Is it necessary to define the array before appending to it? - php

Trivial question.
Suppose I have the following code
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
$words = ['Apple', 'Avocado', 'Banana', 'Blueberry'];
$dict = [];
// build a dictionary keyed on the first letter
foreach ($words as $word) {
$letter = $word[0];
// is this condition necessary?
if (!isset($dict[$letter])) {
$dict[$letter] = [];
}
$dict[$letter][] = $word;
}
?>
Usually when I build a dictionary, before appending an entry, I ensure that the array exist as shown in my example.
I always thought a warning would show up otherwise, however it does not seem to be the case.
So is the IF condition necessary?

From the official documentation on arrays (emphasis mine):
$arr[key] = value;
$arr[] = value;
// key may be an integer or string
// value may be any value of any type
If $arr doesn't exist yet, it will be created, so this is also an
alternative way to create an array. This practice is however
discouraged because if $arr already contains some value (e.g. string
from request variable) then this value will stay in the place and []
may actually stand for string access operator. It is always better to
initialize a variable by a direct assignment.
No warning will be produced, but for clarity's sake it is preferred to initialize by direct assignment as you've always been doing.

Related

php using array_flip to check if value exists vs iterating and if statement

I have a series of arrays and usually if i want to check if a value exists i iterate throu the array, use an if statement inside the foreach block then break or return, but recently I decided to use array_flip to flip the array then check if the key exists with isset:
<?php
$arr = array(1, 0, 'yes', 'no', 'on', 'off' /* more keys */);
/*
foreach($arr as $value) {
if ($value === 'on') { return 'xxx'; }
}
*/
//Alternative
$arrFlipped = array_flip($arr);
if (isset($arrFlipped['on'])) { return xxx; }
?>
The arrays are made from safe data, not user input, so the values would always be valid keys.
I'd like to know if this appoach is ok, what are the advantages and disadvantages?, wich one is faster or waste less resources?
Sorry for my english... thanks!
Edit:
OP asks for multiple values
Don't.
First, it might look like an optimisation in your code, but the performance will not change: in the background, PHP will have to loop through the array anyway.
Second, don't be "smart". The more "tricks" you use in your code, the harder it is to maintain your code. 6 months from now, you'll be scratching your head wondering why the ** you decided to flip the array (you or whoever is tasked to maintain your code).
If you really want to implement something like that, at least encapsulate in a clearly named function so that you can see what you were going for:
function value_exists($arr, $value){
$arrFlipped = array_flip($arr);
if (isset($arrFlipped["$value"])) { return xxx;
}else{ return false; }
}
That way, when you write return value_exists($arr, $value); what you're doing is obvious, even if your implementation is unusual.
Third, you can use in_array or array_search to do what you want.
Fourth, if you are looking for optimizations and you aren't sure if it makes it better, just profile it. The easiest way is to use microtime:
$before = microtime(true);
// code to test
$now = microtime(true);
echo sprintf("Elapsed: %f", $now-$before);
But you shouldn't be trying to optimize for performance unless you notice an actual problem.
What about in_array?
return in_array('on', array(1, 0, 'yes', 'no', 'on', 'off'))
http://php.net/manual/en/function.in-array.php
To check if multiple values exists in array , like you said in comment , use :
array_intersect() returns an array containing all the values of array1 that are present in all the arguments. Note that keys are preserved.
Intersect the $target with the $arr and make sure the intersection is precisely equal to the number of elements in $target:
$arr = array(1, 0, 'yes', 'no', 'on', 'off' /* more keys */);
$target = array('yes', 'off');
if(count(array_intersect($arr, $target)) == count($target)){
echo 'all values found in array' ;
}
This works also for one element , but it should be in array as well

