I have a problem when trying to update table after checking row. Not sure if the "if" statement is wrong, however I'm not quite sure, why the UPDATE sql is returning this error. I wouldn't be suprised if INSERT did that.
Here's part of code:
$sql = "SELECT user_id FROM players WHERE user_id = '$id'";
$result = $connect->query($sql);
if($result->num_rows > 0)
{
$sql = "UPDATE players SET user_id = '$Player->user_id', display_name = '$Player->display_name', attackPower = '$Player->attackPower]', defensePower = '$Player->defensePower'";
if($connect->query($sql) === TRUE)
{
echo 'Table has been successfully updated.';
}else{
echo 'There has been a problem with updating the "players" table. <br>Error: '.$connect->error;
}
}else{
$sql = "INSERT INTO players(user_id, display_name, attackPower, defensePower) VALUES('$Player->user_id', '$Player->display_name', '$Player->attackPower', '$Player->defensePower')";
if($connect->query($sql) === TRUE)
{
echo'Table has been successfully migrated.';
}else{
echo'Table migration has failed.';
}
}
$connect->close();
INSERTing is working just fine. I would appreciate any advice. Thanks.
Your update query should look like:
$sql = "UPDATE `players` SET `display_name` = '{$Player->display_name}',
`attackPower` = '{$Player->attackPower}', `defensePower` = '{$Player->defensePower'}
WHERE `user_id` = '{$Player->user_id}'";
It cause an error because Identity columns are not updateable.
You can update every columns except them:
$sql = "UPDATE players SET display_name = '$Player->display_name', attackPower = '$Player->attackPower]', defensePower = '$Player->defensePower'";
As #aynber and #Julqas said, problem was my sql was missing WHERE condition. Thanks for help.
Related
i am trying to insert into multi table after select query return 0 (not found raws) select query working and insert query never done when submite "displayid" and there is no any syntax error
code:
<?php
if ($_POST["displayid"] == TRUE) {
$sqlid = "SELECT * FROM doc1 WHERE idnum ='$pidnum' AND stats='$ok'";
$result = mysqli_query($conn, $sqlid);
if (mysqli_num_rows($result) > 0) {
$sqlup = "UPDATE doc1 SET m_phone='$pm_phone', seen='$dataseen' WHERE idnum ='$pidnum'";
mysqli_query($conn, $sqlup);
$found = 1;
} else {
$found = 0;
$sqlfail = "INSERT INTO fail(fname,lname,tname,funame,idnum,m_phone,reg_date)
VALUES ('$pfname','$plname','$ptname','$pfuname','$pidnum','$pm_phone','$todaydate')";
$conn->query($sqlfail)
}
}
?>
Use this code:
$sqlfail = "INSERT INTO fail(fname,lname,tname,funame,idnum,m_phone,reg_date)
VALUES ('".$pfname."','".$plname."','".$ptname."','".$pfuname."','".$pidnum."','".$pm_phone."','".$todaydate."')";
make similar changes for update command as well
you actually have one error
$conn->query($sqlfail)
should be
$conn->query($sqlfail);
AND stats='$ok'";
i can't see a variable with this name i think you mean AND stats='ok'";
I'd like to check if a value is already in the table.
The structure of my table is this:
ApplicantId = INT
EventId = INT
StudentId = INT
No need to use unique because these table has dependencies.
Below is what I have tried so far:
include('../connectdb.php');
$ScholarPointId = $_GET["ScholarPointId"];
$Point = $_GET["Point"];
$ScholarId = $_GET["ScholarId"];
$EventId = $_GET["EventId"];
$verifysql = mysql_query("SELECT EventId FROM scholar_attended_events WHERE ScholarId ='$ScholarId' ");
#$resultVerify = mysql_fetch_assoc($verifysql);
$num_rows = mysql_num_rows($verifysql);
if( $num_rows > 0 )
{
$script = "<script>
alert('The user has already attended this event!');
</script>";
header('updatescholarpoints.php');
exit();
}
else{
$result = mysql_query("UPDATE scholar_points
SET scholar_points.Points =
scholar_points.Points + $Point
WHERE scholar_points.ScholarPointId = '$ScholarPointId' ") or die(mysql_error());
mysql_query("INSERT INTO scholar_attended_events (EventId , ScholarId) VALUES( '$EventId' , '$ScholarId' ) ")
or die(mysql_error());
}
?>
What I want is to check if the EventId is already in taken by the Student = StudentId. If so, then system will prompt an alert box. Otherwise, Update and Insert into respective table. How can I do this? It seems I miss something in here. If you could help, I really appreciate it.
just missing an = ?
$verifysql = mysql_query("SELECT EventId FROM scholar_attended_events WHERE ScholarId =$ScholarId ");
(and use PDO or mysqli, your code is really in a deprecated mode)
Thanks for checking out my question. I am trying to only update a value in my database if that field is null (so existing users won't be overwritten if someone tries to signup for a spot that is all ready taken and an error message will be output). I have listed below 2 of the most recent scripts I have tried. The first script works for updating the database if the select statement is not there but will overwrite users if entered for the same day and time. Thanks everybody!
