Array manipulation: Convert one array to another - php

Question

For a few hours, I lost myself in an array.
I have something like this:
$results = [
"User_1" = [
"Step_1" = "accepted",
"Step_2" = "accepted",
"Step_3" = "waiting",
"Step_4" = "refused"
],
"User_2" = [
"Step_1" = "waiting",
"Step_2" = "accepted",
"Step_3" = "accepted",
"Step_4" = "refused"
],
];
I need to count (and have the sum) of all the "status" for a specific "Step".
In this case, I wish to have :
$steps = [
"Step_1" = [
'acceptedSum' => 1,
'refusedSum' => 0,
'waitingSum' => 1
],
"Step_2" =[
'acceptedSum' => 2,
'refusedSum' => 0,
'waitingSum' => 0
],
"Step_3" =[
'acceptedSum' => 1,
'refusedSum' => 0,
'waitingSum' => 1
],
"Step_4" =[
'acceptedSum' => 0,
'refusedSum' => 0,
'waitingSum' => 2
],
];
[ Nota: Number of User is not defined (1 to N) and number of Step too (1 to 4) ]
Any help will be appreciated :)
Thanks to you.

Answer 1

Try this, see if it works or not.
$steps = array();
$count = 0;
$keys = array_keys(current($results));
foreach($keys as $key){
$accepted = 0;
$refused = 0;
$waiting = 0;
foreach ($results as $result) {
foreach ($result as $k => $v) {
if ($key==$k&&$v == 'accepted') {
$accepted++;
}
if ($key==$k&&$v == 'refused') {
$refused++;
}
if ($key==$k&&$v == 'accepted') {
$waiting++;
}
}
}
$new_array = [
'acceptedSum' => $accepted,
'refusedSum' => $refused,
'withoutAnswerSum' => $waiting
];
$steps[$key] = $new_array;
}
print_r($steps);

Answer 2

You could create the existing keys dynamically. The missing keys you could add with a value of 0;
$results = [
"User_1" => [
"Step_1" => "accepted",
"Step_2" => "accepted",
"Step_3" => "waiting"
],
"User_2" => [
"Step_1" => "waiting",
"Step_2" => "accepted",
"Step_3" => "accepted"
],
"User_3" => [
"Step_1" => "refused",
"Step_2" => "refused",
"Step_3" => "waiting"
]
];
$steps = [];
$status = [];
foreach ($results as $result) {
foreach ($result as $key => $r) {
if (!array_key_exists($key, $steps)) {
$steps[$key] = [];
}
if (!array_key_exists($r."Sum", $steps[$key])) {
$steps[$key][$r."Sum"] = 0;
}
$steps[$key][$r."Sum"]++;
$status[] = $r;
}
}
foreach (array_unique($status) as $au) {
foreach ($steps as &$step) {
if (!array_key_exists($au."Sum", $step)) {
$step[$au."Sum"] = 0;
}
}
}
print_r($steps);
Php output demo

Answer 3

I think the output in your question is wrong, but are you looking for something like this
<?php
$results = [
"User_1" => [
"Step_1" => "accepted",
"Step_2" => "accepted",
"Step_3" => "waiting"
],
"User_2" => [
"Step_1" => "waiting",
"Step_2" => "accepted",
"Step_3" => "accepted"
],
"User_3" => [
"Step_1" => "refused",
"Step_2" => "refused",
"Step_3" => "waiting"
]
];
function sumByStatus($array, $status) {
$filtered_array = array_filter($array,function($value) use ($status) {
return $value === $status;
});
return count($filtered_array);
}
$newResult = array_map(function($item) {
return [
'acceptedSum' => sumByStatus($item, 'accepted'),
'refusedSumF' => sumByStatus($item, 'refused'),
'withoutAnswerSum' => sumByStatus($item, 'waiting')
];
}, $results);
print_r($newResult);
The output is
Array
(
[User_1] => Array
(
[acceptedSum] => 2
[refusedSum] => 0
[withoutAnswerSum] => 1
)
[User_2] => Array
(
[acceptedSum] => 2
[refusedSum] => 0
[withoutAnswerSum] => 1
)
[User_3] => Array
(
[acceptedSum] => 0
[refusedSum] => 2
[withoutAnswerSum] => 1
)
)