably then want some JavaScript to empty the selected filename.
What I do is I want the page to stay after submit when there are errors...So I want the page to be reloaded :
($_SERVER["PHP_SELF"])
While I include the sript from a seperate file e.g
include_once "test.php";
I also read somewhere that
if(isset($_POST['submit']))
Is a beginners old fasion way of posting a form, and
if ($_SERVER['REQUEST_METHOD'] == 'POST')
Should be used (Not my words, read it somewhere)
I have 2 php files in my folder. In page1.php, there's a textarea, user should enter some values in it. In page2.php, it will grab what is in the textarea and work with its program. But I can't find a command that grabs the value in textarea. Can someone help me?
page1.php:
<?
$hello = "hello";
?>
<html>
<input type = "text" name = "user_input">
</input>
</html>
page2.php
<?
ob_start();
include 'page1.php';
ob_end_clean();
echo $hello;
?>
So, is there anyone that can solve this? =/
Use $_GET or $_POST in page2.php
page1.php
<?
$hello = "hello";
?>
<html>
<form method="get" action="page2.php" enctype="multipart/form-data">
<input type = "text" name = "user_input">
<input type="submit">
</form>
</html>
page2.php
<?
$text=$_GET['user_input'];
ob_start();
include 'page1.php';
ob_end_clean();
echo $hello;
echo $text;
?>
You may use either $_GET['user_input'] or $_POST['user_input'].
The difference is, you can see the data in the url (visible to everyone) when using GET method and not in the other method.
Also, always use <input> elements (which you want to pass to another file) inside a <form> and specify action="file.php", to where you want to pass data, and the method, either method="get" or method="post", like;
<form method="get" action="page2.php">
also specify the method to grab data in the target file also, like;
$text=$_GET['user_input']; or $text=$_POST['user_input'];
And in your case, you may use;
Method 1
<?php
$hello = "hello";
?>
<html>
<form method="get" action="page2.php">
<input type="text" name="user_input">
<input type="submit">
</form>
</html>
page2.php
<?php
$text=$_GET['user_input'];
echo $text;
?>
Method 2
<?php
$hello = "hello";
?>
<html>
<form method="post" action="page2.php">
<input type="text" name="user_input">
<input type="submit">
</form>
</html>
page2.php
<?php
$text=$_POST['user_input'];
echo $text;
?>
If you want to share the data over a number of pages, you may do this using PHP Session or saving the data in a cookie.
1. Using Sessions
<?php
session_start();
$_SESSION['data'] = 1; // store session data
echo "Pageviews = ". $_SESSION['data']; //retrieve data
?>
Make sure you add session_start(); on every page you want to handle session
You can read more about php sessions here www.tizag.com/phpT/phpsessions.php/
2. Using Cookie
<?php
setcookie("user", "Alex Porter", time()+3600);
?>
and retreive it using
echo $_COOKIE["user"];
You can read more about php sessions here http://www.w3schools.com/php/php_cookies.asp
hope this helps...:)
basically your page1.php is a page with some form in it with a text area. Now user will have to fill it and submit the form to page2.php. You can't echo it's content like that, because that will be on browser subject to user actions. Use a form and submit the data to page2.php. Like this:
page1.php
<html>
<head>
</head>
<body>
<form action="page2.php" method="post">
<textarea name="t1">
</textarea>
</form>
</body>
</html>
page2.php
<?php
$textAreaContents = isset($_POST['t1'])?$_POST['t1']:'';
echo "You submitted: ".$textAreaContents;
?>
if i were you i should use sessions for this. that is where they were made for..
example:when user clicks on submit.
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST')
{
$_SESSION['post'] = $_POST;
}
that is where every post variable will be put in a session.
and your inputbox will be something like this..
<textarea name="message" type="text" value="" rows="0" cols="0" placeholder="" ><?php if(isset($_SESSION['post'])){echo $_SESSION['post']['message'];} ?></textarea>
?>
note that you now can use every post variable that you used in your form by echo (example)
echo $_SESSION['post']['message']
where message is the name of the inputbox. in this case of the textarea
don't forget that at the end when you don't want to use the session anymore use session_destroy(); otherwise you will keep having it in your form. and don't forget session_start(); above every page where you are planning to use sessions ( it must be at 1st line of your document at all times)
I am using Win XP os and XAMPP. I was using eclipse as the editor. In Eclipes I was not able to redirect next page so now I have installed Zend Development Environment.
Now also I am getting the same problem.
My Code is
HomePage.php
<html>
<body>
<form name="Form1" id="FormId" action="Welcome.php" method="post">
name : <input type="text" name="txtName">
Phone Number : <input type="text" name="txtPnum">
<input type="submit" name="SubmitIt" value="Submit It">
</form>
</body>
</html>
And Welcome.php is
<?php
ob_start();
session_start();
if(!($_SESSION['UName']))
{
$_SESSION['UName']=$_POST['txtName'];
}
if(!($_SESSION['Ph Num']))
{
$_SESSION['Ph Num']=$_POST['txtPnum'];
}
?>
<html>
<body>
Welcome <?php
if(isset($_SESSION['UName']))
{
echo $_SESSION['UName'];
}
else
{
echo "Session not set<br/>";
echo "{$_SESSION['UName']}";
echo "The session contains <br>";
print_r($_SESSION);
}
?>
</body>
</html>
Its working fine (redirecting to next page) in the Browser but its not working in the debug mode. Both in Eclipse and Zend Development Environment.
Instead of show the content of the next page, it showing the page name.(Welcome.php in my example).
Should I need to install any other extra softwares or code itself worng.... Whats the problem. Please suggest me.
Thanks in advance....!
which part is supposed to make a redirection, i don't see any header('Location: redirect.php') or something
and why do you use ob_start() here .
you didnt release the output buffer add ob_get_clean(); in the end
<?php
ob_start();
session_start();
if(!($_SESSION['UName']))
{
$_SESSION['UName']=$_POST['txtName'];
}
if(!($_SESSION['Ph Num']))
{
$_SESSION['Ph Num']=$_POST['txtPnum'];
}
ob_end_flush();
?>
<html>
<body>
Welcome <?php
if(isset($_SESSION['UName']))
{
echo $_SESSION['UName'];
}
else
{
echo "Session not set<br/>";
echo "{$_SESSION['UName']}";
echo "The session contains <br>";
print_r($_SESSION);
}
?>
</body>
</html>
try to add this at the end of your code i am pretty sure it is because you are not releasing the output buffer, although i think it should have done it automatically
echo ob_get_clean();
Update:
I am not really sure why you are using the $_SESSION variable here, but is you want to fix the problem, you can use for example $uname instead of $_SESSION['UName'];
Welcome.php
<?php // at the beginning of your file, no spaces or newline
session_start();
$uName=$_POST['txtPnum'];
$txtPnum=$_POST['txtPnum'];
$_SESSION['UName'] = $uName;
$_SESSION['PhNum'] = $uName;
?>
<html>
<body>
Welcome <?php echo $_SESSION['UName']; ?>
</body>
</html>
you get rid of the ob start since you are still debugging your code. and try one step at a time.
Wish you good look.