PHP variable variable name containing index

$arr[0]=123;
$a="arr[0]";
echo $$a;
gives me error
Notice: Undefined variable: arr[0]
on the last line.
What should I do to make it work?
EDIT:
Above is the simplification of what I want to do. If someone wants to know why I want to do this, then here's the explanation:
This is something like what I want to do:
if(condition){
$a=$arr1[0][0];
$b=$arr1[0][1];
$c=$arr1[0][2];
}
else{
$a=$arr2[0];
$b=$arr2[1];
$c=$arr2[2];
}
I can compact it like this:
if(condition)
$arr=$arr1[0];
else
$arr=$arr2;
$a=$arr[0];
$a=$arr[1];
$a=$arr[2];
But I wanted to try doing this using variable variable:
if(condition)
$arr="$arr1[0]";
else
$arr="$arr2";
$a={$$arr}[0];
$b={$$arr}[1];
$c={$$arr}[2];
Sure, we don't need variable variables as we can still code without them. I want to know, for learning PHP, why the code won't work.
Now that you said what you’re actually trying to accomplish: Your code doesn’t work because if you look at $arr1[0][0], only arr is the variable name; the [0] are special accessors for certain types like strings or arrays.
With variable variables you can only specify the name but not any accessor or other operation:
A variable variable takes the value of a variable and treats that as the name of a variable.
Your solution with the additional variable holding the array to access later on would be the best solution to your problem.
What you are trying to do just won't work - the code $arr[0] is referencing a variable called $arr, and then applying the array-access operator ([$key]) to get the element with key 0. There is no variable called $arr[0], so you cannot reference it with variable-variables any more than you could the expression $foo + 1 .
The real question is why you want to do this; variable variables are generally a sign of very messy code, and probably some poor choices of data structure. For instance, if you need to select one of a set of variables based on some input, you probably want a hash, and to look up an item using $hash[$item] or similar. If you need something more complex, a switch statement can often cover the cases you actually need.
If for some reason you really need to allow an arbitrary expression like $arr[0] as input and evaluate it at runtime, you could use eval(), but be very very careful of where the input is coming from, as this can be a very easy way of introducing security holes into your code.
FROM PHP DOC
In order to use variable variables with arrays, you have to resolve an ambiguity problem. That is, if you write $$a[1] then the parser needs to know if you meant to use $a[1] as a variable, or if you wanted $$a as the variable and then the [1] index from that variable. The syntax for resolving this ambiguity is: ${$a[1]} for the first case and ${$a}[1] for the second.
Use
echo ${$a}[0]; // 123
Edit : Based on your edit you can simply have
list($a, $b, $c) = (condition) ? $arr1[0] : $arr2;
Or
$array = (condition) ? $arr1[0] : $arr2;
$a = $array[0];
$b = $array[1];
$c = $array[2];
As pointed out you don't need variable variables. To get a PHP variable variable name containing index (a key) use array_keys() or array_search() or other array parsers. From php's site:
$array = array(0 => 'blue', 1 => 'red', 2 => 'green', 3 => 'red');
$key = array_search('green', $array); // $key = 2;
$key = array_search('red', $array); // $key = 1;
You could also use the following (using $var= instead of echo):
$arr[0]=123;
$arr[1]=456;
foreach ($arr as $key => $value) {
echo "arr[{$key}] = {$value} \r\n";
}
Which outputs:
arr[0] = 123
arr[1] = 456
But I don't see why you'd do that, since the whole point of the array is not doing that kind of stuff.

