Php - isset() condition doesn't work - php

Question

I am a newbie to PHP. & My PHP Code doesn't work, I want to update some date using MySQL but it seems that first IF condition is 'false' i don't why, I am using PHP 7 & XAMP as a local host, Dreamweaver as an IDE & this is my code:
if(isset($_POST["btn_edit"]))
{
$name = $_POST["name"];
$email = $_POST["email"];
$password = $_POST["password"];
if(!empty($_FILES["img"]["name"]))
{
$img = $_FILES["img"]["name"];
$img_temp = $_FILES["img"]["tmp_name"];
if(move_uploaded_file($img_temp, "assets/images/".$img))
{
$query = mysqli_query($Connection, "UPDATE entry_data SET names='$name',emails='$name',passwords='$password',images='$img' WHERE id='$ID'");
if($query)
{
$result = header("Location:index.php");
}
else
{
echo mysql_error();
}
}
}
else
{
$query = mysqli_query($Connection, "UPDATE entry_data SET names='$name',emails='$name',passwords='$password',images='$img' WHERE id='$ID'");
if($query)
{
echo "<h5>Updated</h5>";
}
}
}
it showing me nothing just refresh the page & this is HTML CODE:
<form method="post" enctype="multipart/form-data">
<input name="name" value="<?php echo $name ?>" />
<input name="email" value="<?php echo $email ?>" />
<input name="password" value="<?php echo $password ?>" />
<img width="50" height="50" src="<?php echo 'assets/images/'.$row[4] ?>" />
<input name="img" type="file" class="text-info" required="required" />
<br/>
<input name"btn_edit" type="submit" />
<?php if(isset($_POST["btn_edit"])) echo $result ?>

Answer 1

You have syntax issue in your button HTML.
This:-
<input name"btn_edit" type="submit" />
Need to be:-
<input name="btn_edit" type="submit" /><!-- = is missing in name -->