$sql = ("SELECT `player1` FROM `users` where id = '$id' and Times = '$time'");
$result = $conn->query($sql);
if ($result->fetch_assoc === NULL) {
$update_player = ("UPDATE users SET player1 = '$name' where id = '$id' AND Times = '$time'")
if($update_player){
echo "Date for $name inserted successfully!";
}
}
else {
echo 'That spot is all ready taken!';
}
//2nd script
$query=mysql_query("UPDATE users SET
player1 = isNULL (player1, $name)
where id = '$id' AND Times = '$time'" );
if($query){
echo "Data for $name inserted successfully!";
}
else {
echo 'That spot is all ready taken!';
}
The following code should do the trick:
$query=mysql_query("UPDATE users SET
player1='$name'
where id = '$id' AND Times = '$time' AND player1 IS NULL" );
if(mysql_affected_rows() == 1){
echo "Data for $name inserted successfully!";
}
else {
echo 'That spot is all ready taken!';
}
Note that you should use pdo or mysqli functions instead.
Try This.
while($row = $result->fetch_assoc) {
if($row['player1'] == NULL){
$update_player = ("UPDATE users SET player1 = '$name' where id = '$id' AND Times = '$time'")
}
I have a feeling that my syntax is incorrect but I can't narrow down what's going on. I have no issues running the statement in a phpMyAdmin SQL query, so hopefully I can get pointed in the right direction. My code is as follows:
else if ($resultdetails === 1) {
$query3 = "update customer_det set `10k`='$_10k',
`14k`='$_14k', `18k`='$_18k', `21k`='$_21k', `22k`='$_22k',
`24k`='$_24k', `925k`='$_925k', `coins`='$coins', `bars`='$bars'
where `id` = '".$uid."'";
$result3 = mysql_query($query3);
}
$resultdetails is a variable set with a EXISTS function. In the SQL query, it returns 1 for me, because the row I'm looking for does exist. So there should be no issues with that.
I tried the double ==, as well as the triple, and there doesn't seem to be any difference in results. I believe the triple === means that it's identical, i.e. the datatype is the same and the value is the same.
I think the issue here is the WHERE statement. Any ideas or suggestions would be greatly appreciated. I forgot to mention that customer_det is the table to be updated and id is the primary key, autoincremented. I pull the $uid variable from the database as well.
Your sql query is right !
But your else if is the problem !
see you add ===,
change it with == and i'm also doubt with your variable declare,
your code will look
like this:
else if ($resultdetails == 1) {
$query3 = "update customer_det set `10k`='".$_10k."',
`14k`='".$_14k."', `18k`='".$_18k."',
`21k`='".$_21k."', `22k`='".$_22k."', `24k`='".$_24k."', `925k`='".$_925k."', `coins`='".$coins."', `bars`='".$bars."' where `id` = '".$uid."'";
$result3 = mysql_query($query3);
}
EDIT:
if (CONDITION :: IF FOUND ON DATABASE) {
$query3 = "update customer_det set `10k`='".$_10k."',
`14k`='".$_14k."', `18k`='".$_18k."',
`21k`='".$_21k."', `22k`='".$_22k."', `24k`='".$_24k."', `925k`='".$_925k."', `coins`='".$coins."', `bars`='".$bars."' where `id` = '".$uid."'";
$result3 = mysql_query($query3);
} else {
// Insert query if not found
}
Check for the data type for $uid and $_blahblah
Try this query --
else if ($resultdetails == 1) {
$query3 = "update customer_det set `10k`='$_10k',
`14k`='$_14k', `18k`='$_18k', `21k`='$_21k', `22k`='$_22k',
`24k`='$_24k', `925k`='$_925k', `coins`='$coins', `bars`='$bars'
where `id` = $uid";
$result3 = mysql_query($query3);
}
Here am trying to update a field in a table with two values if the value which i got from other file using the GET function is Deactivate update the value of cnf_status as 1 and if it is Activate update the value of cnf_status as 0. But this bit of code is not working...can anyone help me how to solve this issue?
<?php
require_once '../config.php';
$id = $_GET['id'];
$status = $_GET['status'];
if($status == Deactivate)
{
mysql_query("update user_details set cnf_status='1' where user_id = '$id'");
}
else if($status == Activate)
{
mysql_query("update user_details set cnf_status='0' where user_id = '$id'");
}
?>
Forgot quotes maybe?
if($status == "Deactivate")
{
mysql_query("update user_details set cnf_status='1' where user_id = '$id'");
}
else if($status == "Activate")
{
mysql_query("update user_details set cnf_status='0' where user_id = '$id'");
}
You should also consider using mysql_real_escape_string() to avoid SQL Injections.
$id = mysql_real_escape_string($_GET['id']);
Usually you dont use Single quotes for Int fields... try removeing them.
You only need them when using with fields like: text, varchar, enum
Also you should quote the Deactivate & Activate otherwise they will be used as constants