PHP get array() value to become $variable

ok, So I have this array:
$choices = array($_POST['choices']);
and this outputs, when using var_dump():
array(1) { [0]=> string(5) "apple,pear,banana" }
What I need is the value of those to become variables as well as adding in value as the string.
so, I need the output to be:
$apple = "apple";
$pear = "pear";
$banana = "banana";
The value of the array could change so the variables have to be created depending on what is in that array.
I would appreciate all help. Cheers
Mark
How about
$choices = explode(',', $_POST['choices']);
foreach ($choices as $choice){
$$choice = $choice;
}
$str = "apple,pear,pineapple";
$strArr = explode(',' , $str);
foreach ($strArr as $val) {
$$val = $val;
}
var_dump($apple);
This would satisfy your requirement. However, here comes the problem, since you could not predefine how many variables are there and what are they, it's hard for you to use them correctly. Test "isset($VAR)" before using $VAR seems to be the only safe way.
You'd better just split the source string in just one array and just operate the elements of the specific array.
I have to concur with all the other answers that this is a very bad idea, but each of the existing answers uses a somewhat roundabout method to achieve it.
PHP provides a function, extract, to extract variables from an array into the current scope. You can use that in this case like so (using explode and array_combine to turn your input into an associative array first):
$choices = $_POST['choices'] ?: ""; // The ?: "" makes this safe even if there's no input
$choiceArr = explode(',', $choices); // Break the string down to a simple array
$choiceAssoc = array_combine($choiceArr, $choiceArr); // Then convert that to an associative array, with the keys being the same as the values
extract($choiceAssoc, EXTR_SKIP); // Extract the variables to the current scope - using EXTR_SKIP tells the function *not* to overwrite any variables that already exist, as a security measure
echo $banana; // You now have direct access to those variables
For more information on why this is a bad approach to take, see the discussion on the now deprecated register_globals setting. In short though, it makes it much, much easier to write insecure code.
Often called "split" in other langauges, in PHP, you'd want to use explode.
EDIT: ACTUALLY, what you want to do sounds... dangerous. It's possible (and was an old "feature" of PHP) but it's strongly discourage. I'd suggest just exploding them and making their values the keys of an associative array instead:
$choices_assoc = explode(',', $_POST['choices']);
foreach ($choices as $choice) {
$choices_assoc[$choice] = $choice;
}

Efficiency of using foreach loops to clear a PHP array's values

Which is more efficient for clearing all values in an array? The first one would require me to use that function each time in the loop of the second example.
foreach ($array as $i => $value) {
unset($array[$i]);
}
Or this
foreach($blah_blah as $blah) {
$foo = array();
//do something
$foo = null;
}
I don't want to use unset() because that deletes the variable.
Like Zack said in the comments below you are able to simply re-instantiate it using
$foo = array(); // $foo is still here
If you want something more powerful use unset since it also will clear $foo from the symbol table, if you need the array later on just instantiate it again.
unset($foo); // $foo is gone
$foo = array(); // $foo is here again
If we are talking about very large tables I'd probably recommend
$foo = null;
unset($foo);
since that also would clear the memory a bit better. That behavior (GC) is however not very constant and may change over PHP versions. Bear in mind that re-instantiating a structure is not the same as emptying it.
If you just want to reset a variable to an empty array, you can simply reinitialize it:
$foo = array();
Note that this will maintain any references to it:
$foo = array(1,2,3);
$bar = &$foo;
// ...
$foo = array(); // clear array
var_dump($bar); // array(0) { } -- bar was cleared too!
If you want to break any references to it, unset it first:
$foo = array(1,2,3);
$bar = &$foo;
// ...
unset($foo); // break references
$foo = array(); // re-initialize to empty array
var_dump($bar); // array(3) { 1, 2, 3 } -- $bar is unchanged
Unsetting the variable is a nice way, unless you need the reference of the original array!
To make clear what I mean:
If you have a function wich uses the reference of the array, for example a sorting function like
function special_sort_my_array(&$array)
{
$temporary_list = create_assoziative_special_list_out_of_array($array);
sort_my_list($temporary_list);
unset($array);
foreach($temporary_list as $k => $v)
{
$array[$k] = $v;
}
}
it is not working! Be careful here, unset deletes the reference, so the variable $array is created again and filled correctly, but the values are not accessable from outside the function.
So if you have references, you need to use $array = array() instead of unset, even if it is less clean and understandable.
I'd say the first, if the array is associative. If not, use a for loop:
for ($i = 0; $i < count($array); $i++) { unset($array[$i]); }
Although if possible, using
$array = array();
To reset the array to an empty array is preferable.
Isn't unset() good enough?
unset($array);
How about $array_name = array(); ?
Use array_splice to empty an array and retain the reference:
array_splice($myArray, 0);
i have used unset() to clear the array but i have come to realize that unset() will render the array null hence the need to re-declare the array like for example
<?php
$arr = array();
array_push($arr , "foo");
unset($arr); // this will set the array to null hence you need the line below or redeclaring it.
$arr = array();
// do what ever you want here
?>
Maybe simple, economic way (less signs to use)...
$array = [];
We can read in php manual :
As of PHP 5.4 you can also use the short array syntax, which replaces array() with [].
I see this questions is realla old, but for that problem I wrote a recursive function to unset all values in an array. Recursive because its possible that values from the given array are also an array. So that works for me:
function empty_array(& $complete_array) {
foreach($complete_array as $ckey => $cvalue)
{
if (!is_array($cvalue)) {
$complete_array[$ckey] = "";
} else {
empty_array( $complete_array[$ckey]);
}
}
return $complete_array;
}
So with that i get the array with all keys and sub-arrays, but empty values.
The unset function is useful when the garbage collector is doing its rounds while not having a lunch break;
however unset function simply destroys the variable reference to the data, the data still exists in memory and PHP sees the memory as in use despite no longer having a pointer to it.
Solution:
Assign null to your variables to clear the data, at least until the garbage collector gets a hold of it.
$var = null;
and then unset it in similar way!
unset($var);
The question is not really answered by the posts. Keeping the keys and clearing the values is the focus of the question.
foreach($resultMasterCleaned['header'] as $ekey => $eval) {
$resultMasterCleaned[$key][$eval] = "";
}
As in the case of a two dimensional array holding CSV values and to blank out a particular row. Looping through seems the only way.
[] is nearly 30% faster then as array()
similar as pushing new element to array
$array[] = $newElement then array_push($array, $newElement)
(keep in mind array_push is slower only for single or 2 new elements)
Reason is we skip overhead function to call those
PHP array vs [ ] in method and variable declaration

