PHP ordering json array format - php

Question

Im trying to get a json array, from a sql database which needs to be in the above format
{
"data":[
{
"name": "foo",
"age":"bar"
},
{
"name": "hello",
"age":"hi"
},
{
"name": "bar",
"age":"foo"
},
]
}
My code below return the data like,
{
"0": [
"name" : "blah",
"age" : "bleh"
],
"1": [
"name": "bleh",
"age" : "blah"
],
"data": []
}
CODE
$_SESSION['userID'] = $userID;
include('USERconfig.php');
$dataArray = array("data"=>array());
$sql = "SELECT name, age FROM dataQue";
$stmt = sqlsrv_query( $conn, $sql );
if( $stmt === false) {
die( print_r( sqlsrv_errors(), true) );
}
while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ) {
array_push($dataArray,
array("name"=>$row['name'],"age"=>$row['age']));
}
sqlsrv_free_stmt( $stmt);
header('Content-Type: application/json');
echo json_encode($dataArray);
exit();
How can i get all the data to be appended within the 'data' array?
And how can i get rid of the "0","1","2" ect.. ?
thanks in advance!

Answer 1

array_push() will insert data into the array after what you already have in it, I suggest you change the way you insert data in it by just calling back the array in the loop like this
$i = 0;
while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ) {
$dataArray['data'][$i]['name'] = $row['name'];
$dataArray['data'][$i]['age'] = $row['age'];
$i++;
}
this way all data retrieved from your query will be added to date index. By adding index ($i) will avoid replacing previous register.

Answer 2

You can use :
json_decode($dataArray);
add TRUE to json_decode like :
$dataArray = '{"data":[{"name": "foo","age":"bar"},
{"name": "hello","age":"hi"},
{"name": "bar","age":"foo"}]}';
print_r(json_decode($dataArray, true));
the result will be:
Array(
[data] => Array
(
[0] => Array
(
[name] => foo
[age] => bar
)
[1] => Array
(
[name] => hello
[age] => hi
)
[2] => Array
(
[name] => bar
[age] => foo
)
))