How do I get decimal values? - php

I have two columns on my database, sickleave and vacationleave. It has to be a decimal but for some reason I only get the whole number. For example, I input 1.50, when I press update I get the value 2. I tried setting the column type to decimal but I still get the same result.
Here's my database schema:

From the mysql documentation:
The declaration syntax for a DECIMAL column is DECIMAL(M,D). The ranges of values for the arguments are as follows:
M is the maximum number of digits (the precision). It has a range of 1 to 65.
D is the number of digits to the right of the decimal point (the
scale). It has a range of 0 to 30 and must be no larger than M.
So in your case: hit change button there and in the Length/value column there should be: 11,2 with no parentheses or anything else when you hit save
In case you want to do it manually there's a discussion of it here: MySQL - How do I update the decimal column to allow more digits?
And here's the alter: ALTER TABLE YourTableName MODIFY COLUMN column_name DECIMAL(11,2);

Tried altering it manually using:
ALTER TABLE YourTableName MODIFY COLUMN price DECIMAL(4,2);
Thanks #user3647971

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I have to put the price of some items inside a mysql table. When creating the table I'm using DECIMAL(10,2) as I don't need more than 2 digits after the comma (for example: 123,45 would be accepted as an input but 123,456 would be rounded to 123,45 with PHP).
First question: using DECIMAL(10,2), how do I know how many numbers may be stored before the comma? I know it is not 10, as 10 is just the precision Mysql uses when doing math with those numbers: so where the length of the number itself is specified?
Second question: I'm using PHP to round user input to fit the data type (float with 2 numbers after the comma). How should I use mysqli->bind_param to insert those data? Which of these datatypes (from the documentation) accepted by bind_param should I use (and possibly: why)?
Character Description
i corresponding variable has type integer
d corresponding variable has type double
s corresponding variable has type string
b corresponding variable is a blob and will be sent in packets
DECIMAL(10,2) means that 10 is the maximum number of digits to be used. The 2 specifies that there are two on the right side of the decimal. So this means there are 8 digits left on the left side. See the manual
As for the datatype, you should use double as this is for decimal numbers.
Integer has no decimal chars, so it will floor all numbers. String is for text and not numeric values. Blob is for a binary large object, EG: an image

pdo parameter is whole number, append decimal to it

I'm running an insert using PDO parameter values, and it's working fine, but I'm getting a lot of zeroes where I should have 0.65, 0.7, etc.
The issue is, its inserting into a decimal field and the sql insert is
count(*) / :value
In this case, :value is '1' so instead of dividing the count by 1, I want to divide by 1.0 specifically.
Can I append a decimal and zero to my parameter?
perhaps different approach... ALTER TABLE xxx ALTER COLUMN YYY theColumnName decimal(4,2) or whatever you need, then it will not add zeros after second decimal place

How can I make my MySQL table save a float up to 20 digits?

Here is my table:
Let us suppose I want my account balance to be:
0.4729472846758294728572
So I tried to set it to it but it keeps cutting it off and rounding up.
How can I stop this behavior?
FLOAT values are approximate:
The FLOAT and DOUBLE types represent approximate numeric data values.
If you need arbitrary precision you can use a DECIMAL column instead, e.g. DECIMAL(25, 20). In this case you'll get 5 digits before the decimal and 20 after.
MySQL permits a nonstandard syntax: FLOAT(M,D) or REAL(M,D) or DOUBLE PRECISION(M,D). Here, (M,D) means than values can be stored with up to M digits in total, of which D digits may be after the decimal point. For example, a column defined as FLOAT(7,4) will look like -999.9999 when displayed. MySQL performs rounding when storing values, so if you insert 999.00009 into a FLOAT(7,4) column, the approximate result is 999.0001.
see here:https://dev.mysql.com/doc/refman/5.7/en/floating-point-types.html,
http://code.rohitink.com/2013/06/12/mysql-integer-float-decimal-data-types-differences/

data field type for decimal does not work as required

I have field where i store my grand total to a mysql filed as total and its type set as decimal(10,2)
When my php form adds up and updates the query for 112381348.40 (i.e 112 million)
but when i fetch or view it on phpMyadmin, the value shows as 99999999.99
from my data type set, it has to be 10 digits and 2 decimals where as it is maximum updating as 8 and 2.
Am i understanding wrong or what am i doing wrong.
I know i can increase it to decimal(13,2) and then see it.
But i would like to know the reason, why 10,2 is not happening?
The specification for decimal(m, n) takes two arguments. The first is the "precision" and the second is the "scale". More colloquially, the first is the number of digits in the number. The second is the number of digits to the right of the decimal point.
So, your specification of decimal(10, 2) can store numbers like: 12,345,678.90 -- i.e., up to 99,999,999.99. And that is the maximum number.
If you want to store numbers larger than that, then use a larger precision for the number. For your number, you need at least decimal(11, 2), although I would suggest a larger precision so you don't encounter this problem in the future.
In setting a float or decimal field, the first int value is the total character count. The second is how many decimal places. So:
//decimal(10,2)
12345678.90
//decimal(13,2)
12345678901.23
//decimal(7,3)
1234.567
See?
You have 11 digits. The first number is the total digits. Try:
DECIMAL(11, 2)

Which SQL type should I use to input the value 4.865472349

PHP runs a script that correctly calculates a value. When I echo that value out it comes out as 4.865472349
Then a simple update script is used to enter the value into my database.
$query = "UPDATE members
SET rating = $r
WHERE username = '$username'";
mysql_query($query);
When I do this, the value that is entered into the database is 5.
If I replace $r in the previous formula with 4.865472349 directly, it produces the same result.
Clearly this is because my SQL type was set to "integer"
But Im not sure what to change it to in order to fix this issue. Any help?
If you want the same precision as 4.865472349, you can use DECIMAL(10,9)
Reference
For example, a DECIMAL(18,9) column has nine digits on either side of the decimal point, so the integer part and the fractional part each require 4 bytes. A DECIMAL(20,6) column has fourteen integer digits and six fractional digits. The integer digits require four bytes for nine of the digits and 3 bytes for the remaining five digits. The six fractional digits require 3 bytes.
Assuming you are using MySql
You probably should use DOUBLE. It has the same precision and range as floating point numbers in PHP (in most configurations).
To switch the type using PHPMyAdmin:
Click on the table
Click on structure
Click on Change (the pencil icon) beside rating
Under "Type" select the option "DOUBLE"
Hit Save
You can use float, double or decimal depending on the numbers you'll be storing. I would say float is good enough.
Edit the column type in the database to be able to hold more than just an integer.
ALTER TABLE members
CHANGE rating rating float(10,9);

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