Extract arrays with string to a new array - php

Question

I know that there are some posts at SO with a similar issue, but none of those could really help me solving mine. I do have the following $test array:
array(1) {
[0]=>
array(4) {
[0]=>
array(2) {
["id"]=>
string(8) "40265656"
["text"]=>
string(29) "10' - 1st Corner - Terengganu"
}
[1]=>
array(2) {
["id"]=>
string(8) "40265715"
["text"]=>
string(25) "18' - 2nd Corner - Pahang"
}
[2]=>
array(2) {
["id"]=>
string(8) "40265770"
["text"]=>
string(29) "23' - 3rd Corner - Terengganu"
}
[3]=>
array(3) {
["id"]=>
string(8) "40265830"
["text"]=>
string(29) "26' - 4th Corner - Pahang"
}
}
}
and would like to extract only those arrays containing Pahang in the ["text"] key. First I have tried
$key = array_search('Pahang', $test);
and that gives me bool(false). What am I doing wrong here?

Answer 1

I think this way will be right:
$result = [];
foreach ($array[0] as $arr) {
if (strpos($arr['text'], "Pahang") !== false) {
$result[] = $arr;
}
}

Answer 2

The function array_search(...) searches for a value inside an array, but your array is not flat, it's multidimensional, this means you have one or more arrays inside another array.
In your case, you can use array_filter(...) that allows you to filter your array elements in a callable function.
So, initially you have to define a function that filters the elements:
function getPahang($element) {
return $element['text'] === 'Pahang'
}
This function returns true when the element text value is equal to 'Pahang', instead it returns false.
Now, you have to call array_filter, by passing your array and the callable function:
$new_array = array_filter($test[0], 'getPahang');
You can try a similar script here: http://sandbox.onlinephpfunctions.com/code/c076222dd6d1c6f2675d0241742e6c11da6eff53