HTML Table Change Row to Column For loop - php

Question

I need to attach two tables.
First loop is perfect,
but second For-loop table goes to the Bottom.
I need to attach that bottom table to that previous one.
Can anyone please solve this problem?
Any Solution would be appreciated, so suggest something to solve this.
<?php
include 'pappu.php';
header("Cache-Control: no-store, no-cache, must-revalidate, max-age=0");
header("Cache-Control: post-check=0, pre-check=0", false);
header("Pragma: no-cache");
$grab=ngegrab('https://www.cryptopia.co.nz/api/GetMarkets/USDT');
$json = json_decode($grab, true);
$usd= $json['Data'][3]['AskPrice'];
$grabb=ngegrab('https://www.cryptopia.co.nz/api/GetMarkets/USDT');
$jsonss = json_decode($grabb, true);
$dogeusd= $jsonss['Data'][8]['AskPrice'];
$grabsz=ngegrab('https://www.cryptopia.co.nz/api/GetMarkets/DOGE');
$jsonsz = json_decode($grabsz);
$grabs=ngegrab('https://www.cryptopia.co.nz/api/GetMarkets/BTC');
$jsons = json_decode($grabs);
echo "<table border=1>";
echo "<th>BTC EXCHANGE</th>";
if($jsons)
foreach ($jsons->Data as $sam){
$market= $sam->Label . "\n";
$link= $sam->AskPrice . "\n";
echo "<tr><td>$market</td>";
$link = number_format($link, 8);
echo "<td>$link" ;
echo '($';
echo number_format($link * $usd, 6) ;
echo ')';
echo "</td></tr>";
}
echo "<th>DOGE EXCHANGE</th>";
foreach ($jsonsz->Data as $sam){
$market= $sam->Label . "\n";
$link= $sam->AskPrice . "\n";
echo "<tr><td>$market</td>";
$link = number_format($link, 8);
echo "<td>$link" ;
echo '($' ;
echo number_format($link * $dogeusd, 6) ;
echo ')';
echo "</td></tr>";
}
echo "</table>";
?>

Answer 1

First set the table headers (<th>), then set the table body if you want all the headers to appear inline.
You can then make arrays for the rows of the two tables and just output for each row.
Note: In case your $btc and $doge arrays have a different amount of rows or are not in the same order you then might have to create a third array by combining the two, then loop over that.
echo '<table border="1">
<tr>
<th colspan="2">BTC EXCHANGE</th>
<th colspan="2">DOGE EXCHANGE</th>
</tr>';
// prepare the rows
$btc = array();
$doge = array();
if($jsons)
{
foreach ($jsons->Data as $sam)
{
$number = (float) $sam->AskPrice;
array_push($btc, array($sam->Label, number_format($number,8) ));
}
foreach ($jsonsz->Data as $sam)
{
$number = (float) $sam->AskPrice;
array_push($doge, array($sam->Label, number_format($number,8) ));
}
// assuming count($btc) and count($doge) are the same
for($i=0; $i< count($btc); $i++)
{
echo '<tr>
<td>'.$btc[i][0].'</td>
<td>'.$btc[i][1].' ($'.number_format($btc[i][1] * $usd, 6).')</td>
<td>'.$doge[i][0].'</td>
<td>'.$doge[i][1].' ($'.number_format($doge[i][1] * $usd, 6).')</td>
</tr>';
}
}
echo '</table>';
?>

Answer 2

You have two <th> cells which should be in a table row <tr>:
echo "<th>BTC EXCHANGE</th>";
and
echo "<th>DOGE EXCHANGE</th>";
Change your code to:
echo "<tr><th>BTC EXCHANGE</th></tr>";
and
echo "<tr><th>DOGE EXCHANGE</th>";