Get part of PHP file from URL - php

Question

Is it possible to take a specific part of code from one php file. For a project I have 12 page templates. So in WordPress when I make a new page and want to select a page template, a long list will appear with 12 months.
Here an example of couple months.
Januari, Fabruari, Maart, April etc..
So the question will be, is it possible to place all php code in one page template. And when you go to a specific url it takes a look to the end of the domain and based on that one part of php code..
Example:
www.domain.com/januari
Takes the part from the url /januari
This is Januari
www.domain.com/februari
Takes the part from the url /februari
This is Februari
In future there will be a lot of page templates so it will look really messy. It should be cleaner if there will be one page template "Months" with all content in it. Hope you understand the problem!
Thanks!

Answer 1

You can use the global $_SERVER['REQUEST_URI'] to identify which path was used to get to your PHP script. Then you can print the specific parts based upon if conditions or a switch case:
For the url www.domain.com/januari $_SERVER['REQUEST_URI'] will be /januari, for www.domain.com/februari ir will be /februari, etc...
switch($_SERVER['REQUEST_URI']) {
case '/januari':
//January code here
break;
case '/februari':
//February code her
break;
//...
}
But note, that for the URL www.domain.com/januari?some=get&params $_SERVER['REQUEST_URI'] will be /januari?some=get&params.

Answer 2

You don't need to use any PHP methods for that.
Just use the concept of Page Slug in Wordpress.
here is the code which gives you the slug of current opened page.
<?php
global $post;
$post_slug = $post->post_name;
switch ($post_slug) {
case 'january':
// page for January
get_template_part('template-parts/january');
break;
case 'februari':
// page for februari
get_template_part('template-parts/februari');
break;
... and so on
}
By getting slug into variable '$post_slug' you can apply your conditional statements to compare the value with your paremeters.
OR also you can prefer is_page() method of wp to compare current page with your params.

Answer 3

There are a number of approaches to this problem. My approach will let you keep separate PHP files for each month but only one Page Template will be used.
Let's say page-template-month.php is your template file. And your month specific files have the following structure
theme-root /
- template-parts /
- - january.php
- - february.php
...
Now, the approach to get your specific query term and build logic around it.
Using get_the_ID()
The above function returns the post/page ID and you can build your logic around that ID. Now, your page-template-month.php file will have the following snippet
switch( get_the_ID() ) {
case 5:
// let's assume it's the page for January
get_template_part( 'template-parts/january' );
break;
case 18:
// let's assume it's the page for February
get_template_part( 'template-parts/february' );
break;
}

Answer 4

You can with get the actual link with and cut it
$actualLink = "$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$whatYouWant = substr($actualLink, strpos($actualLink, "/")[1]);
But why not use $_GET ?