Changes to a PHP Array Not "Sticking"

OK so I'm making something to do some data mining but I do changes to an array (by overwritting previous array values) in a loop and they show that they've been changed but once I get outside of a greater loop the values change back to their original values.
Probably easier to give an example:
It starts off like this, turning a bunch of the parts of the array into the word "MATCH".
Now if I was to immediately dump the values of the array it would show that some values have changed to "MATCH" (ie, right after changing the value I would echo the array slot and it would show it's value to be "MATCH") However after I get outside the loop the array changes back to it's original contents
Here is a compressed version of the code:
//i've got this big loop for doing the main work
do {
//Set dat ticker
$q = 0;
// Run through entire previous scrape array to check for matches and mark them as unchanged
do {
if ($itemTitle[$i] == $prodURLS[$q]) {
$prodURLS[$q] = "MATCH";
echo "When the value is printing immediately it shows that it's changed: ".$prodURLS[$q]."<br>";
}
$q++;
} while ($q < $urlArraySize);
$i++;
} while ($i < $itemtitleArraySize);
//If I were to try to print the variable down here it would be reverted to like it was before I changed it to "MATCH"
print_r($prodURLS);
From running your code, setting the variables as follow, it works for me:
$prodURLS = array('a','b','c');
$itemTitle = array('a');
$urlArraySize = count($prodURLS);
$itemtitleArraySize = count($itemTitle);
$i = 0;
My only recommendations with only this amount of information, are:
To provide more context information, as madth3 suggests.
To check the scope in which you are setting/checking values. You may need the & operator to pass variables by reference, or the global keyword to use global variables.
To use the foreach loop, it will make your code smaller and easier to read. Also you won't need to count the size of the arrays and will have other advantages, e.g. in the use of associative arrays. Again, be careful about the use of variables by reference. For example:
foreach ($itemTitle as $item) {
foreach ($prodURLS as &$prod) {
if ($item == $prod) {
$prod = 'MATCH';
}
}
}
unset($prod); //Unset variable set by reference if you are going to use it later on!
Also, you may find useful some of the php array functions like array_walk. Check out the PHP Manual on the array functions reference.
Really, there isn't a lot that can be said from just the code you provided.
Good luck.

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