PHP Find files with specific name part in folder - php

Is there a way to get all the files with a specific name from a folder with php?
For example I have in folder next files:
6546-da6sd.png
465-dasd.jpg
654-548484.jpg
654-sasaf.png
654-sakj879.jpg
776-54fsdfs.png
....
I want to get all files that start with "654-" (but not the first (6546-da6sd.png))
Thank You!

you can use glob() and strpos() like:
<?php
$dir = 'files/';
$key = '654-';//search key
foreach (glob("$dir*") as $file) {
$file = str_replace($dir,'',$file);
if (strpos($file, $key) == 0) {
echo($file."<br>");
}
}
?>

Related

how to check for certain file extension in a folder with php [duplicate]

This question already has answers here:
Getting the names of all files in a directory with PHP
(15 answers)
Closed 4 years ago.
I have a folder named uploads with a lot of files in it. I want to find out if there is a .zip file inside it. How can i check if there is a .zip file inside it with php?
Use the glob() function.
$result = glob("my/folder/uploads/*.zip");
It will return an array with the *.zip-files.
Answer is already given by #Bemhard, i am adding more information for future use:
If you want to run script inside your uploads folder than you just need to call glob('*.zip').
<?php
foreach(glob('*.zip') as $file){
echo $file."<br/>";
}
?>
If you have multiple folders and containing multiple zip files inside the folders, than you just need to run script from root.
<?php
$dir = __DIR__; // will get the exact path
$dirs = array_filter(glob('*'), 'is_dir'); // filter is directory or not.
$i = 1;
foreach ($dirs as $key => $value) {
foreach(glob($value.'/*.zip') as $file){
echo $file."<br/>"; // this will print all files inside the folders.
}
$i++;
}
?>
One Extra point, if you want to remove all zip files with this activity, than you just need to unlink file by:
<?php
$dir = __DIR__; // will get the exact path
$dirs = array_filter(glob('*'), 'is_dir'); // filter is directory or not.
$i = 1;
foreach ($dirs as $key => $value) {
foreach(glob($value.'/*.zip') as $file){
echo $file."<br/>"; // this will print all files inside the folders.
unlink($file); // this will remove all files.
}
$i++;
}
?>
References:
Unlink
Glob
This also could help, using scandir and pathinfo
/**
*
* #param string $directoryPath the directory to scan
* #param string $extension the extintion e.g zip
* #return []
*/
function getFilesByExtension($directoryPath, $extension)
{
$filesRet = [];
$files = scandir($directoryPath);
if(!$files) return $filesRet;
foreach ($files as $file) {
if(pathinfo($file)['extension'] === $extension)
$filesRet[]= $file;
}
return $filesRet;
}
it can be used like
var_dump(getFilesByExtension("uploads/","zip"));

PHP List Directories Recursively Issue

I'm trying to list all PHP files in a specified directory and for it to recursively check all sub-directories until it finds no more, there could be numerous levels.
The function I have below works fine with the exception that it only recurses down one level.
I've spent hours trying to see where I'm going wrong, I'm calling the scanFiles() when it finds a new directory but this only seems to work one level down and stop, any help greatly appreciated.
Updated:
function scanFiles($pParentDirectory)
{
$vFileArray = scandir($pParentDirectory);
$vDirectories = array();
foreach ($vFileArray as $vKey => $vValue)
{
if (!in_array($vValue, array('.', '..')) && (strpos($vValue, '.php') || is_dir($vValue)))
{
if (!is_dir($vValue))
$vDirectories[] = $vValue;
else
{
$vDirectory = $vValue;
$vSubFiles = scanFiles($vDirectory);
foreach ($vSubFiles as $vKey => $vValue)
$vDirectories[] = $vDirectory.DIRECTORY_SEPARATOR.$vValue;
}
}
}
return $vDirectories;
}
You can do this easily like this:
// helper function
function getFiles(&$files, $dir) {
$items = glob($dir . "/*");
foreach ($items as $item) {
if (is_dir($item)) {
getFiles($files, $item);
} else {
if (end(explode('.', $item)) == 'php') {
$files[] = basename($item);
}
}
}
}
// usage
$files = array();
getFiles($files, "myDir");
// debug
var_dump($files);
myDir looks like this: has php files in all dirs
Output:
P.S. if you want the function to return the full path to the found .php files, remove the basename() from this line:
$files[] = basename($item);
This will then produce result like this:
hope this helps.
This is because $vDirectory is just a folder name, so scanDir looks in the current folder for it, not the sub folder.
What you want to do is to pass in the path to the folder, not just the name. This should be as simple as changing your recursive call to scanFiles($pParentDirectory . DIRECTORY_SEPARATOR . $vDirectory)
Your main problem is functions like scanDir or isDir need the full file path to work.
If you pass the full file path to them, it should work correctly.

