PHP: var_dump while loop - php

Question

I was trying to create a loop for all the variables on a page to display in one while loop. I couldn't seem to get the variable to output. Here is the code I tried that made the most sense to me:
<?php
$varone = true;
$vartwo = 47;
$varthree = "A little string";
$vars = get_define_vars();
while($loop = $vars){
echo "variable ".$vars;
var_dump($vars;)
}
?>
It would crash one browser and the other it would stay blank. The reason I tried the code this way is because I thought of how I would word a mysql loop and I thought it would work in a similar way. Sorry if this is a newb question.

Answer 1

You should use something like a foreach() loop...
foreach ($vars as $name => $var){
echo "variable ".$name."=";
var_dump($var);
}

Answer 2

Alternatively, I think it might be easier to use an array for this.
$new_array[] = true;
$new_array[] = 47;
$new_array[] = "A little string";
$a=0;
while($new_array[$a]){
echo "variable ".$a." = ";
var_dump($new_array[$a]);
$a++;
}

Answer 3

The reason I tried the code this way is because I thought of how I
would word a mysql loop and I thought it would work in a similar way.
Though I would go with foreach you can use your current code with list and each as many use to fetch from MySQL:
while(list($key, $val) = each($vars)){
echo "variable $key";
var_dump($val); //var_dump($vars;) PARSE ERROR check ;
}
However each is deprecated:
Warning This function has been DEPRECATED as of PHP 7.2.0. Relying on
this function is highly discouraged.