MYSql prepare not accepting my request: No tables used - php

Question

I am using MySQLi in php to prevent SQL Injection with my table.
I have the following SQL command that works perfectly if input into phpMyAdmin.
INSERT INTO UsageData (MyID) SELECT * FROM (SELECT 'USER') AS tmp WHERE NOT EXISTS ( SELECT MyID FROM UsageData WHERE MyID = 'USER') LIMIT 1
Essentially it is intended to insert a new row with MyID as 'USER' if such a row does not already exist.
I have tried to do this with php like so
$query1 = "INSERT INTO UsageData (MyID) SELECT * FROM (SELECT ?) AS tmp WHERE NOT EXISTS ( SELECT MyID FROM UsageData WHERE MyID = ? ) LIMIT 1";
if ($statement1 = $database->prepare($query1)) {
$statement1->bind_param("ss", $inID, $inID);
$statement1->execute();
$statement1->close();
} else {
echo "Incorrect SQL 1\n";
echo "Query: ".$query1."\n";
echo $database->error."\n";
}
However this always results in the echoing of "Incorrect SQL". The error mentioned is "No tables used".
I have a SQL request sent right after it in the PHP that works perfectly but this one for some reason does not.
What am I doing incorrectly?

Answer 1

Okay, I'm going to assume that you've done the work to properly set up the database handler by doing something like $database = new pdo(...);
I'm a little foggy as to what happens when you put assignment statements inside the as an if condition. I would advise you to do the assignment before the if-else block and then test to see if ($statement1 === false) (testing for equivalence, not just equality) for an error. Otherwise, you can enclose $database->prepare(...) in a try-catch block as it emits a PDOException if something goes wrong like this:
try {
$statement1 = $database->prepare($query1);
} catch (PDOException $e) {
die("PDO Exception: " . $e->getCode() . ": " . $e->getMessage());
}