get all file names from a directory in php

(Well what I gone through a lot of posts here on stackoverflow and other sites. I need a simple task, )
I want to provide my user facility to click on upload file from his account, then select a directory and get the list of all the files names inside that directory.
According to the posts here what I got is I have to pre-define the directory name, which I want to avoid.
Is there a simple way to click a directory and get all the files names in an array in PHP? many thanks in advance!
$dir = isset($_POST['uploadFile']) ? _SERVER['DOCUMENT_ROOT'].'/'.$_POST['uploadFile'] : null;
if ($_POST['uploadFile'] == true)
{
foreach (glob($dir."/*.mp3") as $filename) {
echo $filename;
}
}
I will go ahead and post a sample of code I am currently using, with a few changes, although I would normally tell you to look it up on google and try it first.
if ($handle = opendir($dir)) {
while (false !== ($file = readdir($handle))) {
echo $file;
}
closedir($handle);
}
This will display the entire contents of a directory... including: ".", "..", any sub-directories, and any hidden files. I am sure you can figure out a way to hide those if it is not desirable.
<?php
$files=glob("somefolder/*.*");
print_r($files);
?>
Take a look at the Directory class (here) and readdir()
I'm confused what do you want, all files or only some files?
But if you want array of folders and files, do this
$folders = array();
$files = array();
$dir = opendir("path");
for($i=0;false !== ($file = readdir($dir));$i++){
if($file != "." and $file != ".."){
if(is_file($file)
$files[] = $file;
else
$folders[] = $file;
}
}
And if only some folders you want, later you can delete them from array
I always use this amazing code to get file lists:
$THE_PATTERN=$_SERVER["DOCUMENT_ROOT"]."/foldername/*.jpg";
$TheFilesList = #glob($THE_PATTERN);
$TheFilesTotal = #count($TheFilesList);
$TheFilesTotal = $TheFilesTotal - 1;
$TheFileTemp = "";
for ($TheFilex=0; $TheFilex<=$TheFilesTotal; $TheFilex++)
{
$TheFileTemp = $TheFilesList[$TheFilex];
echo $TheFileTemp . "<br>"; // here you can get full address of files (one by one)
}

Get folders and files recursively from a folder in alphabetical order in PHP?

I need to get all the folders and files from a folder recursively in alphabetical order (folders first, files after)
Is there an implemented PHP function which caters for this?
I have this function:
function dir_tree($dir) {
$path = '';
$stack[] = $dir;
while ($stack) {
$thisdir = array_pop($stack);
if ($dircont = scandir($thisdir)) {
$i=0;
while (isset($dircont[$i])) {
if ($dircont[$i] !== '.' && $dircont[$i] !== '..' && $dircont[$i] !== '.svn') {
$current_file = "{$thisdir}/{$dircont[$i]}";
if (is_file($current_file)) {
$path[] = "{$thisdir}/{$dircont[$i]}";
} elseif (is_dir($current_file)) {
$path[] = "{$thisdir}/{$dircont[$i]}";
$stack[] = $current_file;
}
}
$i++;
}
}
}
return $path;
}
I have sorted the array and printed it like so:
$filesArray = dir_tree("myDir");
natsort($filesArray);
foreach ($filesArray as $file) {
echo "$file<br/>";
}
What I need is to know when a new sub directory is found, so I can add some spaces to print it in a directory like structure instead of just a list.
Any help?
Many thanks
Look at the RecursiveDirectoryIterator.
$directory_iterator = new RecursiveIteratorIterator(new RecursiveDirectoryIterator($dir));
foreach($directory_iterator as $filename => $path_object)
{
echo $filename;
}
I'm not sure though if it returns the files in alphabetical order.
Edit:
As you say it does not, I think the only way is to sort them yourself.
I would loop through each directory and put directories and files in a seperate arrays, and then sort them, and then recurse in the directories.
I found a link which helped me a lot in what I was trying to achieve:
http://snippets.dzone.com/posts/show/1917
This might help someone else, it creates a list with folders first, files after. When you click on a subfolder, it submits and another page with the folders and files in the partent folder is generated.

Is there an easy way to read filenames in a directory and add to an array?

I have a directory: Audio/ and in that will be mp3 files only. I'm wanting to automate the process of creating links to those files. Is there a way to read a directory and add filenames within that directory to an array?
It'd be doubly cool if we could do an associative array, and have the key be the file name minus the .mp3 tag.
Any ideas?
To elaborate: I actual have several Audio/ folders and each folder contains mp3s of a different event. The event details are being pulled from a database and populating a table. That's why I'm duplicating code, because right now in each Audio/ folder, I'm having to define the filenames for the download links and define the filenames for the mp3 player.
Thank you! This will greatly simplify my code as right now I'm repeating tons of code over and over!
The SPL way is with DirectoryIterator:
$files = array();
foreach (new DirectoryIterator('/path/to/files/') as $fileInfo) {
if($fileInfo->isDot() || !$fileInfo->isFile()) continue;
$files[] = $fileInfo->getFilename();
}
And for completeness : you could use glob as well :
$files = array_filter(glob('/path/to/files/*'), 'is_file');
This will return all files (but not the folders), you can adapt it as needed.
To get just the filenames (instead of files with complete path), just add :
$files = array_map('basename', $files);
Yes: use scandir(). If you just want the name of the file without the extension, use basename() on each element in the array you received from scandir().
This should be able to do what you're looking for:
// Read files
$files = scandir($dirName);
// Filter out non-files ('.' or '..')
$files = array_filter($files, 'is_file');
// Create associative array ('filename' => 'filename.mp3')
$files = array_combine(array_map('basename', $files), $files);
Sure...I think this should work...
$files[] = array();
$dir = opendir("/path/to/Audio") or die("Unable to open folder");
while ($file = readdir($dir)) {
$cleanfile = basename($file);
$files[$cleanfile] = $file;
}
closedir($dir);
I imagine that should work...
$results = array();
$handler = opendir($directory);
while ($file = readdir($handler)) {
if ($file != "." && $file != "..") {
$results[] = $file;
}
}
closedir($handler);
this should work, if you want any files to be excluded from the array, just add them to the if statement, same for file extensions

Categories